This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A person walks 60 meters in 1 minute. Then walks 30 meters in 2 minutes. What is their average speed over the 3 minute walk? |
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Answer» average speed is 30 METER PER minute Explanation:if it is WRONG ,so I am sorry .. |
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| 2. |
What is... thermal induction?????? |
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Answer» IS UR ANSWERInduction heating is the process of heating an electrically CONDUCTING object by electromagnetic induction, through HEAT GENERATED in the object by eddy currents. An induction heater consists of an electromagnet and an ELECTRONIC OSCILLATOR that passes a high-frequency alternating current through the electromagnet. _______❤️________→FOLLOW ME→MAKE MY ANSWER BRAINLIST→GIVE THANKS TO MY ANSWER_______❤️________ |
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| 3. |
Calculate the gravitational force acting on object of mass 100kg (G=6.67×10-¹¹),(mass of earth=6×10²⁴kg),(radius of earth=6.4×10^6 m) please solve this question and explain it |
| Answer» EXPLANATION:PLS FIND THE ATTACHMENT THANKS | |
| 4. |
Give answer with appropriate explaination |
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Answer» tion:LISTEN tan(THETA) is PROPORTIONAL to FE I e qsquare .THEREFORE more is angle the more will be charge ....if m is same for both balls so if q1 more the Ø1 more |
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| 5. |
Find direction of induced current for the given case |
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| 6. |
WHAT IS A MOTION AND WHAT ARE ITS USES |
| Answer» SEE the attachmentplz MARK as BRANLIST LIKE and FOLLOW | |
| 7. |
Two lamps , one rated 40 W at 220V and the other 100W at 220V, are connected in parallel to the electric supply at 220V a. Draw a circuit diagram to show the connections b. Calculate the current drawn from the electric supply c. Calculate the total energy consumed by the lamps together when they operate for an hour |
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| 8. |
यदि कोई वस्तु 15cm वक्रता त्रिज्या के अवतल दर्पण से 10 cm की दूरी पर रखी हो , तो प्रतिभिबं की सिथति ज्ञात कीजिये । |
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Answer» Explanation:समाधान,हमारे पास हैत्रिज्या, R = - 15 cmवस्तु दूरी, U = - 10 cmढूँढ़ने के लिए,प्रतिभिबं की सिथति, v = ?यहाँ, हम जानते हैं किफोकल लम्बाई, f = R/2फिर, f = - 15/2 दर्पण सूत्र के अनुसार.हम जानते हैं कि,1/f = 1/u + 1/v फिर, 1/v = 1/f - 1/u सभी मूल्यों को रखते हुए, हम प्राप्त करते हैं,⇒ 1/v = 1/f - 1/u⇒ 1/v = 1/- 15 - 1/- 10⇒ 1/v = - 2/15 + 1/10⇒ 1/v = - 4 + 3/30⇒ 1/v = - 1/30⇒ v = - 30 cm इसलिये, प्रतिभिबं की सिथति 30 cm हैं। |
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| 9. |
An object is placed 40.0 cm in front of a convex mirror. The image appears 15 cm behind the mirror. What is the focal length of the mirror? 1 point + 24 c m + 11 cm -24 cm - 11 cm |
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| 10. |
List any five examples of motion you observe in a day. Mention the typeof motion it is. |
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Answer» running, cycling, JUMPING, eating and drinking ..EXPLANATION:I hope it HELP you.. |
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| 11. |
Please write the answer to this question and explain the procedure. |
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Answer» !!!Sorry REALLY can’t HELP u as the QUESTION is not fully visible to me!!!Sorry but plz FOLLOW me!!! |
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| 12. |
An object is placed at a distance of 40 cm from a concave mirror of focal length 15 cm. If the object is displaced through a distance of 20 cm towards the mirror, the displacement of the image will be |
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Answer» tion:v/u = f/ f-uv/40 = -15 / -15 + 40v = -24cmv / 20 = -15 / -15 +20V = -60cm that is the mirror MOVED by 36 CM away |
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| 13. |
What is a cardiologist? |
