35. Derive an expression for the rise of liquid in a capillary tube an

1.	35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.
Answer» $\huge{\mathfrak{Bonjour!♡}}$ •°⭑ $\bullet{\underline{\sf{\color{lightpink}{Capillary\: Action:-}}}}$ ⭑The phenomenon of RISE and fall of liquid in a capillary tube is KNOWN as Capillary Action. $\bullet{\underline{\sf{\color{lightpink}{Concept:-}}}}$ ⭑It is experimentally found that PRESSURE below concave surface is less than 2T/R from pressure just above it. In order to compensate this pressure DIFFERENCE liquid RISES inside capillary tube. $\bullet{\underline{\sf{\color{lightpink}{Derivation:-}}}}$ According to concept; $\rightarrow{ \tt{\frac{2T}{R} = \rho gh}} \\ \\ \rightarrow \:{ \bf{ h = \frac{2T}{R \rho g}}} \: \: \: \: \: \: ...(1)$ $\boxed{ \sf{cos \theta = \frac{r}{R} \: \: \: r = radius \: of \: capillary \: tube}} \\$ $\rightarrow \: { \tt{R = \frac{r}{cos \theta} }} \: \: \: \: ...(2) \\ \\{ \sf{ putting \: eq(2) \: into \: \: eq(1)}} \\ \\ \leadsto{ \boxed{ \bf{h = \frac{2T}{r \rho g} cos \theta}}} \\$

35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.

Answer»

$\huge{\mathfrak{Bonjour!♡}}$ •°⭑

$\bullet{\underline{\sf{\color{lightpink}{Capillary\: Action:-}}}}$

⭑The phenomenon of RISE and fall of liquid in a capillary tube is KNOWN as Capillary Action.

$\bullet{\underline{\sf{\color{lightpink}{Concept:-}}}}$

⭑It is experimentally found that PRESSURE below concave surface is less than 2T/R from pressure just above it. In order to compensate this pressure DIFFERENCE liquid RISES inside capillary tube.

$\bullet{\underline{\sf{\color{lightpink}{Derivation:-}}}}$

According to concept;

$\rightarrow{ \tt{\frac{2T}{R} = \rho gh}} \\ \\ \rightarrow \:{ \bf{ h = \frac{2T}{R \rho g}}} \: \: \: \: \: \: ...(1)$

$\boxed{ \sf{cos \theta = \frac{r}{R} \: \: \: r = radius \: of \: capillary \: tube}} \\$

$\rightarrow \: { \tt{R = \frac{r}{cos \theta} }} \: \: \: \: ...(2) \\ \\{ \sf{ putting \: eq(2) \: into \: \: eq(1)}} \\ \\ \leadsto{ \boxed{ \bf{h = \frac{2T}{r \rho g} cos \theta}}} \\$

35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.

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35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.​

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35. Derive an expression for the rise of liquid in a capillary tube and show that the height of liquidcolumn supported is inversely proportional to the curvature of the tube.