67486 + Interview Questions in Secondary School in Physics

1.	Sound ka veg jyada water me hota h ya air me
Answer» Answer: AIR me because air have very SMALL PARTICALS to make faster the wave in air I hope it will HELP you..

1.

Sound ka veg jyada water me hota h ya air me

Answer»

Answer:

AIR me

because air have very SMALL PARTICALS to make faster the wave in air

I hope it will HELP you..

Discussion

2.	How can i understand SHM easily
Answer» Explanation: To *understand* *SHM* *better* *you* *should* *know* *the* *basic* *TRIGONOMETRY* *and* *graph* of *SIN* *and* *cos* *and* *about* *equation* . *And* *some* *term* *related* to *SHM* *like* *amplitude* , *FREQUENCY* , *TIME* *period* *etc. And* *This* *topic* is *COMPLEX* *topic* so go *through* *lecture* *deeply* *help* *you* *much* *better* in *solving* *the* *problem. Thank* *you*

2.

How can i understand SHM easily

Answer»

Explanation:

To understand SHM better you should know the basic TRIGONOMETRY and graph of SIN and cos and about equation .

And some term related to SHM like amplitude , FREQUENCY , TIME period etc.

And This topic is COMPLEX topic so go through lecture deeply help you much better in solving the problem.

Thank you

Discussion

3.	when will experience a greater pressure hundred to the surface of water or 200 CM below the surface of water justify your answer
Answer» ANSWER: EXPLANATION: Which GRADE are U in

3.

when will experience a greater pressure hundred to the surface of water or 200 CM below the surface of water justify your answer

Answer»

ANSWER:

EXPLANATION:

Which GRADE are U in

Discussion

4.	If the resultant of the forces has a magnitude smaller than the magnitude of larger force the two forces must be?
Answer» ANSWER: i THINK it MUST be UNBALANCED FORCE s

4.

If the resultant of the forces has a magnitude smaller than the magnitude of larger force the two forces must be?

Answer»

ANSWER:

i THINK it MUST be

UNBALANCED FORCE s

Discussion

5.	A ball dropped from a certain height is in a state of
Answer» ANSWER: EXPLANATION: MOTION

5.

A ball dropped from a certain height is in a state of

Answer»

ANSWER:

EXPLANATION:

MOTION

Discussion

6.	GiveDefinition for the static inertia
Answer» Explanation: Static INERTIA REFERS to the inertia of a BODY at rest . The inertia of a BOOK on the table is static inertia

6.

GiveDefinition for the static inertia

Answer»

Explanation:

Static INERTIA REFERS to the inertia of a BODY at rest . The inertia of a BOOK on the table is static inertia

Discussion

7.	A hole at the bottom of a ship is more dangerous than one near the surface
Answer» ANSWER: EXPLANATION: FALSE

7.

A hole at the bottom of a ship is more dangerous than one near the surface

Answer»

ANSWER:

EXPLANATION:

FALSE

Discussion

8.	Given that vector p+q+r=0./p/=3, /r/=5, /q/=4 what's the angle between vector p and r
Answer» Angle between P and Q is ∅ now, P + q = -R take magnitude p² + q² +2p.qcos∅ = r² P² +P² +2p.qcos∅= 2P² cos∅ = 0 ∅ =π/2 angle between q and r ∅' q + r = -P take magnitude q² + r² +2rpcos∅'=p² p² + 2p² +2.√2P.P cos∅' =P² cos∅' =-1/√2 ∅ = 3π/4 angle between r and P is ∅" P + r = -q take magnitude P²+ 2P² +2√2p²cos∅" = P² cos∅" =-1/√2 ∅" = 3π/4 hope it helps u MARK me as BRAINLIEST one

8.

Given that vector p+q+r=0./p/=3, /r/=5, /q/=4 what's the angle between vector p and r

Answer»

Angle between P and Q is ∅

now,

P + q = -R

take magnitude

p² + q² +2p.qcos∅ = r²

P² +P² +2p.qcos∅= 2P²

cos∅ = 0

∅ =π/2

angle between q and r ∅'

q + r = -P

take magnitude

q² + r² +2rpcos∅'=p²

p² + 2p² +2.√2P.P cos∅' =P²

cos∅' =-1/√2

∅ = 3π/4

angle between r and P is ∅"

P + r = -q

take magnitude

P²+ 2P² +2√2p²cos∅" = P²

cos∅" =-1/√2

∅" = 3π/4

hope it helps u MARK me as BRAINLIEST one

Discussion

9.	Solids, liquids, and gasses are called the three _________ of matter
Answer» solid, LIQUIDS and gases are called the THREE STATES of matter I hope this will HELP you!!

