67486 + Interview Questions in Secondary School in Physics

1.	A body is projected into air certain angle ø to the horizontal, what is the ratio at the potentialenergy to K.E at the maximum height?
Answer» ANSWER: 2/1 is it RIGHT????? GIVE me the right answer

1.

A body is projected into air certain angle ø to the horizontal, what is the ratio at the potentialenergy to K.E at the maximum height?

Answer»

ANSWER:

2/1 is it RIGHT????? GIVE me the right answer

Discussion

2.	What is meant by self confidence
Answer» Answer: when we have BELIEVE on your self when we don't DEPENDS on other that is known as self CONFIDENCE

2.

What is meant by self confidence

Answer»

Answer:

when we have BELIEVE on your self

when we don't DEPENDS on other

that is known as self CONFIDENCE

Discussion

3.	1.Substance used as synthetic (7)2.A plastic used for making containers and carry bags(9) 3.substance made up of large number of smaller molecules(7) 4.Another name for this compound is artificial silk (5)
Answer» Answer: SUBSTANCE USED as synthetic. PVC, polythene and bakelite are synthetic substances. A plastic used for making containers and carry bags. Plastic bags are made from a ubiquitous polymer substance known as polyethylene. Substance made up of large number of SMALLER MOLECULES. Substance made up of large number of smaller molecules is polymer. Another NAME for this compound is artificial silk. Its common name is rayon. Rayon is often regarded as artificial silk.

3.

1.Substance used as synthetic (7)2.A plastic used for making containers and carry bags(9) 3.substance made up of large number of smaller molecules(7) 4.Another name for this compound is artificial silk (5)

Answer»

Answer:

SUBSTANCE USED as synthetic.

PVC, polythene and bakelite are synthetic substances.

A plastic used for making containers and carry bags.

Plastic bags are made from a ubiquitous polymer substance known as polyethylene.

Substance made up of large number of SMALLER MOLECULES.

Substance made up of large number of smaller molecules is polymer.

Another NAME for this compound is artificial silk.

Its common name is rayon. Rayon is often regarded as artificial silk.

Discussion

4.	an object of size density is placed at 30 cm in front of a concave mirror of focal length 20cm at what distance from the mirror should a screen be placed so that a sharp focus image can be obtained find the size of the nature of the image
Answer» ANSWER: Given, U = 30cm f = 20cm v = ? in CASE of concave mirror, FORMULA is $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$ =} Here u need to take f and u negative =} (-1)/20 = (-1)/30 + 1/v =} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20 =} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60) =} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60)=} v = 60cm =} the distance from mirror to OBJECT is 60cm

4.

an object of size density is placed at 30 cm in front of a concave mirror of focal length 20cm at what distance from the mirror should a screen be placed so that a sharp focus image can be obtained find the size of the nature of the image

Answer»

ANSWER:

Given,

U = 30cm

f = 20cm

v = ?

in CASE of concave mirror,

FORMULA is

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

=} Here u need to take f and u negative

=} (-1)/20 = (-1)/30 + 1/v

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60)

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60)=} v = 60cm

=} the distance from mirror to OBJECT is 60cm

Discussion

5.	Why it is easy to catch a rubber ball then a steel ball of same size moving with same velocity
Answer» ANSWER: It MAY Be DUE To DIFFERENCE In Their DENSITIES .

5.

Why it is easy to catch a rubber ball then a steel ball of same size moving with same velocity

Answer»

ANSWER:

It MAY Be DUE To DIFFERENCE In Their DENSITIES .

Discussion

6.	300 kg of water are lifted 10 m vertically in 5 s.show that the work done is 30 KJ and that the power is 6 KW.
Answer» Answer: Work done= m ×g× h so W= 300×10×10= 30000 J or 30 KJ And Power= Work done/time taken so P=30000/5=6000W Or 6KW

6.

300 kg of water are lifted 10 m vertically in 5 s.show that the work done is 30 KJ and that the power is 6 KW.

Answer»

Answer:

Work done= m ×g× h

so W= 300×10×10= 30000 J or 30 KJ

And Power= Work done/time taken

so P=30000/5=6000W Or 6KW

Discussion

7.	Solve the following ordinary differential equation d 2y/dx2+dy/dx+y=0
Answer» ANSWER: SORRY I am WEAK in Mathematic sorryyyyyyyyyyyyy sorryyyyyy

7.

