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In an experiment to find the density of a solid, the mass and volume of the solid were found to be 400.3 ± 0.02 g and 75.6 ± 0.01 cm³ respectively. Find the percentage error in the determination of its density. |
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Answer» udent,◆ ANSWER -∆d/d % = 0.0182 %◆ Explaination -GIVEN that -M ± ∆M = 400.3 ± 0.02 gV ± ∆V = 75.6 ± 0.01 cm³Density of a SOLID is given by -d = M / VPercentage error in measurement of density will be -∆d/d % = (∆M/M + ∆V/V) × 100∆d/d % = (0.02/400.3 + 0.01/75.6) × 100∆d/d % = 0.0182 %Therefore, percentage error in determination of density is 0.0182 %.Best luck DEAR... |
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