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Answer» Cardiology is a branch of medicine that deals with the disorders of the heart as well as some parts of the circulatory SYSTEM. The FIELD includes medical DIAGNOSIS and treatment of congenital heart defects, coronary artery disease, heart failure, valvular heart disease and electrophysiology. EXPLANATION:please mark as BRANLIST |
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| 14. |
A coil of R= 10ohm and L=5H is connected to a 100 V battery then energy stored is |
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Answer» 250JExplanation:v=IRI=V/R=10AE=1/2*LI SQUARE 1/2*5*10*10=250J |
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| 15. |
4 point charges of magnitude, +10Mc,+10Mc ,-10Mc, -10Mc are placed at 4 corners of the square of side 10cm . a point charge of magnitude+5Mc is placed at the center of the square then find the net force of the center |
| Answer» FORCE of the CENTRE is zero as EQUAL and opposite CHARGES cancel each other. | |
| 16. |
Plzzz solve this 1st question in given image...... class 11 its urgent now............... answer in briefly (1),(2) and (3) part |
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Answer» tion:1. 1.A=2i^+j^-3k^/√14 2.i^+3k^/2 3.-2i^+j^/√5 |
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| 17. |
Q#29. spread positivity |
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Answer» DON'T ASK HEAD SCRATCHING QUESTIONS DURING NIGHT TIME ASK SIMPLE QUESTIONSExplanation:AND MARK ME AS BRAINLIEST ANSWER |
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| 18. |
Two point white dots are 1mm apart on a black paper. They are viewed by eye of pupil diameter 3 mm. Approximately, what is the maximum distance at which these dots can be resolved by the eye? (Take 500nm) |
| Answer» TION:X/D = 1.22 λ/ D1 MM / D = 1.22 x 500 x 10⁻⁹ / 3 mmD = 5m | |
| 19. |
Alo find effective capacitance between A and B.Given C = 10 uF |
| Answer» HI BRO you ASK GOOD QUESTION | |
| 20. |
Find the resultant force: if 50 N force acts on a body in the downward direction and 60 N force acts on it at the same time in the upward direction |
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| 21. |
A beam of unpolarised light of intensity I0 is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 900 relative to that of A. What is the intensity of the emergent light when (N-1) more polaroids are inserted between them? Their axes are equally spaced. |
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Answer» IαA 2 where A is the amplitude and I is the INTENSITY For unpolarised light, it can be resolved into TWO components of equal magnitude in any pair of PERPENDICULAR DIRECTIONS. So the amplitude that is along the plane of polarisation of the polaroid will always be 2 A So, the intensity which will pass through it will always be 2I 0 Now when this polarised light falls on polaroid B whose plane of polarisation makes an angle θ with the plane of polarisation of INCIDENT light, the component of amplitude along the plane of polarisation of the polaroid is Acosθ.Therefore, intensity of light that passes through is I i cos 2 θ where I i is the intensity of incident light.Here, I i = 2I 0 and θ=45 ∘ So intensity of light emerging through B is2I 0 × 21 = 4I 0 HOPE IT HELPSTHANKS FOR YOUR QUESTION |
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| 22. |
The power factor of an ac circuit is given by |
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Answer» (1) the COSINE ANGLE between voltage and current(2) the ratio of kW/ KVA |
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| 23. |
A source emits electromagnetic waves of wavelength 3m. One beam reaches the observer directly and other after reflection from a water surface, travelling 1.5 m extra distance and with intensity reduced to 1/4 as compared to intensity due to the direct beam alone. The resultant intensity will be: |
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Answer» tion:I = I1 + I2 + 2√I1 I2 cosФHere Ф = 0I = I + i/4 + 2 X i/2 = 9i /4 |
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| 24. |
Formula for radius of gyration. |
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Answer» I = mk2 EXPLANATION: |
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| 25. |
An object of 5 cm height is placed at a distance of 15 cm from a concave mirror.Find the position, height and nature of its image.The focal length of the mirror is 10 cm |
