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The area of a parallelogram whose diagonals are P= 2î +3j and Q= i +4j is |
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Answer» Explanation:The MAGNITUDE (length) of p is 13−−√ and the magnitude of Q is 17−−√. With the HEIGHT shown the area is A=17−−√H To find the value of h, the sine of θ and the magnitude of p can be used. Need to find the value of θ. cosθ=p⃗ ⋅q⃗ ∥∥p⃗ ∥∥∥∥q⃗ ∥∥ cosθ=2(1)+3(4)13√17√ θ=cos−1(14221√)≈19.6538∘ sinθ=h13√ h=13−−√sinθ=13−−√sin(19.6538∘) Substitution results in: A=17−−√13−−√sin(19.6538∘)≈4.9999 The area of the parallelogram is 4.9999 units squared.please mark it as brainliest |
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