9.

Solids, liquids, and gasses are called the three _________ of matter

Answer»

solid, LIQUIDS and gases are called the THREE STATES of matter

I hope this will HELP you!!

Discussion

10.	√3 AxB=A-B, then find the angle between A and B
Answer» ANSWER: kgziydoysoysousofufgbb. G vhbng.fdshsGzgGYYYYYTYTFGTF

10.

√3 AxB=A-B, then find the angle between A and B

Answer»

ANSWER:

kgziydoysoysousofufgbb. G vhbng.fdshsGzgGYYYYYTYTFGTF

Discussion

11.	a bus covers half distance at speed V and remaining half distance at speed V1 for 1/3 time and V2 for 2/3 time .Find average speed?
Answer» ANSWER: i HOPE it Hepls You Explanation: xxxxxxxxxxxxxxxxxxxxx

11.

a bus covers half distance at speed V and remaining half distance at speed V1 for 1/3 time and V2 for 2/3 time .Find average speed?

Answer»

ANSWER:

i HOPE it Hepls You

Explanation:

xxxxxxxxxxxxxxxxxxxxx

Discussion

12.	Difference between weigh and up thrust
Answer» ANSWER: Upthrust-The net upward force exerted by a body to an object IMMERSED PARTIALLY or COMPLETELY in it,is called its Upthrust. Weight- The quantity of the matter contained by a body is called Weight.

12.

Difference between weigh and up thrust

Answer»

ANSWER:

Upthrust-The net upward force exerted by a body to an object IMMERSED PARTIALLY or COMPLETELY in it,is called its Upthrust. Weight- The quantity of the matter contained by a body is called Weight.

Discussion

13.	What is parallatic angle
Answer» Answer: The parallactic angle is the angle between the great CIRCLE through a CELESTIAL object and the zenith, and the HOUR circle of the object.

13.

What is parallatic angle

Answer»

Answer:

The parallactic angle is the angle between the great CIRCLE through a CELESTIAL object and the zenith, and the HOUR circle of the object.

Discussion

14.	G ka manBtaiye capital gains ka
Answer» Explanation: 6.67 into 10 to the POWER MINUS 11

14.

G ka manBtaiye capital gains ka

Answer»

Explanation:

6.67 into 10 to the POWER MINUS 11

Discussion

15.	a body of mass 5 kg displaces 1000 sqcm of water when fully immersed in water. find the volume of the object
Answer» ANSWER: VOLUME is looocm3. This is ANS

15.

a body of mass 5 kg displaces 1000 sqcm of water when fully immersed in water. find the volume of the object

Answer»

ANSWER:

VOLUME is looocm3. This is ANS

Discussion

16.	State any two observation from everyday life which show that light travels in straight line
Answer» Answer: torch LIGHT when TRIED to pass through a HOLE will always show the same area as the area of hole Explanation:

16.

State any two observation from everyday life which show that light travels in straight line

Answer»

Answer:

torch LIGHT when TRIED to pass through a HOLE will always show the same area as the area of hole

Explanation:

Discussion

17.	The radius of sphere is (4.3±0.1)cm the % error in its volume is
Answer» ANSWER: here is UR answer.... HOPE it will HELP U

17.

The radius of sphere is (4.3±0.1)cm the % error in its volume is

Answer»

ANSWER:

here is UR answer....

HOPE it will HELP U

Discussion

18.	À particle is moving in a circle of diameter 10m .The distance covered by it on completing 2 revolutions is
Answer» ANSWER: 62.8m is the CORRECT answer

18.

À particle is moving in a circle of diameter 10m .The distance covered by it on completing 2 revolutions is

Answer»

ANSWER:

62.8m is the CORRECT answer

Discussion

19.	Dimensional formula of magnetic strength
Answer» Answer: F = (v×q)×B F = MLT^-2 V = LT^-1 Q = AT so B = (MLT^-2)/(LT^-1)(AT) B = ML^0T^-2A-1 . . .. press the 5 STARS if it HELPS u

19.

