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A car starts from rest and attains velocity of 20 m/s in 20 sec . The distance traveled in car during this period is |
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Answer» ▪ INITIAL velocity = zero (i.e. rest)▪ Final velocity = 20mps▪ Time interval = 20sTo Find :▪ Distance covered by car in the given interval of time.Concept :✏ Since, acceleration has SAID to be constant throughout the journey, we can easily APPLY equation of kinematics to solve this type of questions. First equation of kinematics :☆ v = u + atThird equation of kinematics :☆ v² - u² = 2ass denoted distance u denotes initial velocityt denotes timea denotes accelerationv denotes final velocityCalculation :☢ Acceleration of car :→ v = u + at→ 20 = 0 + a(20)→ a = 20/20→ a = 1m/s²☢ Distance covered by car :→ v² - u² = 2as→ (20)² - (0)² = 2(1)s→ 400 = 2s→ s = 400/2→ s = 200m |
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