An object is dropped from rest at a height of 150m and simultaneously

1.	An object is dropped from rest at a height of 150m and simultaneously another object is dropped from rest at a height 100m. What is the differences in their heights after 2 sec. If both objects dropped with the same accelerations? How does the difference in heights vary with time?
Answer» Answer: Explanation: Solution :- From 2nd equation of motion, s = ut + 1/2at² We know that, G = 10 m/s In 2 seconds, Distance covered by first body, s₁ = 1/2 × g × 4 = 2g = 2 × 10 = 20 m Distance covered by second body, s₂ = 1/2 × g × 4 = 2g = 2 × 10 = 20 m After 2 seconds, Height of 1st body, h₁ = 150 - 20 = 130 m Height of 2nd body, h₂ = 100 - 20 = 80 m Difference between height after 2 seconds, = 130 - 80 = 50 m. Hence, The difference in heights of the OBJECTS will remain same with equal time as both the objects have been DROPPED from rest and are falling with same acceleration.

An object is dropped from rest at a height of 150m and simultaneously another object is dropped from rest at a height 100m. What is the differences in their heights after 2 sec. If both objects dropped with the same accelerations? How does the difference in heights vary with time?

Answer»

Answer:

Explanation:

Solution :-

From 2nd equation of motion,

s = ut + 1/2at²

We know that,

G = 10 m/s

In 2 seconds,

Distance covered by first body, s₁ = 1/2 × g × 4

= 2g

= 2 × 10

= 20 m

Distance covered by second body, s₂ = 1/2 × g × 4

= 2g

= 2 × 10

= 20 m

After 2 seconds,

Height of 1st body, h₁ = 150 - 20 = 130 m

Height of 2nd body, h₂ = 100 - 20 = 80 m

Difference between height after 2 seconds, = 130 - 80 = 50 m.

Hence, The difference in heights of the OBJECTS will remain same with equal time as both the objects have been DROPPED from rest and are falling with same acceleration.

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