Solve the following ordinary differential equation d 2y/dx2+dy/dx+y=0

Answer»

ANSWER:

SORRY I am WEAK in Mathematic

sorryyyyyyyyyyyyy

sorryyyyyy

Discussion

8.	35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.
Answer» $\huge{\mathfrak{Bonjour!♡}}$ •°⭑ $\bullet{\underline{\sf{\color{lightpink}{Capillary\: Action:-}}}}$ ⭑The phenomenon of RISE and fall of liquid in a capillary tube is KNOWN as Capillary Action. $\bullet{\underline{\sf{\color{lightpink}{Concept:-}}}}$ ⭑It is experimentally found that PRESSURE below concave surface is less than 2T/R from pressure just above it. In order to compensate this pressure DIFFERENCE liquid RISES inside capillary tube. $\bullet{\underline{\sf{\color{lightpink}{Derivation:-}}}}$ According to concept; $\rightarrow{ \tt{\frac{2T}{R} = \rho gh}} \\ \\ \rightarrow \:{ \bf{ h = \frac{2T}{R \rho g}}} \: \: \: \: \: \: ...(1)$ $\boxed{ \sf{cos \theta = \frac{r}{R} \: \: \: r = radius \: of \: capillary \: tube}} \\$ $\rightarrow \: { \tt{R = \frac{r}{cos \theta} }} \: \: \: \: ...(2) \\ \\{ \sf{ putting \: eq(2) \: into \: \: eq(1)}} \\ \\ \leadsto{ \boxed{ \bf{h = \frac{2T}{r \rho g} cos \theta}}} \\$

8.

35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.

Answer»

$\huge{\mathfrak{Bonjour!♡}}$ •°⭑

$\bullet{\underline{\sf{\color{lightpink}{Capillary\: Action:-}}}}$

⭑The phenomenon of RISE and fall of liquid in a capillary tube is KNOWN as Capillary Action.

$\bullet{\underline{\sf{\color{lightpink}{Concept:-}}}}$

⭑It is experimentally found that PRESSURE below concave surface is less than 2T/R from pressure just above it. In order to compensate this pressure DIFFERENCE liquid RISES inside capillary tube.

$\bullet{\underline{\sf{\color{lightpink}{Derivation:-}}}}$

According to concept;

$\rightarrow{ \tt{\frac{2T}{R} = \rho gh}} \\ \\ \rightarrow \:{ \bf{ h = \frac{2T}{R \rho g}}} \: \: \: \: \: \: ...(1)$

$\boxed{ \sf{cos \theta = \frac{r}{R} \: \: \: r = radius \: of \: capillary \: tube}} \\$

$\rightarrow \: { \tt{R = \frac{r}{cos \theta} }} \: \: \: \: ...(2) \\ \\{ \sf{ putting \: eq(2) \: into \: \: eq(1)}} \\ \\ \leadsto{ \boxed{ \bf{h = \frac{2T}{r \rho g} cos \theta}}} \\$

Discussion

9.	Differentiate between solar and lunar eclips
Answer» Answer: Solar eclipses RESULT from the MOON blocking the Sun relative to the Earth; thus Earth, Moon and Sun all LIE on a line. Lunar eclipses work the same WAY in a different order: Moon, Earth and Sun all on a line. In this case the Earth's shadow hides the Moon from view. Explanation:

9.

Differentiate between solar and lunar eclips

Answer»

Answer:

Solar eclipses RESULT from the MOON blocking the Sun relative to the Earth; thus Earth, Moon and Sun all LIE on a line. Lunar eclipses work the same WAY in a different order: Moon, Earth and Sun all on a line. In this case the Earth's shadow hides the Moon from view.

Explanation:

Discussion

10.	In a gravity free space, a man of mass M standing at a height h above the ground throws a ball of mass m straight down with speed u. When the ball reaches the ground the distance of the man from above the ground is?
Answer» Answer: the centre of mass of the system doesn't change i.e..., change in COM=0 consider the MAN M moves a distance of X in the opposite DIRECTION (gravity free space) therefore, M(X) + m (-H) = 0

10.

In a gravity free space, a man of mass M standing at a height h above the ground throws a ball of mass m straight down with speed u. When the ball reaches the ground the distance of the man from above the ground is?

