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C. convex LENS of FOCAL LENGTH 10 m ...because if the POWER is positive that is + 0.1 it will ALWAYS convex lens only

So, here's UR ANS ............

Let after x second the separation between particles is h.
for first PARTICLE,


..........(1)

2ND particle,
.......(2)

given,

1/2gx² - 1/2g(x - t)² = l

1/2g[x² - (x - t)²] = l

[x² - x² + 2xt - t²] = 2l/g

2xt - t² = 2l/g

2xt = t² + 2l/g

x = t/2 + l/gt

Answer:

Explanation:

Solution :-

From 2nd equation of motion,

s = ut + 1/2at²

We know that,

G = 10 m/s

In 2 seconds,

Distance covered by first body, s₁ = 1/2 × g × 4

= 2g

= 2 × 10

= 20 m

Distance covered by second body, s₂ = 1/2 × g × 4

= 2g

= 2 × 10

= 20 m

After 2 seconds,

Height of 1st body, h₁ = 150 - 20 = 130 m

Height of 2nd body, h₂ = 100 - 20 = 80 m

Difference between height after 2 seconds, = 130 - 80 = 50 m.

Hence, The difference in heights of the OBJECTS will remain same with equal time as both the objects have been DROPPED from rest and are falling with same acceleration.

W=mgh
= 0.5 X 9.8 x H

K.E = 1/2 m v2

We'll REPLACE K.E i.e kinectic enerygy by 1 J and MASS (m) by 1 (given in the QUESTION)

1 = 1/2 * 1 * v2

2 = v2 (take 2 to the other SIDE)

root 2 = v

or 1.4 m/s = v

Work done = mgh
m= 100kg
h= 10m
g= 10m/s²
mgh= 10000 joules
work done = 10K joules

the other hand, is PITCH. ... So if the frequency increases then the pitch of the sound wave also increases. AMPLITUDE affects the LOUDNESS of the sound wave. So if the sound wave is loud it MEANS it has a HIGHER amplitude.

For a young adult with a NORMAL vision, the NEAR point is about 25 cm and thefar point of the EYE is at INFINITY. ANORMAL eye can see objects clearly that are between 25 cm and infinity.

Here is your answer↓

Frequency of WAVE = 200Hz

Speed of wave = 440m

So, WAVELENGTH is GIVEN by

wave= speed/frequency

= 440/220

= 2m ANS..

Hope it will help u↑ ☆ :)

Here is your ANSWER ↑
Hope it will HELP you :)

Here is your answer ↓

Space wave are the radio WAVES of very high frequency (i.e between 30MHz to 3MH or more)

while Sky wave is a radio wave reflection from the INOSPHERE.

(INOSPHERE is a PART of the earth's upper ATMOSPHERE for about 60km to 1000km altitude)


Hope it will help you ↑ ★ :)

Hii friend,

I have seen this question in a SAMPLE paper.

# Complete question with options-
Q. How do we KNOW that fission isn't responsible for the sun’s energy ?
(A) Fission doesn't produce enough energy per GRAM of fuel
(B) If fission were going on in the sun, the sun would explode
(C) If fission were going on in the sun, the sun's MASS would increase
(D) There isn't very much fissionable material in the sun.

# Answer - (D) There isn't very much fissionable material in the sun.

Thanks for asking...

Potential ENERGY  is energy an object has because of its position relative to some other object. When you stand at the top of a stairwell you have more potential energy than when you are at the bottom, because the earth can pull you down through the force of gravity, doing WORK in the process. When you are holding two MAGNETS apart they have more potential energy than when they are close together. If you let them GO, they will move toward each other, doing work in the process.

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters. Notice that gravitational potential energy has the same units as kinetic energy, kg m2 / s2. In FACT, all energy has the same units, kg m2 / s2, and is measured using the unit Joule (J).

273.15 DEGREES CELSIUS

Hii dear,

# ANSWER- 124 J

# Given-

dT=10°K

R=8.3J/mole°K

Qp=207J

n=1

# Formula-

For one mole of an IDEAL monoatomic gas

Cp-Cv=R

But heat at CONSTANT pressure is given by,

Qp=n×Cp×dT

207=1×Cp×10

Cp=20.7J

Also heat at constant volume is given by,

Qv=n×Cv×dT

Qv=1×(Cp-R)×dT

Qv=(20.7-8.3)10

Qv=12.4×10

Q=124J

Heat at constant volume to raise temperature by 10°K is 124J.

