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Find the equation of the hyperbola referred to its principal axes: Whose foci are at (±2, 0) and eccentricity is 3/2 |
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Answer» Let the required equation of hyperbola be \(\frac{x^2}{a^2} - \frac {y^2}{b^2} = 1\)……(i) Given, eccentricity (e) = 3/2 Co-ordinates of foci are (±ae, 0). Given co-ordinates of foci are (±2, 0) ae = 2 ⇒ a(3/2) =2 ⇒ a = 4/3 ⇒ a2 = 16/9 |
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