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(B)Micrometer Screw gaugeExplanation:In this questionwe have been asked diameter of paper pin is MEASURED accurately by using?Micrometer screw GAUGE sometime known as micrometer is used to MEASURE the diameter of the paper pin.This device is widely used for the accurate measurement of the various components.It is also used in telescope or microscope to measure the diameter of the CELESTIAL BODIES.

6Explanation:% are addeed t=4pi WHOLESQUARE L/G

(B)......EXPLANATION:OPTION no.(B)

tion:Given si UNIT is of resistance. The SI unit of resistance is kg m² A⁻² s⁻³.There is ANOTHER SI unit of resistance that is Ohm .The main SI unit of resistance is ohm and the given SI unit is derived FORM of the Ohm

here is your ANSWER THANK you

DExplanation:When TWO phtsical quantity are ADDED or subtracted there should be as many decimal places retained in FINAL result as are there in the NUMBER with LEAST decimal place

udent,◆ Answer -(C) the energy delivered by radiation to a target◆ Explaination -Rad UNIT is used to REPORT the MEASUREMENT of dose of radiation absorbed.It is GENERALLY used to measure required radiation dose for radiotherapy in various cancers.Conversion FACTOR -1 rad = 0.01 Gy1 rad = 0.01 J/kg1 rad = 100 ergsHope this helps you.

: option (D) momentumexplanation : LET's check options one - by - one. option (A) we know, FORCE = mass × accelerationso, dimension of force = dimension of mass × dimension of acceleration= [M1][L¹T-²] = [M¹L¹T-²] , obviously, it is not the answer.option (B) energy = WORKDONE = force × displacementdimension of energy = dimension of force × dimension of displacement= [M¹L¹T-²] × [L¹] = [M¹L²T-²] , it is not same as above mentioned.option (C), PRESSURE = force/area so, dimension of pressure = [M¹L¹T-²]/[L²]= [M¹L-¹T-²] , no it's not correct.option (D), momentum = mass × velocityso, dimension of momentum = [M¹][L¹T-¹]= [M¹L¹T-¹], hurray ! we got it, dimension of momentum is same as above mentioned.hence, option (D) is correct.

: option (C) work explanation : SI unit of energy is kgm²/s² or JOULE. LET's check all the options ! option (A) power , it cannot be possible because power is energy consumed per unit time. so, its SI unit is Kgm²/s³ or Wattoption (B) momentum, it cannot be not possible because momentum = mass × Velocity . so, its SI unit is Kgm/s or Nsoption (C) work, YES it is possible. work is the dot product of force and displacement. so, its SI unit is Kgm²/s² or Joule .option (D) force, it is obviously not possible. as all KNOW , Newton is si unit of force. hence, The unit of energy is same as the unit of work.

the LARGEST HORIZONTAL DISPLACEMENT that it POSSIBLE with the projectionspeed of 7m/s

2500ExplanatKq/R*2= 10 OUTSIDE of sphere=kq/r*2(r=2R)PUT VALUES and get the ans

l1+l2=25.2+16.8= 42cmdelta l1+delta l2=0.1+0.1= 0.2combined LENGTH=(42+.2)CM(42-.2)cm

(1):-157(2):-14264(3):-600

he moment of a force, also known as the torque T is defined as the force F acting at a PERPENDICULAR DISTANCE d. The dimension of moment is [M L2 T-2] which is the same as energy, however there is no DIRECT RELATIONSHIP between the two. The SI unit of a moment is the Newton meter (Nm).

A)The QUANTITY having DIMENSION is the RIGHT answer.hope it HELPS you!!

e period of a Simple pendulum is given by, Here, l is the length of pendulum, and g is the ACCELERATION due to gravity. Checking the correctness of the above equation through DIMENSIONAL analysis We need to prove that, The both sides of the equation have same dimensions. 2π is a dimensionless constant On the Left hand side TIME period = [T] On the right hand side 2π = No dimensions l = [L] g = [LT^-2]Now, T = 2π√(l/g)Therefore, The dimensions on both sides are equal. HENCE, is dimensionally correct.

1) 4.325×10^3. =magnitude is (3)2)0.789×10^3. =(3)3)1.6×10^-19. =(-19)Explanation:if we compare it with A×10^nhere, N is ORDER of magnitude then answer is such aswhere 0.5 is SMALL than A is small than 5

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udent,◆ Answer -V = k.η/(r.ρ)◆ Explaination -First LET's write down KNOWN dimensions.v = [L1T-1]r = [L1]ρ = [L-3M1]η = [L-1M1T-1]Suppose critical velocity of viscous fluid is GIVEN by -v = k.r^x.ρ^y.η^zIn dimensional form,[v] = [r]^x.[ρ]^y. [η]^z[L1T-1] = [L1]^x.[L-3M1]^y.[L-1M1T-1]^z[L1T-1] = [L^(x-3y-z).M^(y+z).T^(-z)]Comparing two sides,x-3y-z = 1y+z = 0-z = -1Solving we get,x = -1y = -1z = 1Substitute this in initial formula -v = k.r^-1.ρ^-1.η^1v = k.η/(r.ρ)Hope this helps you...

