1.

an object of size density is placed at 30 cm in front of a concave mirror of focal length 20cm at what distance from the mirror should a screen be placed so that a sharp focus image can be obtained find the size of the nature of the image​

Answer»

ANSWER:

Given,

U = 30cm

f = 20cm

v = ?

in CASE of concave mirror,

FORMULA is

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

=} Here u need to take f and u negative

=} (-1)/20 = (-1)/30 + 1/v

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60)

=} (-1)/20 = (-1)/30 + 1/v=} 1/v = 1/30 - 1/20=} 1/v = (-1/60)=} v = 60cm

=} the distance from mirror to OBJECT is 60cm


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