Dimensional formula of magnetic strength

Answer»

Answer:

F = (v×q)×B

F = MLT^-2

V = LT^-1

Q = AT

so

B = (MLT^-2)/(LT^-1)(AT)

B = ML^0T^-2A-1

.

..

press the 5 STARS if it HELPS u

Discussion

20.	A ball of mass m strikes the bat with a speed v and goes back in the opposite direction with speed 2v. If ball was in contact for t time, then force applied by the bat is
Answer» Answer: -3mv/t Explanation: F = Change in momentum / Total time = MASS × (final velocity - INITIAL velocity) / time = m × (-2v - v)/t = -3mv/t

20.

A ball of mass m strikes the bat with a speed v and goes back in the opposite direction with speed 2v. If ball was in contact for t time, then force applied by the bat is

Answer»

Answer:

-3mv/t

Explanation:

F = Change in momentum / Total time

= MASS × (final velocity - INITIAL velocity) / time

= m × (-2v - v)/t

= -3mv/t

Discussion

21.	If force is directly proportional to mass then why F=ma
Answer» Answer: HEY dear.... force is directly PROPORTIONAL to both mass and acceleration... from that... this equation COMES out...

21.

If force is directly proportional to mass then why F=ma

Answer»

Answer:

HEY dear.... force is directly PROPORTIONAL to both mass and acceleration... from that... this equation COMES out...

Discussion

22.	2. Write symbols of the followingelements and the radicals obtainedfrom them, and indicate the chargeon the radicals.Mercury, potassium, nitrogen, copper,sulphur, carbon, chlorine, oxygenplz answer atleast one for me
Answer» Answer: hg , K , N ,CU,s ,C ,CL ,O...........

22.

2. Write symbols of the followingelements and the radicals obtainedfrom them, and indicate the chargeon the radicals.Mercury, potassium, nitrogen, copper,sulphur, carbon, chlorine, oxygenplz answer atleast one for me

Answer»

Answer:

hg , K , N ,CU,s ,C ,CL ,O...........

Discussion

23.	Explain the meaning of the following equation p=m×v where symbol have their usual meaning
Answer» <P> Explanation: the equation is, p = mv in which, p = linear momentum m = mass v = velocity so we can say that, the linear momentum of any body is equal to the product of mass and velocity of that body. In other words, if velocity or mass of the body increases then the linear momentum of the body will also be increase..... So, linear momentum DIRECTLY depends upon mass and velocity. linear momentum is a vector QUANTITY because mass is SCALAR quantity but velocity is vector.So overall it is a vector quantity.

23.

Explain the meaning of the following equation p=m×v where symbol have their usual meaning

Answer»

<P>

Explanation:

the equation is, p = mv

in which, p = linear momentum

m = mass

v = velocity

so we can say that,

the linear momentum of any body is equal to the product of mass and velocity of that body.

In other words,

if velocity or mass of the body increases then the linear momentum of the body will also be increase.....

So, linear momentum DIRECTLY depends upon mass and velocity.

linear momentum is a vector QUANTITY because mass is SCALAR quantity but velocity is vector.So overall it is a vector quantity.

Discussion

24.	Force will only be produced when______
Answer» EXPLANATION: when ENERGY is APPLIED

24.

Force will only be produced when______

Answer»

EXPLANATION:

when ENERGY is APPLIED

Discussion

25.	How simple pendulum can be made
Answer» ANSWER: take a one thread tie it with the metal BOB now it should be FREE to oscillate

25.

How simple pendulum can be made

Answer»

ANSWER:

take a one thread tie it with the metal BOB now it should be FREE to oscillate

Discussion

26.	an athlete covers one round of a circular track in 50s. After 3min50s what will be the displacement of the athlete if the radius of the ground is 70 m .( physics)
Answer» ANSWER: 264 m is the answer...........

26.

an athlete covers one round of a circular track in 50s. After 3min50s what will be the displacement of the athlete if the radius of the ground is 70 m .( physics)

Answer»

ANSWER:

264 m is the answer...........

Discussion

27.	Please answer this 2d physics question
Answer» ANSWER: Which send PICTURE or type it. Then I WOULD be ABLE to HELP you out.

27.

Please answer this 2d physics question

Answer»

ANSWER:

Which send PICTURE or type it. Then I WOULD be ABLE to HELP you out.