Answer»

Answer:

the centre of mass of the system doesn't change

i.e...,

change in COM=0

consider the MAN M moves a distance of X in the opposite DIRECTION (gravity free space)

therefore,

M(X) + m (-H) = 0

Discussion

11.	A ball thrown up is caught by the thrower 6s after start. till what height will the ball will rise
Answer» ANSWER: h=1/2×10×36= 180M. is it RIGHT??

11.

A ball thrown up is caught by the thrower 6s after start. till what height will the ball will rise

Answer»

ANSWER:

h=1/2×10×36= 180M. is it RIGHT??

Discussion

12.	What are the non contact forces?
Answer» Non contact forces are those forces which ACT on an OBJECT without COMING in contact with it. The are CONSERVATIVE forces. e.g. ge gravitational force, magnetic force etc.

12.

What are the non contact forces?

Answer»

Non contact forces are those forces which ACT on an OBJECT without COMING in contact with it.
The are CONSERVATIVE forces.
e.g. ge
gravitational force, magnetic force etc.

Discussion

13.	Uses of thermal conductivity of bad conductor by Lee's disc
Answer» ANSWER: In addition, it has radial holes to insert thermometers. Thermal CONDUCTIVITY is the property of a MATERIAL . It indicates the ability of a material to conduct HEAT. At the steady state, heat conducted through the bad CONDUCTOR is equal to heat radiated from the Lee's disc.

13.

Uses of thermal conductivity of bad conductor by Lee's disc

Answer»

ANSWER:

In addition, it has radial holes to insert thermometers. Thermal CONDUCTIVITY is the property of a MATERIAL . It indicates the ability of a material to conduct HEAT. At the steady state, heat conducted through the bad CONDUCTOR is equal to heat radiated from the Lee's disc.

Discussion

14.	Why dimensional method are applicable only to three quantities?
Answer» ANSWER: most irritating, eating, WATCHING phone Explanation: v'vvvvvvvv. BB N n. BNN

14.

Why dimensional method are applicable only to three quantities?

Answer»

ANSWER:

most irritating, eating, WATCHING phone

Explanation:

v'vvvvvvvv. BB N n. BNN

Discussion

15.	Observation practical book page no 26
Answer» ANSWER: What is the QUESTION?

15.

Observation practical book page no 26

Answer»

ANSWER:

What is the QUESTION?

Discussion

16.	Please answer with explanation ......
Answer» ANSWER: OPTION d is correct answer FOLLOW me and marks as BRAINLIST

16.

Please answer with explanation ......

Answer»

ANSWER:

OPTION d is correct answer FOLLOW me and marks as BRAINLIST

Discussion

17.	If magnification of m is less than 0 the image formed is
Answer» Answer: is magnification is less than ZERO then the image is VIRTUAL and erect. I hope it HELPS you please MARK as brainliest

17.

If magnification of m is less than 0 the image formed is

Answer»

Answer:

is magnification is less than ZERO then the image is VIRTUAL and erect.

I hope it HELPS you

please MARK as brainliest

Discussion

18.	Why does the colour of alcohol change?
Answer» Answer: ETHANOL change color because ethanol gets OXIDIZED to form ethanoic acid WHOSE color will change from orange to green. Explanation: The ethanol will undergo an OXIDATION reaction where ethanoic acid is formed which will result in the formation of chromium disulphite.

18.

Why does the colour of alcohol change?

Answer»

Answer:

ETHANOL change color because ethanol gets OXIDIZED to form ethanoic acid WHOSE color will change from orange to green. Explanation: The ethanol will undergo an OXIDATION reaction where ethanoic acid is formed which will result in the formation of chromium disulphite.

Discussion

19.	Calculate the change in pressure in the following cases 1 when force acting an is doubled 2
Answer» ANSWER: p=w/t Explanation: w=f/s p=f1×s/t /f2×s/t =f1/f2 =1/2 =1:2

19.

Calculate the change in pressure in the following cases 1 when force acting an is doubled 2

Answer»

ANSWER:

p=w/t

Explanation:

w=f/s

p=f1×s/t

/f2×s/t

=f1/f2

=1/2

=1:2

Discussion

20.	What will be the force of a 60 kg man on the moon, mars and jupiter? are they the same? why?
Answer» Force = MASS X acceleration DUE to gravity I don't THINK they will be the same, because of acceleration due to gravity. The acceleration due to gravity varies

20.

What will be the force of a 60 kg man on the moon, mars and jupiter? are they the same? why?

Answer»

Force = MASS X acceleration DUE to gravity

I don't THINK they will be the same, because of acceleration due to gravity.

