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An object of 5 cm height is placed at a distance of 15 cm from a concave mirror.Find the position, height and nature of its image.The focal length of the mirror is 10 cm |
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Answer» ▪ HEIGHT of object = 5cm▪ Distance of object = 15cm▪ Focal length of mirror = 10cm▪ Type of mirror : concaveTo FIND :▪ Distance of IMAGE.▪ Height of image.▪ Nature of image.Formula :✏ Mirror formula :☆ 1/u + 1/V = 1/f✏ Lateral magnification :☆ m = -v / u = h' / hCalculation :u = -15 cmf = -10 cmh = 5 cm☢ Distance of image (v) : → 1/ u + 1/v = 1/f→ 1/(-15) + 1/v = 1/(-10)→ 1/v = -1/10 + 1/15→ 1/v = (-3+2)/30→ v = -30 cm☢ Height of image (h') : → -v / u = h' / h→ -(-30)/(-15) = h' / 5→ -2 = h' / 5→ h' = -10 cm☢ Nature of image :RealInvetedEnlarged |
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