PLEASE SEE the ATTACHMENT below...............

Here is your answer
S.I. unit of speed is metre PER second (m/ s) .
it also expressed in other units such as meter per MINUTE (m/ MIN) or kilometer per hour( km/ h)
HOPE it helps

Hii friend,

# ANSWER- Y = 2 × 10^12 N/m2

# GIVEN-

m=4kg

l=20m

dl=0.031mm=3.1×10-5m

r=2mm=2×10^-3m

# Formula-

Youngs MODULUS is given by

Y = stress/strain

Y = (F/A)/(dl/l)

Y = (mg/πr^2)/(dl/l)

Y = (4×3.1π/π×4×10^-6)/(3.1×10-5/20)

Y = 2 × 10^12 N/m2

Youngs modulus = 2 × 10^12 N/m2.

Hope that was helpful...

Because the TEMPERATURE of tea CUP is so HIGH than our mouth temperature so our body FEEL so warm

I THINK 1 :60☺️☺️☺️☺️☺️

<P>Answer:

7%

P=A^2√B / C

ΔP/ P = 2(ΔA/A) + 1/2(ΔB/B) + ΔC / C

SUBSTITUTING,

ΔA / A x 100 = 1

--> ΔA / A = 0.01

ΔB / B x 100 = 2

--> ΔB / B = 0.02

ΔC / C x 100 = 4

--> ΔC / C = 0.04

ΔP / P = 2(0.01) + 0.01 + 0.04

= 0.07

ΔP/P x 100 = 0.07 x 100

= 7%

A has UNIFORM MOTION while B doesn't

So now we start with the main thing that is the aircraft CHARACTERISTICS and within this aircraft characteristics we will be looking at the VARIOUS TYPES of characteristics like engine type and propulsion, the size of aircraft, the aircraft weight and the wheel configuration, the MINIMUM turning radius, the MINIMU

It is due to atmospheric refraction
Light ray from the STAR TRAVELS through the space unhindered. The continously changing atmosphere refracts the light from the stars
When the atmosphere refracts more starlight toward US, the intensity of starlight is INCREASED and the stars appear to be brigher
When the atmosphere refracts small light, the intensity of starlight is decreased and the stars appear to be dim
In this way, the amount of starlight reaching our eyes increases and decreases continously
This causes star to twinkle

hope it will HLP u.... (♡˙︶˙♡)

As we KNOW that ;
Resistance = Resistivity*length/area
Here we NOTE that the resistance is DIRECTLY proportional to length and inversely proportional to area of cross section .... 
Now a/c to question,;
Length of wire is double then area is reduced to HALF...
Now 
NEW resistance = resistivity*2length/area/2
New resistance =(resistivity*length/area)*4
New resistance = 4resistance

A tv transmission TOWER antenna is at a height

H(t) = 20 m

receiving antenna is at a height

H(r) = 25 m

And

R = 6.4 × 10^6

Where R is a radius of earth curvature

Distance between transmitter and receiver ( line of sight)

D = √2RH(t) + √2RH(r)

D = √{2×6.4×(10)^6 × 20} + √{2×6.4×(10)^6 ×25 }

D = √{128 × (10)^5 × 20} + √{128 × (10)^5 × 25 }

D = 16000 + 17888.543

D = 33888.543 meter

D = 33888.543 × 1/(10)^3

D = 33.888 KM

Area covered

A = πD^2

A = ( 22/7 ) × ( 33.888 )^2

A = 22/7 × 1148.396

A = 3609.246 square KiloMeters

RANGE area covered

ANSWER- 3609.246 square KiloMeters

<P>P. E=mgh

M=20kg

h=4m

Them P. E at

4m is 20×10×4=800

3m is 20×10×3=600

2m is 20×10×2=400

1m is 20×10×1=200

Hey!