The acceleration due to gravity varies

Discussion

21.	The rate of chang of momentum of an object is proportional to
Answer» ANSWER: *THE* *RATE* OF *CHANGE* OF *MOMENTUM* OF AN *OBJECT* IS *PROPORTIONAL* TO *APPLIED* *FORCE. Explanation:* NEWTONS SECOND *LAW*..

21.

The rate of chang of momentum of an object is proportional to

Answer»

ANSWER:

THE RATE OF CHANGE OF MOMENTUM OF AN OBJECT IS PROPORTIONAL TO APPLIED FORCE.

Explanation:

NEWTONS SECOND LAW..

Discussion

22.	Define critical angle calculate critical angle of liquid whose refractive index is 2
Answer» ANSWER: u=1/sinc , 2= 1/sinc , sinc=1/2 c=30degrees . HOPE you UNDERSTAND this

22.

Define critical angle calculate critical angle of liquid whose refractive index is 2

Answer»

ANSWER:

u=1/sinc , 2= 1/sinc , sinc=1/2 c=30degrees . HOPE you UNDERSTAND this

Discussion

23.	(4) It cannot overtake the busA balloon is sing with undspeed 6ADedos e punow weby the stone tofrom the balloon Themestrike the grounds 10 m70bus8090(4) 18
Answer» ANSWER: 20 m/s- your answer but TRY to GET

23.

(4) It cannot overtake the busA balloon is sing with undspeed 6ADedos e punow weby the stone tofrom the balloon Themestrike the grounds 10 m70bus8090(4) 18

Answer»

ANSWER:

20 m/s- your answer but TRY to GET

Discussion

24.	Frequency of ultrasound is
Answer» Answer: ULTRASOUND devices OPERATE with frequencies from 20 kHz up to several gigahertz.

24.

Frequency of ultrasound is

Answer»

Answer:

ULTRASOUND devices OPERATE with frequencies from 20 kHz up to several gigahertz.

Discussion

25.	Motion of needle of clock is uniform or non uniform motion
Answer» ANSWER: The needles of clock possess UNIFORM Motion. Explanation: The needles of clock travel equal distance in equal INTERVALS of TIME. THEREFORE, it is uniform motion.

25.

Motion of needle of clock is uniform or non uniform motion

Answer»

ANSWER:

The needles of clock possess UNIFORM Motion.

Explanation:

The needles of clock travel equal distance in equal INTERVALS of TIME. THEREFORE, it is uniform motion.

Discussion

26.	A pasenger train of length 60 m travels at a speed of 80
Answer»

Discussion

27.	An object can be considered as a point object if the distance travelled by it is dash than its size.
Answer» Answer An OBJECT can be CONSIDERED as a point object if the distance TRAVELLED by it is more than its size. Hope this helps please mark as the BRAINLIEST

27.

An object can be considered as a point object if the distance travelled by it is dash than its size.

Answer»

Answer

An OBJECT can be CONSIDERED as a point object if the distance TRAVELLED by it is more than its size.

Hope this helps please mark as the BRAINLIEST

Discussion

28.	In a hydrogen atom the electron and proton are at a distance of 0.5 angstroms . The dipole moment of the system is
Answer» Explanation: DIPOLE moment p=q.2a where, q=charge 2a=distace between two CHARGES thus, for ELECTRON and proton charge q=1.6×10^-19c distance 2a=0.510^-10m therefor p= 1.6×10^-190.510^-10 p=0.810^-29

28.

In a hydrogen atom the electron and proton are at a distance of 0.5 angstroms . The dipole moment of the system is

Answer»

Explanation:

DIPOLE moment p=q.2a

where, q=charge

2a=distace between two CHARGES

thus,

for ELECTRON and proton charge q=1.6×10^-19c

distance 2a=0.5*10^-10m

therefor p= 1.6×10^-19*0.5*10^-10

p=0.8*10^-29

Discussion

29.	It is easier to pull down a tree branch from it's free end than anywhere else
Answer» ANSWER: *YES, it is easier to PULL down a tree BRANCH from it's FREE end than anywhere else.*

29.

It is easier to pull down a tree branch from it's free end than anywhere else

Answer»

ANSWER:

YES, it is easier to PULL down a tree BRANCH from it's FREE end than anywhere else.

