Saved Bookmarks
| 1. |
An alpha particle having kinetic energy 10Mev.an atom having atomic mass 35.calculate its distance of closest approach |
|
Answer» 10.08 fermiExplanation:At it's closest approach, where, q₁ = charge on ALPHA particle = 2 × 1.6 × 10⁻¹⁹ q₂ = charge on NUCLEUS = 35 × 1.6 × 10⁻¹⁹ r = DISTANCE of closest approach K = 1/4π∈₀Hence,∴ |
|