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Answer» ▪ HEIGHT of object = 5cm▪ Distance of object = 15cm▪ Focal length of mirror = 10cm▪ Type of mirror : concaveTo FIND :▪ Distance of IMAGE.▪ Height of image.▪ Nature of image.Formula :✏ Mirror formula :☆ 1/u + 1/V = 1/f✏ Lateral magnification :☆ m = -v / u = h' / hCalculation :u = -15 cmf = -10 cmh = 5 cm☢ Distance of image (v) : → 1/ u + 1/v = 1/f→ 1/(-15) + 1/v = 1/(-10)→ 1/v = -1/10 + 1/15→ 1/v = (-3+2)/30→ v = -30 cm☢ Height of image (h') : → -v / u = h' / h→ -(-30)/(-15) = h' / 5→ -2 = h' / 5→ h' = -10 cm☢ Nature of image :RealInvetedEnlarged |
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| 26. |
Obtain an expression for energy stores in a capacitor. In following fig , the energy stored in c4 is 27J . Calculate the tital energy stores in the system |
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Answer» n following FIG, the energy stored in c4 is 27J.To find:Obtain an expression for energy stores in a capacitor. Calculate the TOTAL energy stores in the system.Solution:Now first let us consider,V(QR) = VThe energy stored in a capacitor is given by,U = 1/2 CV²The energy stored in C4 is given by,U4 = 1/2 C4V²27 = 1/2 (6 × 10^{-6}) V² (given U4 = 27 J)V² = 9 × 10^{-6}Now consider the energy stored in capacitor C2U2 = 1/2 C2V²U2 = 1/2 (2 × 10^{-6}) × 9 × 10^{-6}U2 = 9 JNow consider the energy stored in capacitor C3U3 = 1/2 C3V²U3 = 1/2 (3 × 10^{-6}) × 9 × 10^{-6}U3 = 13.5 JNow consider,U234 = U2 + U3 + U4= 9 + 13.5 + 27∴ U234 = 49.5 JNow consider the capacitors,C' = C2 + C3 + C4= 2 + 3 + 6∴ C' = 11 ×10^{-6} CNow let us consider other formula for stored energy,U = Q²/2CSo, we have,U234 = Q²/2C'49.5 = Q²/2(11 × 10^{-6})Q² = 49.5 × 22 × 10^{-6}Now consider the energy stored in capacitor C1 U1 = Q²/2C1= 49.5 × 22 × 10^{-6} / 2 × 1 × 10^{-6}∴ U1 = 544.5 JThe total energy stored is,U_{Total} = U1 + U234= 544.5 + 49.5∴ U_{Total} = 594 JTherefore the total energy in the system is 594 J |
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| 27. |
An alpha particle having kinetic energy 10Mev.an atom having atomic mass 35.calculate its distance of closest approach |
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Answer» 10.08 fermiExplanation:At it's closest approach, where, q₁ = charge on ALPHA particle = 2 × 1.6 × 10⁻¹⁹ q₂ = charge on NUCLEUS = 35 × 1.6 × 10⁻¹⁹ r = DISTANCE of closest approach K = 1/4π∈₀Hence,∴ |
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| 28. |
If A =B+C and the magnitudes of A , B and c are 5, 4 and 3 units, the angle between A and C is– (A)cos{3\5} (b)COS{4/5} (c) pi\2 (D)sin{3\4} |
| Answer» TION:hhzhshsiodpdjdjdndofpd | |
| 29. |
Please answer fast. Explain Clock rule. |
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Answer» ng to Clock Face Rule, Look at one face of the circular wire through which current is flowing. If the current is flowing in :(a)Clockwise DIRECTION then that face of circular wire will behave as SOUTH POLE and the opposite face will behave as North Pole.(b) Anti-clockwise direction then that face of wire will behave as North pole and the opposite face will behave as South pole.Ye yaad rakho agar Current clockwise direction mein flow ho raha hain toh wo face South pole hain AUR uska Opposite face North pole hoga.Agar Current ANTICLOCKWISE direction mein flow ho raha hain toh wo face North pole hoga aur uska opposite face South face Hoga.Please follow me |
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| 30. |
What precautions do you take while diluting acids? |
| Answer» ADD ACID in water by DROP wise not water in acidwe should wear glovesand GOGLES | |
| 31. |
Does electric potential happens in a circuit |
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Answer» c potential in the circuit HELPS in the MOVEMENT of the CHARGES from higher Potential to the LOWER potential. |
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| 32. |
A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates Young’s double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is |
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Answer» A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates YOUNG’s DOUBLE slit and GIVES RISE to TWO overlapping interference ...Top answer · 1 vote |
