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Find the equation of the hyperbola referred to its principal axes: Whose length of transverse axis is 8 and distance between foci is 10. |
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Answer» Let the required equation of hyperbola be \(\frac{x^2}{a^2} - \frac {y^2}{b^2} = 1\) Length of transverse axis = 2a Given, length of transverse axis = 8 ⇒ 2a = 8 ⇒ a = 4 ⇒ a2 = 16 Distance between foci = 2ae Given, distance between foci = 10 ⇒ 2ae = 10 ⇒ ae = 5 ⇒ a2 e2 = 25 Now, b2 = a2 (e2 – 1) ⇒ b2 = a2 e2 – a2 ⇒ b2 = 25 – 16 = 9 The required equation of hyperbola is \(\frac {x^2}{16} - \frac {y^2}{9}=1\) |
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