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Given that vector p+q+r=0./p/=3, /r/=5, /q/=4 what's the angle between vector p and r |
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Answer»
Angle between P and Q is ∅ now, P + q = -R take magnitude p² + q² +2p.qcos∅ = r² P² +P² +2p.qcos∅= 2P² cos∅ = 0 ∅ =π/2 angle between q and r ∅' q + r = -P take magnitude q² + r² +2rpcos∅'=p² p² + 2p² +2.√2P.P cos∅' =P² cos∅' =-1/√2 ∅ = 3π/4 angle between r and P is ∅" P + r = -q take magnitude P²+ 2P² +2√2p²cos∅" = P² cos∅" =-1/√2 ∅" = 3π/4 hope it helps u MARK me as BRAINLIEST one |
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