Discussion

30.	A concave mirror forms image of an object placed in front of it,at a distance of 20 cm behind the mirror.If focal length of the mirror is 20 cm,then find the magnification.Answer with explanation.
Answer» ANSWER: *HERE* IS *YOUR* *ANSWER* Explanation: PLS. *MARK* ME AS *BRAINLISTER*

30.

A concave mirror forms image of an object placed in front of it,at a distance of 20 cm behind the mirror.If focal length of the mirror is 20 cm,then find the magnification.Answer with explanation.

Answer»

ANSWER:

HERE IS YOUR ANSWER

Explanation:

PLS. MARK ME AS BRAINLISTER

Discussion

31.	Give an example where electron ejects photon.
Answer» Answer: When we provides energy to electron it get excited to higher energy STATE.. ( higher energy => less stability) so this excited state don't last long and electron falls to the GROUND level and EMITS I hope it's HELPFUL for you

31.

Give an example where electron ejects photon.

Answer»

Answer:

When we provides energy to electron it get excited to higher energy STATE.. ( higher energy => less stability) so this excited state don't last long and electron falls to the GROUND level and EMITS

I hope it's HELPFUL for you

Discussion

32.	(a) What are fossil fuels ? Give three examples of fossil fuels.(b) Describe how fossil fuels were formed. (C) Explain how, sun is considered to be the ultimate source of fossil fuels. (d) Which fossil fuels were formed by the buried remains of small plants and animals?(e) Which fossil fuel was formed by the buried remains of large land plants ?
Answer» Answer: a) Fossil FUELS are the fuel obtained from digging the EARTH and other natural resources. They are formed more than millions years ago. The PLANT and animal got buried millions of years ago and undergo chemical changes due to PRESSURE and transformed into fossil fuel.

32.

(a) What are fossil fuels ? Give three examples of fossil fuels.(b) Describe how fossil fuels were formed. (C) Explain how, sun is considered to be the ultimate source of fossil fuels. (d) Which fossil fuels were formed by the buried remains of small plants and animals?(e) Which fossil fuel was formed by the buried remains of large land plants ?

Answer»

Answer:

a) Fossil FUELS are the fuel obtained from digging the EARTH and other natural resources. They are formed more than millions years ago. The PLANT and animal got buried millions of years ago and undergo chemical changes due to PRESSURE and transformed into fossil fuel.

Discussion

33.	WHY DO SOUND TRAVEL IN THE NIGHT MORE FASTER THAN IN DAY
Answer» EXPLANATION: in the day the temperature is QUITE hotter and as result the particles move little FASTER and as result carry sounds more fast follow bro

33.

WHY DO SOUND TRAVEL IN THE NIGHT MORE FASTER THAN IN DAY

Answer»

EXPLANATION:

in the day the temperature is QUITE hotter and as result the particles move little FASTER and as result carry sounds more fast

follow bro

Discussion

34.	What is the SI unit of impulse ?
Answer» NEWTON SECOND IS THE SI UNIT OF IMPULSE

34.

What is the SI unit of impulse ?

Answer»

NEWTON SECOND IS THE SI UNIT OF IMPULSE

Discussion

35.	Two strings are passing over a smooth pulley on one side they are attached to masses 3kg and 4kg respectively and on the other to one of 5kg .find the tension in the strings and the acceleration of the system
Answer» smaller mass = m1=3kg » LARGER mass =m2=4kg » Tension = T » For mass m 1 => T−m 1 G=ma ____eq(1) » For mass m 2 => m 2 g−T=m 2 a. ____eq(2) » By EQ(1) + eq(2) => (m 2 −m 1 )g = (m 1 +m 2 )a => a=(m 2 −m 1 )g/(m 1 +m 2 ) => $$a = (4-3)×10/(4+3)$$ =>$$ a = 1×10/7 = 10/7$$ => a=33.6ms − 2

35.

Two strings are passing over a smooth pulley on one side they are attached to masses 3kg and 4kg respectively and on the other to one of 5kg .find the tension in the strings and the acceleration of the system

Answer»

smaller mass = m1=3kg

» LARGER mass =m2=4kg

» Tension = T

» For mass m

1

=> T−m

1

G=ma ____eq(1)

» For mass m

2

=> m

2

g−T=m

2

a. ____eq(2)

» By EQ(1) + eq(2)

=> (m

2

−m

1

)g = (m

1

+m

2

)a

=> a=(m

2

−m

1

)g/(m

1

+m

2

)

=> $$a = (4-3)×10/(4+3)$$

=>$$ a = 1×10/7 = 10/7$$

=> a=33.6ms

−

2

Discussion

36.	A Lens has focal length 20 can. Calculatepower of lens..
Answer» ANSWER: POWER of LENS = 1/f = 1/20

36.