Explanation:10 N

consider, 1 unit of SI unit of work gives n units of CGS units of work. We KNOW that, Dimensional FORMULA for Work is Since IRRESPECTIVE of the unit, Work has same DIMENSIONS, We can WRITE Here, 1 corresponds to SI, and 2 corresponds to CGS. In SI, Units are kg, m, s while CGS has g, cm, s From our earlier discussion, 1 SI unit of work gives n = 10^7 CGS units of work. Hence, 1 Joule = 10^7 erg.

udent,◆ ANSWER -∆d/d % = 0.0182 %◆ Explaination -GIVEN that -M ± ∆M = 400.3 ± 0.02 gV ± ∆V = 75.6 ± 0.01 cm³Density of a SOLID is given by -d = M / VPercentage error in measurement of density will be -∆d/d % = (∆M/M + ∆V/V) × 100∆d/d % = (0.02/400.3 + 0.01/75.6) × 100∆d/d % = 0.0182 %Therefore, percentage error in determination of density is 0.0182 %.Best luck DEAR...

ind force exerted by the sun on the earth at FIRST. from gravitational force, F = GMm/r² here, M = 1.99 × 10³⁰ Kg, m = 5.97 × 10²⁴ kg , r = 1.49 × 10¹¹ m and G = 6.67 × 10⁻¹¹ Nm²/Kg² so, F = (6.67 × 10⁻¹¹ × 1.99 × 10³⁰ × 5.97 × 10²⁴)/(1.49 × 10¹¹)² = 35.69 × 10²¹ N = 3.569 × 10²² N now order of magnitude : if any number N is REPRESENTED as N = a × 10ⁿ , where √10/10 ≤ a < √10 , then n is KNOWN as order of magnitude of given number.here, 3.569 > √10 so, F = 3.569 × 10²² N = 0.3569 × 10²³ Nnow you SEE, √10/10 ≤ 0.3569 < √10so, 23 is order of magnitude of force exerted by sun on the earth.

The expression of the speed of sound in TERMS of pressure and the density of the air is given byExplanation:Given that, The speed of sound in air depends upon the pressure and density of air .Therefore, .Let, Dimensions of velocity, .Dimensions of pressure, .Dimensions of density, .Comparing the dimensions of both SIDES of relation (1), we GET,which gives, USING these VALUES,where, is the constant of proportionality.

Suppose a stationery object of mass m MOVES because of an applied force.Let u be its initial velocity (here u = 0).Let the applied force be F. This generates an acceleration a in the object, and, after time t, the velocity of the becomes equal to v. The displacement during this time is s.The work done on the object, W=F×sAccording to Newton's second law of motion,F=ma ------------ (1)SIMILARLY, using Newton's second EQUATION of motion However, as initial velocity is zero,u=0s=ut + 1/2 at2s=0 + 1/2 at2s= 1/2 AT2 ------------(2):. W=ma × 1/2 at2 -----------using equations (1) and(2)W=1/2 m(at)2 -------------(3)Using Newton's first equation of motion.............v= u + at:.v= 0 + at:.v= at:.v2 = (at)2 ----------(4):.W=1/2 mv2 -----------using equations (3) and (4)The kinetic energy gained by an object is the amount of work done on the object.:.K.E. = W:.K.E. = 1/2 mv2Hope it helps you

udent,◆ ANSWER -1 cal = 4.2 β⁻²α⁻¹γ² xy²z⁻²◆ Explaination -LET x, y and z be units of mass, length and time in new system of units.x = α kg, 1 kg = x/αy = β m, 1 m = y/βz = γ s, 1 s = z/γNow we know,1 cal = 4.2 J1 cal = 4.2 kgm²s⁻²Substitute values,1 cal = 4.2 × (x/α) × (y/β)² × (z/γ)⁻²z1 cal = 4.2 β⁻²α⁻¹γ² xy²z⁻²Therefore, magnitude of 1 cal in new system of units is 4.2 β⁻²α⁻¹γ².Hope this helps you...

n't COLLIDE....

itude of 2 is 60N then value of F1 will come out to be 60cos45°=60*1/√2=30√2and F2 will be equal to 60sin 45°30√2plz MARK BRAINLIEST if it HELPED .....

_MATE✔❤✌❤✔Dimensions:- ✔❤❤✔ Dimensions of any physical QUANTITY are those POWERS which are RAISED on fundamental units to express its unit. The expression which shows how and which of the BASE quantities represent the dimensions of a physical quantity, is called the dimensional formula.✔❤✌❤✔PIYUSH_SHARMA✔❤✌

Due to a few less concentration if DEVIATE from our ORIGINAL path is known as a mistake, If we are irresponsible for our work is known as the cause of mistake. If we are not started our work from FIXED TIME then they are also known as a mistake. If we want to not do any mistake then Always fully concentrate our work, give always our best.

: option (B) error explanation : here two confusing words are appeared. i.e.,“ error ” and “mistake” it seems, both are same in meaning. yes of course, these are SYNONYMOUS of each other. but their meaning are slightly different. An ‘error’ is nothing but deviation from accuracy or correctness.i.e., error = true value - MEASURED value it maybe either negative or positive.but A ‘mistake’ is an error CAUSED by fault.so, above DEFINITION cleared your doubts, didn't it ? now you can easily SAY , The difference between the true value and measured value is called error

It's INEVITABLE that any system will fail at times OFTEN failures are attributes to human error

Explanation:RANDOM Errors:-Errors that occur DUE to a fault in the symmetry of the instruments.It can be rectified by TAKING MANY trials and then finding the average of the values found.Hope this helps you....