find the free fall acceleration of an object on the surface of the Moo

1.	find the free fall acceleration of an object on the surface of the Moon if the radius of the moon and its mass are 1740 kilometres and 77.4 into 10 ^ 22 kg respectively compare this value with three for acceleration of a body on the surface of the earth
Answer» Explanation: Acceleration due to GRAVITY is given by a = GM / R² where G = Universal gravitation constant M = Mass of planet (or moon) R = Radius of planet (or moon) For moon a = (6.674 × 10^-11 × 7.4 × 10^22)/(1740 × 10^3)^2 = 1.6 m/s² Free fall acceleration of any body on moon is 1.6 m/s² Comparison with Earth Acceleration due to gravity of Earth = 9.8 m/s² Earth / Moon = (9.8 m/s²) / (1.6 m/s²) = 6.125 Earth = 6.125 × Moon Note: I've used the CORRECT value of mass of earth's moon i.e 7.4 × 10²² KG, not 77.4 × 10²² kg

find the free fall acceleration of an object on the surface of the Moon if the radius of the moon and its mass are 1740 kilometres and 77.4 into 10 ^ 22 kg respectively compare this value with three for acceleration of a body on the surface of the earth

Answer»

Explanation:

Acceleration due to GRAVITY is given by

a = GM / R²

where

G = Universal gravitation constant

M = Mass of planet (or moon)

R = Radius of planet (or moon)

For moon

a = (6.674 × 10^-11 × 7.4 × 10^22)/(1740 × 10^3)^2

= 1.6 m/s²

Free fall acceleration of any body on moon is 1.6 m/s²

Comparison with Earth

Acceleration due to gravity of Earth = 9.8 m/s²

Earth / Moon = (9.8 m/s²) / (1.6 m/s²) = 6.125

Earth = 6.125 × Moon

Note: I've used the CORRECT value of mass of earth's moon i.e 7.4 × 10²² KG, not 77.4 × 10²² kg

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