A Lens has focal length 20 can. Calculatepower of lens..

Answer»

ANSWER:

POWER of LENS = 1/f

= 1/20

Discussion

37.	Electric motor based on flemmingsleft hand rule
Answer» EXPLANATION: ELECTRIC motor is based on Flemming left hand rule.this is CORRECT STATEMENT.

37.

Electric motor based on flemmingsleft hand rule

Answer»

EXPLANATION:

ELECTRIC motor is based on Flemming left hand rule.this is CORRECT STATEMENT.

Discussion

38.	Very low temperatures are measured using ?
Answer» ANSWER: USING a cryometre... EXPLANATION: FOLLOW MAH ❣️❣️

38.

Very low temperatures are measured using ?

Answer»

ANSWER:

USING a cryometre...

EXPLANATION:

FOLLOW MAH ❣️❣️

Discussion

39.	In a resonance column experiment the first resonance is obtained when the level of water in tube is 20 cm from the open end resonance will also be obtained when the water level is at a distance of
Answer» Answer: Given: 1st resonance is obtained at 20 CM in open organ TUBE. To find: 2nd resonance at what depth. Concept: In an open organ tube , the open end FORMS anti-node and closed end forms node. Let depth at which fundamental frequency happens be l , wavelength of STANDING WAVE be λ , depth of 2nd resonance be l2 For fundamental frequency , we can say that : $\boxed{ \sf{ \huge{ \red{l = \dfrac{ \lambda}{4} }}}}$ For 2nd frequency , we can say that : $\boxed{{ \sf{ \large{ \green{ \therefore l_{2} = \dfrac{ \lambda}{4} + \dfrac{ \lambda}{2} }}}}}$ ${ \sf{ \large{ \green{ \therefore l_{2} = \dfrac{ 3\lambda}{4} }}}}$ So we can understand that $\boxed{ \boxed{ \sf{l_{2} = 3 \times l}}}$ $\sf{ \implies \: l_{2} = 3 \times 20}$ $\sf{ \implies \: l_{2} = 60 \: cm}$ So final answer : $\boxed{ \red{ \bold{ \sf{2nd \: resonance \: at \: 60 \: cm}}}}$

39.

In a resonance column experiment the first resonance is obtained when the level of water in tube is 20 cm from the open end resonance will also be obtained when the water level is at a distance of

Answer»

Answer:

Given:

1st resonance is obtained at 20 CM in open organ TUBE.

To find:

2nd resonance at what depth.

Concept:

In an open organ tube , the open end FORMS anti-node and closed end forms node.

Let depth at which fundamental frequency happens be l , wavelength of STANDING WAVE be λ , depth of 2nd resonance be l2

For fundamental frequency , we can say that :

$\boxed{ \sf{ \huge{ \red{l = \dfrac{ \lambda}{4} }}}}$

For 2nd frequency , we can say that :

$\boxed{{ \sf{ \large{ \green{ \therefore l_{2} = \dfrac{ \lambda}{4} + \dfrac{ \lambda}{2} }}}}}$

${ \sf{ \large{ \green{ \therefore l_{2} = \dfrac{ 3\lambda}{4} }}}}$

So we can understand that

$\boxed{ \boxed{ \sf{l_{2} = 3 \times l}}}$

$\sf{ \implies \: l_{2} = 3 \times 20}$

$\sf{ \implies \: l_{2} = 60 \: cm}$

So final answer :

$\boxed{ \red{ \bold{ \sf{2nd \: resonance \: at \: 60 \: cm}}}}$

Discussion

40.	Any two types of robot with relevant example
Answer» Explanation: MATERIALS HANDLING Machine tending spot welding I have given you 1 more EX PLZ like me and follow me i will help you in solving your problems

40.

Any two types of robot with relevant example

Answer»

Explanation:

MATERIALS HANDLING
Machine tending
spot welding

I have given you 1 more EX

PLZ like me and follow me i will help you in solving your problems

Discussion

41.	What is the velocity of red and violet?
Answer» ANSWER: VELOCITY = WAVELENGTH×TIME velocity of red=700nm/sec violet=400nm/sec

41.

