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Check the correctness of T = 2π\sqrt{\frac{l}{g} } |
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Answer» e period of a Simple pendulum is given by, Here, l is the length of pendulum, and g is the ACCELERATION due to gravity. Checking the correctness of the above equation through DIMENSIONAL analysis We need to prove that, The both sides of the equation have same dimensions. 2π is a dimensionless constant On the Left hand side TIME period = [T] On the right hand side 2π = No dimensions l = [L] g = [LT^-2]Now, T = 2π√(l/g)Therefore, The dimensions on both sides are equal. HENCE, is dimensionally correct. |
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