Discussion

28.	How do you increase the pressure by keeping area unchanged and force unchanged?
Answer» ANSWER: PRESSURE is the ratio of force DIVIDED by area precisely the force counted is perpendicular to the area of CONSIDERATION and not at any angle other than 90˚.

28.

How do you increase the pressure by keeping area unchanged and force unchanged?

Answer»

ANSWER:

PRESSURE is the ratio of force DIVIDED by area precisely the force counted is perpendicular to the area of CONSIDERATION and not at any angle other than 90˚.

Discussion

29.	A book rest on the table . What is the frictional force acting on it
Answer» Answer: The frictional FORCE is *STATIC* *force..... Mark* *my answer* *as BRAINLIST*

29.

A book rest on the table . What is the frictional force acting on it

Answer»

Answer:

The frictional FORCE is STATIC force.....

Mark my answer as BRAINLIST

Discussion

30.	X=a⁴b³/c⅓d½ percentage error
Answer» PERCENTAGE ERROR =RELATIVE error *100

30.

X=a⁴b³/c⅓d½ percentage error

Answer»

PERCENTAGE ERROR =RELATIVE error *100

Discussion

31.	If an electron moves from left to right in a conductor,what will be the direction of magnetic field lines around the conductor?Mention the name of the rule
Answer» ANSWER: The direction of the induced magnetic field is SOMETIMES REMEMBERED by Maxwell's corkscrew RULE. That is, if the conventional current is flowing away from the VIEWER, the magnetic field runs clockwise round the conductor, in the same direction that a corkscrew would have to turn in order to move away from the viewer.

31.

If an electron moves from left to right in a conductor,what will be the direction of magnetic field lines around the conductor?Mention the name of the rule

Answer»

ANSWER:

The direction of the induced magnetic field is SOMETIMES REMEMBERED by Maxwell's corkscrew RULE. That is, if the conventional current is flowing away from the VIEWER, the magnetic field runs clockwise round the conductor, in the same direction that a corkscrew would have to turn in order to move away from the viewer.

Discussion

32.	Why does the appear blue in colour?and it sometimes change its colour?
Answer» ANSWER: WATER I THINK it so BROTHER

32.

Why does the appear blue in colour?and it sometimes change its colour?

Answer»

ANSWER:

WATER I THINK it so BROTHER

Discussion

33.	Temperature is the average .......................of the molecule s of a substance
Answer» ANSWER: $front color=$ $\huge\bold\{boxed{thanks}$ temperature is the average SPEED of the MOSKAL of the SUBSTANCE

33.

Temperature is the average .......................of the molecule s of a substance

Answer»

ANSWER:

$front color=$

$\huge\bold\{boxed{thanks}$ temperature is the average SPEED of the MOSKAL of the SUBSTANCE

Discussion

34.	A man is hanging from the free end of a massless rope of length 40 m. The mass of the man is 20 ka and the maximum tension that the rope can bear in 300 N. Then starting from rest, the minimum time in which man can reach the other end of the rope is (g 10 m/s2)
Answer» PLS PUT FULL QUESTION so that we can ANSWER it

Discussion

35.	find the free fall acceleration of an object on the surface of the Moon if the radius of the moon and its mass are 1740 kilometres and 77.4 into 10 ^ 22 kg respectively compare this value with three for acceleration of a body on the surface of the earth
Answer» Explanation: Acceleration due to GRAVITY is given by a = GM / R² where G = Universal gravitation constant M = Mass of planet (or moon) R = Radius of planet (or moon) For moon a = (6.674 × 10^-11 × 7.4 × 10^22)/(1740 × 10^3)^2 = 1.6 m/s² Free fall acceleration of any body on moon is 1.6 m/s² Comparison with Earth Acceleration due to gravity of Earth = 9.8 m/s² Earth / Moon = (9.8 m/s²) / (1.6 m/s²) = 6.125 Earth = 6.125 × Moon Note: I've used the CORRECT value of mass of earth's moon i.e 7.4 × 10²² KG, not 77.4 × 10²² kg

35.

find the free fall acceleration of an object on the surface of the Moon if the radius of the moon and its mass are 1740 kilometres and 77.4 into 10 ^ 22 kg respectively compare this value with three for acceleration of a body on the surface of the earth

Answer»

Explanation:

Acceleration due to GRAVITY is given by

a = GM / R²

where

G = Universal gravitation constant

M = Mass of planet (or moon)