What is the velocity of red and violet?

Answer»

ANSWER:

VELOCITY = WAVELENGTH×TIME

velocity of red=700nm/sec

violet=400nm/sec

Discussion

42.	Uses of irregular reflection
Answer» Explanation: Benzoic acid is a white solid with the formula C₆H₅CO₂H. It is the simplest AROMATIC carboxylic acid. The name is derived from gum benzoin, which was for a long time its only source. Benzoic acid occurs naturally in many plants and serves as an intermediate in the BIOSYNTHESIS of many secondary metabolites. Wikipedia Formula: C7H6O2 Molar MASS: 122.12 g/mol Melting point: 122.3 °C Boiling point: 249.2 °C Density: 1.27 g/cm³ ChemSpider ID: 238............ I HOPE help you......... THANKS.......... okkkkkkkkkkkkkk....

42.

Uses of irregular reflection

Answer»

Explanation:

Benzoic acid is a white solid with the formula C₆H₅CO₂H. It is the simplest AROMATIC carboxylic acid. The name is derived from gum benzoin, which was for a long time its only source. Benzoic acid occurs naturally in many plants and serves as an intermediate in the BIOSYNTHESIS of many secondary metabolites. Wikipedia

Formula: C7H6O2

Molar MASS: 122.12 g/mol

Melting point: 122.3 °C

Boiling point: 249.2 °C

Density: 1.27 g/cm³

ChemSpider ID: 238............

I HOPE help you.........

THANKS..........

okkkkkkkkkkkkkk....

Discussion

43.	A compound microscope has lenses of focal length 1.0cm and 5.0cm. An object is placed 1.2cm from the objective lens. If a virtual image is formed 25cm from the eyepiece, calculate the distance between the two lenses.
Answer» ANSWER: 12.25 is CORRECT answer EXPLANATION: HOPE the answer will HELP you

43.

A compound microscope has lenses of focal length 1.0cm and 5.0cm. An object is placed 1.2cm from the objective lens. If a virtual image is formed 25cm from the eyepiece, calculate the distance between the two lenses.

Answer»

ANSWER:

12.25 is CORRECT answer

EXPLANATION:

HOPE the answer will HELP you

Discussion

44.	Difference between ferromagnetic ,diamagnetic and paramagnetic material.
Answer» The KEY DIFFERENCE between DIAMAGNETIC, paramagnetic and ferromagnetic materials is that diamagnetic materials are not attracted to an EXTERNAL magnetic field, and paramagnetic materials are attracted to an external magnetic field whereas ferromagnetic materials are strongly attracted to an external magnetic field.

Discussion

45.	The speed of sound in water is 1500 metre per second how for away from an under sea rock should a deep sea diver be so that he can hear his own Echo
Answer» Answer: The deep sea diver should be 75 meters to hear his own echo. Explanation: Where, 2D is the total DISTANCE, v is the sound's velocity in sea, and t is the time by the sound to travel the distance. To hear his own echo means the time is no longer than 0.1 SECOND and 1500 m/s is the sound's velocity. When a sound wave travel from surface to the bottom of the earth, the sound echo which means the sound travels the distance twice. Thus, the velocity and time of the sound is equal to twice the distance. To LEARN more: Sound waves are mechanical waves.explain the meaning of this statement. ALSO prove this with the help of a example. brainly.in/question/1217057 A SONAR echo takes 3 sec to return from a whale.How far away is the whale from SONAR?Speed of sound in sea water is 1440m/s

45.

The speed of sound in water is 1500 metre per second how for away from an under sea rock should a deep sea diver be so that he can hear his own Echo

Answer»

Answer:

The deep sea diver should be 75 meters to hear his own echo.

Explanation:

Where, 2D is the total DISTANCE, v is the sound's velocity in sea, and t is the time by the sound to travel the distance.

To hear his own echo means the time is no longer than 0.1 SECOND and 1500 m/s is the sound's velocity.

When a sound wave travel from surface to the bottom of the earth, the sound echo which means the sound travels the distance twice. Thus, the velocity and time of the sound is equal to twice the distance.

