A ball falling in a lake of depth 200m shows a decrease of o.1% in its volume at the bottom. The bulk modulus of the ball is

A ball falling in a lake of depth 200m shows a decrease of o.1% in its

1.	A ball falling in a lake of depth 200m shows a decrease of o.1% in its volume at the bottom. The bulk modulus of the ball is
Answer» Hey dear, ◆ Answer- B = 19.6×10^8 ◆ Explaination- # Given- h = 200 m ∆V/V = 0.1 % # Solution- Bulk MODULUS of material is given by- Bulk modulus = PRESSURE / Strain B = P / (∆V/V) Here, we know P = ρgh ∆V/V = 0.1 % B = ρgh / (∆V/V) B = 1000×9.8×200 / (0.1/100) B = 19.6×10^8 Bulk modulus of the ball material is 19.6×10^8. Hope this HELPS...

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A ball falling in a lake of depth 200m shows a decrease of o.1% in its volume at the bottom. The bulk modulus of the ball is

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