R = Radius of planet (or moon)

For moon

a = (6.674 × 10^-11 × 7.4 × 10^22)/(1740 × 10^3)^2

= 1.6 m/s²

Free fall acceleration of any body on moon is 1.6 m/s²

Comparison with Earth

Acceleration due to gravity of Earth = 9.8 m/s²

Earth / Moon = (9.8 m/s²) / (1.6 m/s²) = 6.125

Earth = 6.125 × Moon

Note: I've used the CORRECT value of mass of earth's moon i.e 7.4 × 10²² KG, not 77.4 × 10²² kg

Discussion

36.	Work is a scalar quantity or vector quantity
Answer» ANSWER scalar........ because it has no DIRECTION LIKE force and velocity........

36.

Work is a scalar quantity or vector quantity

Answer»

ANSWER scalar........

because it has no DIRECTION LIKE force and velocity........

Discussion

37.	The position x of a particle moving in a straight line varies with time t as x=(t+3)^-1. The acceleration of particle is proportional to
Answer» Answer: Option (1) $(\text{velocity})^{3/2}$ Explanation: GIVEN, the position x VARIES with time t as $x=(t+3)^{-1}$ or, $x=\frac{1}{x+3}$ We KNOW that rate of CHANGE of displacement is velocity i.e. $v=\frac{dx}{dt}$ or, $v=\frac{d}{dt}(t+3)^{-1}$ or, $v=-(t+3)^{-2}$ Also, the rate of change of velocity is accelration i.e. $a=\frac{dv}{dt}$ or, $a=\frac{d}{dt}[-(t+3)^{-2}]$ $\implies a=2(t+3)^{-3}$ $\implies a=2[(t+3)^{-2}]^{3/2}$ $\implies a=2[-v]^{3/2}$ $\implies a=-2v^{3/2}$ Thus, $a \propto v^{3/2}$ or, $\text{acceleration}\propto (\text{velocity})^{3/2}$

37.

The position x of a particle moving in a straight line varies with time t as x=(t+3)^-1. The acceleration of particle is proportional to

Answer»

Answer:

Option (1) $(\text{velocity})^{3/2}$

Explanation:

GIVEN, the position x VARIES with time t as

$x=(t+3)^{-1}$

or, $x=\frac{1}{x+3}$

We KNOW that rate of CHANGE of displacement is velocity

i.e. $v=\frac{dx}{dt}$

or, $v=\frac{d}{dt}(t+3)^{-1}$

or, $v=-(t+3)^{-2}$

Also, the rate of change of velocity is accelration

i.e. $a=\frac{dv}{dt}$

or, $a=\frac{d}{dt}[-(t+3)^{-2}]$

$\implies a=2(t+3)^{-3}$

$\implies a=2[(t+3)^{-2}]^{3/2}$

$\implies a=2[-v]^{3/2}$

$\implies a=-2v^{3/2}$

Thus, $a \propto v^{3/2}$

or, $\text{acceleration}\propto (\text{velocity})^{3/2}$

Discussion

38.	A truck of mass 1000kg increases its speed from 36kmh to 72 kmh .Find increase in its kinetic energy.
Answer» ANSWER: kinetic energy INCREASE 4 TIME

38.

A truck of mass 1000kg increases its speed from 36kmh to 72 kmh .Find increase in its kinetic energy.

Answer»

ANSWER:

kinetic energy INCREASE 4 TIME

Discussion

39.	A,B,C initially placed at vertices of an equilateral triangle.A moves towards B,B moves towards C and C moves towards A.Cal the velocity at the time of collision.
Answer» ANSWER: SORRY I CANT answer UR QUETION

39.

A,B,C initially placed at vertices of an equilateral triangle.A moves towards B,B moves towards C and C moves towards A.Cal the velocity at the time of collision.

Answer»

ANSWER:

SORRY I CANT answer UR QUETION

Discussion

40.	. A particle is projected with a velocityV = (3ỉ - j+ 2k) m/s and a constant accelerationacting on the particle is a =(-6î +2j - 4k) m/s.?Then the path of projectile is(1) Straight line (2) Circle(3) Parabola(4) Ellipse
Answer» ANSWER: STRAIGHT LINE (2)CIRCLE

40.