To LEARN more:

Sound waves are mechanical waves.explain the meaning of this statement. ALSO prove this with the help of a example.

brainly.in/question/1217057

A SONAR echo takes 3 sec to return from a whale.How far away is the whale from SONAR?Speed of sound in sea water is 1440m/s

Discussion

46.	A body is projected into air with velocity 20 m/s at an angle 60°. Find its position after 1 second
Answer» Answer: We will DIVIDE the Projectile MOTION into 2 simultaneously occuring 1D motions. ALONG X AXIS : $\sf{ \therefore \: x = u \cos( \theta) \times t}$ $\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}$ $\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}$ $\sf{ \implies \: x = 10 \: m}$ Along Y axis : $\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}$ $\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )$ $\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}$ $\sf{ \implies \: y =17.32 - 5}$ $\sf{ \implies \: y =12.32 \: m}$ So , coordinate will be : $\boxed{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}$

46.

A body is projected into air with velocity 20 m/s at an angle 60°. Find its position after 1 second

Answer»

Answer:

We will DIVIDE the Projectile MOTION into 2 simultaneously occuring 1D motions.

ALONG X AXIS :

$\sf{ \therefore \: x = u \cos( \theta) \times t}$

$\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}$

$\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}$

$\sf{ \implies \: x = 10 \: m}$

Along Y axis :

$\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}$

$\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )$

$\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}$

$\sf{ \implies \: y =17.32 - 5}$

$\sf{ \implies \: y =12.32 \: m}$

So , coordinate will be :

$\boxed{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}$

Discussion

47.	when ring starts swiveling on rough surface it's double time of radius is 70000mkg find out centripetal acc.ang.speed is 10 rotation per sec and mi is 1500 M L2 ??????
Answer» ANSWER: kzkxjxjx ksksk snnsjs iaisks kskkd sjjsjd

47.

when ring starts swiveling on rough surface it's double time of radius is 70000mkg find out centripetal acc.ang.speed is 10 rotation per sec and mi is 1500 M L2 ??????

Answer»

ANSWER:

kzkxjxjx

ksksk

snnsjs

iaisks

kskkd

sjjsjd

Discussion

48.	The main two constituents of air are
Answer» NITROGEN and oxygen are the TWO main CONSTITUENTS of air. Mark my answer as the BRAINIEST.

48.

The main two constituents of air are

Answer»

NITROGEN and oxygen are the TWO main CONSTITUENTS of air.

Mark my answer as the BRAINIEST.

Discussion

49.	the relative density of silver is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit.
Answer» Answer: $\huge \underline{ \rm \red{hello}}.$ Question:- the relative density of SILVER is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit. ____________________ Solution:- Given , the relative density of silver = 10.8. the density of water = 1.0 ×10³ kg m-³. To Find :- Density Of Silver We Know That , Relative density of a SUBSTANCE, $\sf{ \rm \red{ = \: \frac{density \: of \: substance}{density \: of \: water} }}$ Now , Putting the value of relative density of silver and density of water in the above formula : $\sf10.8 = \frac{ \sf{ \rm {density \: of \: silver}}}{1.0 \times {10}^{3} }$ So , density of silver = 10.8×1.0×10³ kg m-³ = 10.8 × 10³ kg m-³ Thus , The density of silver in SI Units is 10.8 × 10³ kg m-³. This can ALSO be written as 10800 kg m-³.

49.

the relative density of silver is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit.

Answer»

Answer:

$\huge \underline{ \rm \red{hello}}.$

Question:-

the relative density of SILVER is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit.

____________________

Solution:-

Given ,

the relative density of silver = 10.8.

the density of water = 1.0 ×10³ kg m-³.

To Find :-

Density Of Silver

We Know That ,

Relative density of a SUBSTANCE,

$\sf{ \rm \red{ = \: \frac{density \: of \: substance}{density \: of \: water} }}$

Now , Putting the value of relative density of silver and density of water in the above formula :

$\sf10.8 = \frac{ \sf{ \rm {density \: of \: silver}}}{1.0 \times {10}^{3} }$

So , density of silver = 10.8×1.0×10³ kg m-³

= 10.8 × 10³ kg m-³

Thus , The density of silver in SI Units is 10.8 × 10³ kg m-³.

This can ALSO be written as 10800 kg m-³.

Discussion

50.	Explain the magnetic indication
Answer» Answer: I THINK it's magnetic induction what u R TRYING to ask by the WAY it is the process by which a substance is magnetized using external magnetic field

50.

Explain the magnetic indication

Answer»

Answer:

I THINK it's magnetic induction what u R TRYING to ask

by the WAY it is the process by which a substance is magnetized using external magnetic field

Discussion

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