SINCE ng(refractive INDEX of GLASS) = c/v

=) 1.33 = 3*10^8 / v

=) v(SPEED of light in water) = 3*10^8/1.33

= 2.25 * 10^8 m/s

hope it helps you!!

Newland law of octave:
When ELEMENTS are arranged in the order of increasing atomic mass the property of EVERY EIGHT elements are repetition of that starting ELEMENT.

Newland is an English SCIENTIST who in year 1866 arrange elements known at that time in ASCENDING order of their atomic MAAS he started with hydrogen and ended on THORIUM. he found that every eight element had PROPERTY similar to first, he proved it by using indian musical notes and by using western musical notes ie. 'saptak' . the similarity observed in every eighh and first element is called as newland law of octave.

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Hey dear,

◆ Answer-
B = 19.6×10^8

◆ Explaination-
# Given-
h = 200 m
∆V/V = 0.1 %

# Solution-
Bulk MODULUS of material is given by-
Bulk modulus = PRESSURE / Strain
B = P / (∆V/V)

Here, we know
P = ρgh
∆V/V = 0.1 %

B = ρgh / (∆V/V)
B = 1000×9.8×200 / (0.1/100)
B = 19.6×10^8

Bulk modulus of the ball material is 19.6×10^8.

Hope this HELPS...

Noun. a native or naturalized member of a STATE or nation who OWES allegiance to its government and is entitled to its protection (distinguished from ALIEN). an inhabitant of a city or TOWN, especially ONE entitled to its privileges or franchises. an inhabitant, or denizen: The deer is a citizen of our woods.

Initial KINETIC energy(I. K. E) = mu²
=1250 × (72×5/18)J. (we have to change it in S. I unit)
=1250 × 15 = 18570J.

Similarly,
Final Kinetic energy(F. K. E) = mv²
= 1250 × (18×5/18)J
= 1250×5= 6250J.


Change in K. E = F. K. E - I. K. E = 18570-6250=12320J.


Hope this will help you.

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Answer: 3

Explanation:

REMEMBER the ENERGY curve for shm. The VALUE of max energy are same.

TE= KE+PE

when particle is at mean POSITION

Ke= k. Pe=0 TE =k

When particle is at extreme position

Ke=0 Pe= k Te=k

Because your BODY is ALSO APPLYING PRESSURE

Electric motor INVOLVE rotating COILS of WIRE which are driven by the magnetic force EXERTED by a magnetic field on an electric current

Then INCIDENT RAY and emergent Ray are EQUAL (angle) and are PARALLEL to each other

F = M × a (a→ ACCELERATION)

a = F/M

v = s/t

t = s/v

t² = s²/v²

s = ut+½at²

s = 0+½(F/M)t²

s = (F/2M)(s²/v²)

1 = (F/2M)(s/v²)

v² = F×s/2M

v = √(F×s/2M)

We KNOW that acceleration is rate of CHANGE of velocity.

We have, v=(180–16x)^1/2

Now,differentiating it w.r.t t i.e time,

So, dv/dt = [1/2(180–16x)^(-1/2)](-16dx/dt)

(I HOPE u have no problem in differentiating, if u have then please recinsider because it's BASICS)

So, on simplifying above equation,

a(acc.)=dv/dt=[1/2(180–16x)^(-1/2)](-16v)

Putting the VALUE of v from original equation,

a=dv/dt=[-8(180–16x)^(-1/2)](180–16x)^1/2)

Clearly,on simplifying we get,

a=dv/dt=-8 m/sec^2 which is the required answer.

Power=Fs/t

F=mg=2.5×10×10=250

Power=Fs=(250×20)/50=100 Watt

We can use g=9.8 then ANSWER is little different.

then, F=2.5×10×9.8=245

Power=(245×20)/50=98 Watt

I HOPE it help u....

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F=1.5 N

Mass of A=2 mm²=0.000002 m²

Mass of B=6 mm²=0.000006 m²

Pressure on A=Force/Area of A=1.5/0.000002=7,50,000 Pa=7.5×10^5 Pa

Pressure on B=Force/Area of B=1.5/0.000006=2,50,000 Pa=2.5×10^5 Pa

I hope it help you....

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