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| 33. |
What is adiabatic change ? Write the relation between pressure and volume of an ideal gas foran adiabatic change. What is the meaning of r. |
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Answer» tsydudrrfgguufxtdrfwftd GGM FYI your email ADDRESS is no need to do the NEEDFUL at earliestExplanation:yrfutact |
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| 34. |
Write down the postulates of the Kinetic theoryof gases. |
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Answer» tion:--->A gas consists of molecules in constant random motion.--->Gas molecules influence each other only by collision; they exert no other FORCES on each other.--->All collisions between gas molecules are PERFECTLY elastic; all kinetic ENERGY is conserved.Please MARK as brainliest if it helped. |
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| 35. |
Show a diagram of electric potential and potential difference |
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Answer» The electrical POTENTIAL difference is defined as the amount of work DONE to CARRYING a unit charge from one POINT to another in an electric field. In other words, the potential difference is defined as the difference in the electric potential of the two charged bodies.Explanation:PLS FOLLOW ME |
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| 36. |
Give a diagram of electric circuit potential at a point |
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Answer» The electric POTENTIAL TELLS you how MUCH potential energy a single point CHARGE at a given location will have. The electric potential at a point is equal to the electric potential energy (measured in JOULES) of any charged particle at that location divided by the charge (measured in coulombs) of the particle |
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| 37. |
The area of a parallelogram whose diagonals are P= 2î +3j and Q= i +4j is |
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Answer» Explanation:The MAGNITUDE (length) of p is 13−−√ and the magnitude of Q is 17−−√. With the HEIGHT shown the area is A=17−−√H To find the value of h, the sine of θ and the magnitude of p can be used. Need to find the value of θ. cosθ=p⃗ ⋅q⃗ ∥∥p⃗ ∥∥∥∥q⃗ ∥∥ cosθ=2(1)+3(4)13√17√ θ=cos−1(14221√)≈19.6538∘ sinθ=h13√ h=13−−√sinθ=13−−√sin(19.6538∘) Substitution results in: A=17−−√13−−√sin(19.6538∘)≈4.9999 The area of the parallelogram is 4.9999 units squared.please mark it as brainliest |
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| 38. |
612 B35. Calculate the effectiveresistance between the points AA and B in the circuit shownin figure. |
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Answer» resistors and are in SERIES connection, then their effective RESISTANCE is,If two resistors and are in PARALLEL connection, then their effective resistance is,In the fig., two groups of resistors, having resistance each connected in parallel, are connected in series.Here the group of resistors and are connected in parallel each with a resistance of . Hence their EQUIVALENT resistance is,Similarly, resistors and are also connected in parallel. Hence their equivalent resistance is also,Now the circuit can be shortened to as the following.Hence the effective resistance between points A and B is,THUS equivalent resistance is |
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| 39. |
What Is nature of light |
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Answer» Light is a transverse, electromagnetic wave that can be SEEN by the TYPICAL human. The wave nature of light was first illustrated through experiments on diffraction and interference. LIKE all electromagnetic WAVES, light can travel through a vacuum.Explanation:PLS FOLLOW ME |
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| 40. |
Three cars start from the same time simultaneously.Car A finishes in 9 seconds, Car B finishes in 16 seconds in how many seconds does Car C finishes. And also three cars have same acceleration and cars A and B have same initial velocities bit Car C's initial velocity is=0 |
