A body is projected into air with velocity 20 m/s at an angle 60°. Fi

1.	A body is projected into air with velocity 20 m/s at an angle 60°. Find its position after 1 second
Answer» Answer: We will DIVIDE the Projectile MOTION into 2 simultaneously occuring 1D motions. ALONG X AXIS : $\sf{ \therefore \: x = u \cos( \theta) \times t}$ $\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}$ $\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}$ $\sf{ \implies \: x = 10 \: m}$ Along Y axis : $\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}$ $\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )$ $\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}$ $\sf{ \implies \: y =17.32 - 5}$ $\sf{ \implies \: y =12.32 \: m}$ So , coordinate will be : $\boxed{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}$