. A particle is projected with a velocityV = (3ỉ - j+ 2k) m/s and a constant accelerationacting on the particle is a =(-6î +2j - 4k) m/s.?Then the path of projectile is(1) Straight line (2) Circle(3) Parabola(4) Ellipse

Answer»

ANSWER:

STRAIGHT LINE (2)CIRCLE

Discussion

41.	Newton's universal law of gravitation is expressed asF=G×m1m2÷r2
Answer» Answer: G is the local acceleration due to gravity between 2 objects. ... You get this value from the LAW of Universal Gravitation. Force = ma = G(Mm)/R^2. Here you use the radius of the earth for r, the distance to sea level from the CENTER of the earth, and M is the mass of the earth.

41.

Newton's universal law of gravitation is expressed asF=G×m1m2÷r2

Answer»

Answer:

G is the local acceleration due to gravity between 2 objects. ... You get this value from the LAW of Universal Gravitation. Force = m*a = G(M*m)/R^2. Here you use the radius of the earth for r, the distance to sea level from the CENTER of the earth, and M is the mass of the earth.

Discussion

42.	Which supply are we using in railways and what is the operating voltage?
Answer» ANSWER: ELECTRIC traction VOLTAGES voltages are used in 1.5kV DC and 25KV for AC mainline trains.

42.

Which supply are we using in railways and what is the operating voltage?

Answer»

ANSWER:

ELECTRIC traction VOLTAGES

voltages are used in 1.5kV DC and 25KV for AC mainline trains.

Discussion

43.	A car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph. If g=10ms, the power of its engine is
Answer» Answer: The POWER of the engine is 4 KW Explanation: According to the problem the weight of the car is 1000kg and the slope is 2 in 25 it means it will go 2 meter towards head and then it will cover the HYPOTENUSES 25 m Now the sinθ = 2/25 Now the speed is 18 km /hr Now we NEED to find the power, As we know the power is = work done/time = force x displacement/ time Now displacement/ time = velocity Therefore Power = force x velocity Now as the car is in the slope the therefore it has two components of force : mg ad mgsinθ Therefore, Power = mgsinθ x v = 1000 x 10 x 2/25 x 18 x 1000/3600 = 4000 Watt or 4 KW

43.

A car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph. If g=10ms, the power of its engine is

Answer»

Answer:

The POWER of the engine is 4 KW

Explanation:

According to the problem the weight of the car is 1000kg

and the slope is 2 in 25

it means it will go 2 meter towards head and then it will cover the HYPOTENUSES 25 m

Now the sinθ = 2/25

Now the speed is 18 km /hr

Now we NEED to find the power,

As we know the power is = work done/time = force x displacement/ time

Now displacement/ time = velocity

Therefore Power = force x velocity

Now as the car is in the slope the therefore it has two components of force : mg ad mgsinθ

Therefore, Power = mgsinθ x v

= 1000 x 10 x 2/25 x 18 x 1000/3600

= 4000 Watt or 4 KW

Discussion

44.	A body of mass 60kg is moving with a speed 50m /s . Find its kinetic energy
Answer» EXPLANATION: KE =1/2 * mv^2 =0.560*50^2 = 75000 joules = 75 KJ

44.

A body of mass 60kg is moving with a speed 50m /s . Find its kinetic energy

Answer»

EXPLANATION:

KE =1/2 * m*v^2

=0.5*60*50^2 = 75000 joules

= 75 KJ

Discussion

45.	If an object has a greater speed, does it necessarily have a greater acceleration?
Answer» ANSWER: No the VELOCITY or speed COULD constant so it is not NECESSARY that it is accelerating

45.

If an object has a greater speed, does it necessarily have a greater acceleration?

Answer»

ANSWER:

No the VELOCITY or speed COULD constant so it is not NECESSARY that it is accelerating

Discussion

46.	D-dx ethe power x the power 2
Answer» Explanation: Now to find the DERIVATIVE of the general exponential FUNCTION f(X) = ax. We begin with the DIFFERENCE quotient, as usual. In the third step, we apply the product property of EXPONENTS.

46.

D-dx ethe power x the power 2

Answer»

Explanation:

Now to find the DERIVATIVE of the general exponential FUNCTION f(X) = ax. We begin with the DIFFERENCE quotient, as usual. In the third step, we apply the product property of EXPONENTS.

