1.

Two particles begin to fall freely from same height but the second falls t seconds after the first.find time ( after dropping of the first) when separation between particles is h

Answer»

Let after x second the separation between particles is h.
for first PARTICLE,
h_1=ux+\frac{1}{2}gx^2

h_1=\frac{1}{2}gx^2..........(1)

2ND particle,
h_2=0.t+\frac{1}{2}g(x-t)^2.......(2)

given, h_1-h_2=<klux>L</klux>

1/2gx² - 1/2g(x - t)² = l

1/2g[x² - (x - t)²] = l

[x² - x² + 2xt - t²] = 2l/g

2xt - t² = 2l/g

2xt = t² + 2l/g

x = t/2 + l/gt


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