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Find the order of magnitude of force exerted by the sun on the earth. Mass of the sun = 1.99 × 10³⁰ kg, Mass of earth = 5.97 × 10²⁴ kg, Distance between Earth and the Sun = 1.49 × 10¹¹ m, G = 6.67 × 10⁻¹¹ Nm²/kg² |
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Answer» ind force exerted by the sun on the earth at FIRST. from gravitational force, F = GMm/r² here, M = 1.99 × 10³⁰ Kg, m = 5.97 × 10²⁴ kg , r = 1.49 × 10¹¹ m and G = 6.67 × 10⁻¹¹ Nm²/Kg² so, F = (6.67 × 10⁻¹¹ × 1.99 × 10³⁰ × 5.97 × 10²⁴)/(1.49 × 10¹¹)² = 35.69 × 10²¹ N = 3.569 × 10²² N now order of magnitude : if any number N is REPRESENTED as N = a × 10ⁿ , where √10/10 ≤ a < √10 , then n is KNOWN as order of magnitude of given number.here, 3.569 > √10 so, F = 3.569 × 10²² N = 0.3569 × 10²³ Nnow you SEE, √10/10 ≤ 0.3569 < √10so, 23 is order of magnitude of force exerted by sun on the earth. |
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