Discussion

47.	If the radius of earth is R then height H at which value of g become one- fourth is
Answer» Answer: g = $\frac{GM}{R^{2} }$ at some height H let the acceleration DUE to GRAVITY be g' g' = $\frac{GM}{(R+H)^{2} }$ but g' = g/4 solving for H, $\frac{g}{4} = g'\\ \\\frac{GM}{4R^2} = \frac{GM}{(R+H)^2} \\R+H = 2R \\\\H = R \\\\$ The g becomes one-fourth at a height H = R (radius of earth) from the earths SURFACE

47.

If the radius of earth is R then height H at which value of g become one- fourth is

Answer»

Answer:

g = $\frac{GM}{R^{2} }$

at some height H let the acceleration DUE to GRAVITY be g'

g' = $\frac{GM}{(R+H)^{2} }$

but g' = g/4

solving for H,

$\frac{g}{4} = g'\\ \\\frac{GM}{4R^2} = \frac{GM}{(R+H)^2} \\R+H = 2R \\\\H = R \\\\$

The g becomes one-fourth at a height H = R (radius of earth) from the earths SURFACE

Discussion

48.	» Only moods answer it A truck of mass 1000 kg is pulling a trailer of mass 2000kg as shown the retarding force on the truck is 580 N. And that on the trailer is 1000 N, the truck engine exert a force of 6000 N.(i) Calculate the acceleration of the truck and trailer .(ii) The tension in connecting rope.
Answer» $\huge{\mathfrak{\underline{\underline{Correct\:\:Question}}}}$ A truck of mass 1000 kg is pulling a TRAILER of mass 2000kg as shown the retarding force on the truck is 500 N. And that on the trailer is 1000 N, the truck engine EXERT a force of 6000 N. (i) Calculate the acceleration of the truck and trailer . (ii) The TENSION in connecting rope. $\huge{\underline{\mathfrak{Answer:}}}$ $\rule{200}{2}$ Let a be the acceleration of the truck and the trailer. (1) 6000 - (500 + 1000) » (1000 + 2000)a » THEREFORE, a = 4500/3000 » 1.5 ms-² ............[Answer] (2) Let T be the tension in the connected rope. T = 2000a + 1000 » 3000 + 1000 » 4000 N ...........[Answer] $\rule{200}{2}$

48.

» Only moods answer it A truck of mass 1000 kg is pulling a trailer of mass 2000kg as shown the retarding force on the truck is 580 N. And that on the trailer is 1000 N, the truck engine exert a force of 6000 N.(i) Calculate the acceleration of the truck and trailer .(ii) The tension in connecting rope.

Answer»

$\huge{\mathfrak{\underline{\underline{Correct\:\:Question}}}}$

A truck of mass 1000 kg is pulling a TRAILER of mass 2000kg as shown the retarding force on the truck is 500 N. And that on the trailer is 1000 N, the truck engine EXERT a force of 6000 N.

(i) Calculate the acceleration of the truck and trailer .

(ii) The TENSION in connecting rope.

$\huge{\underline{\mathfrak{Answer:}}}$

$\rule{200}{2}$

Let a be the acceleration of the truck and the trailer.

(1) 6000 - (500 + 1000)

» (1000 + 2000)a

» THEREFORE, a = 4500/3000

» 1.5 ms-² ............[Answer]

(2) Let T be the tension in the connected rope.

T = 2000a + 1000

» 3000 + 1000

» 4000 N ...........[Answer]

$\rule{200}{2}$

Discussion

49.	If+a+constant+force+acts+on+a+body+initially+kept+at+rest,+the+distance+moved+by+the+body+in+time't'+is+proportional+to
Answer» ANSWER: your mind Explanation: APNA DIMAAG lagao beta please tabhi SAFAL HO payoge

49.

If+a+constant+force+acts+on+a+body+initially+kept+at+rest,+the+distance+moved+by+the+body+in+time't'+is+proportional+to

Answer»

ANSWER:

your mind

Explanation:

APNA DIMAAG lagao beta

please

tabhi SAFAL HO payoge

Discussion

50.	A body of mass 5kg initially arrest is moved by horizontal force of 2newton on a smooth horizontal surface. The work done by the force in 10seconds is
Answer» ANSWER: HOPE this will HELP you.

50.

A body of mass 5kg initially arrest is moved by horizontal force of 2newton on a smooth horizontal surface. The work done by the force in 10seconds is

Answer»

ANSWER:

HOPE this will HELP you.

Discussion

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