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Answer» It is a WRONG QUESTION. There WOULD be some CORRECTION in question. |
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| 41. |
Monochromatic light of wavelength 400 nm and 560 nm are incident simultaneously on double slits apparatus whose slits separation is 0.1 mm and screen distance is 1 m. Distance between areas of total darkness will be |
| Answer» LING QUES very long OK short plz | |
| 42. |
Please solve this ____________________________________________ |
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Answer» can you PLEASE tell me what is the CHAPTER name then I can SOLVE your question |
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| 43. |
32. a. Find the velocity of source of sound, when the frequency appears to be double to a stationaryobserver velocity of sound in 330 ms |
| Answer» SORRY, but I don't KNOW!EXPLANATION: | |
| 44. |
What will happen if the sum will not exist ? Will the planets still in their orbit due to the centripetal force are there will be any affect on them ? |
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Answer» Which SUM....PLEASE TELL thatExplanation:Please MARK me as the BRAINLIEST |
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| 45. |
What is the nature of the image formed by a concave mirror if the magnification produced by the mirror is -2 |
| Answer» OW r u??❤️┏_________∞◆∞_________┓✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭┗_________∞◆∞_________┛Since the magnification is negative, we understand that the image is inverted By the equation for magnification,m = -v/u-2 = -v/u-2u = -vv = 2um = h' / h-2 = h' / HH' = -2hImage DISTANCE is twice the object distance since v = 2uImage size or image height is twice the object height or OBJCET height since h' = 2h┏_________∞◆∞_________┓✭Hòpè Ìt Hèĺp§✭Fòĺĺòw @zahaansajidPls mark as brainliest✭Follow me and I'll follow you back ✭┗_________∞◆∞_________┛ | |
| 46. |
A parallel plate capacitor made up of circular plates each of radius 6 CM has a capacitance 100pf capacitor is connected to a 230 volt supply with a frequency of 300 radius raise to -1 what is The RMS value of the conductor dash current |
| Answer» KNOW SORRY ............ | |
| 47. |
A car starts from rest and attains velocity of 20 m/s in 20 sec . The distance traveled in car during this period is |
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Answer» ▪ INITIAL velocity = zero (i.e. rest)▪ Final velocity = 20mps▪ Time interval = 20sTo Find :▪ Distance covered by car in the given interval of time.Concept :✏ Since, acceleration has SAID to be constant throughout the journey, we can easily APPLY equation of kinematics to solve this type of questions. First equation of kinematics :☆ v = u + atThird equation of kinematics :☆ v² - u² = 2ass denoted distance u denotes initial velocityt denotes timea denotes accelerationv denotes final velocityCalculation :☢ Acceleration of car :→ v = u + at→ 20 = 0 + a(20)→ a = 20/20→ a = 1m/s²☢ Distance covered by car :→ v² - u² = 2as→ (20)² - (0)² = 2(1)s→ 400 = 2s→ s = 400/2→ s = 200m |
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| 48. |
Body starts from rest at acceleration of 5m/s2 what will its' velocity after 10 seconds |
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Answer» 50m/sExplanation: |
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| 49. |
The area of a parallelogram whose diagonals are P= 2î +3j and Q = i +4j is a) 5 sq.units. b)10 sq.unitsc) 20 sq.units. d) 2.5 sq.units |
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Answer» (d) 2.5 sq. units.Explanation:AREA of a parallelogram with it's diagonals GIVEN isHere, d₁ = 2I + 3jAnd, d₂ = 1i + 4jHence, (d₁ × d₂)HENCE, area of parallelogram, |
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| 50. |
What are the unbalanced forces? Expcontact forces' and 'non-contact forces'.lain the differe nce between |
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Answer» There are two TYPES of forces: CONTACT forces: objects are in contact with each other and exert forces on each other. Non-contact (FIELD) forces: objects are not in contact with each other and exert forces on each other.!...HOPE THIS HELP U...!❤!...AND THANKS FOR WRITING MY STORY...!❤ |
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