1.

[M¹L¹T⁻¹] is an expression for _______.(A) force (B) energy(C) pressure (D) momentum

Answer»

: option (D) momentumexplanation : LET's check options one - by - one. option (A) we know, FORCE = mass × accelerationso, dimension of force = dimension of mass × dimension of acceleration= [M1][L¹T-²] = [M¹L¹T-²] , obviously, it is not the answer.option (B) energy = WORKDONE = force × displacementdimension of energy = dimension of force × dimension of displacement= [M¹L¹T-²] × [L¹] = [M¹L²T-²] , it is not same as above mentioned.option (C), PRESSURE = force/area so, dimension of pressure = [M¹L¹T-²]/[L²]= [M¹L-¹T-²] , no it's not correct.option (D), momentum = mass × velocityso, dimension of momentum = [M¹][L¹T-¹]= [M¹L¹T-¹], hurray ! we got it, dimension of momentum is same as above mentioned.hence, option (D) is correct.



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