A car weighing 1000kg is going up an incline with a slope of 2 in 25 a

1.	A car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph. If g=10ms, the power of its engine is
Answer» Answer: The POWER of the engine is 4 KW Explanation: According to the problem the weight of the car is 1000kg and the slope is 2 in 25 it means it will go 2 meter towards head and then it will cover the HYPOTENUSES 25 m Now the sinθ = 2/25 Now the speed is 18 km /hr Now we NEED to find the power, As we know the power is = work done/time = force x displacement/ time Now displacement/ time = velocity Therefore Power = force x velocity Now as the car is in the slope the therefore it has two components of force : mg ad mgsinθ Therefore, Power = mgsinθ x v = 1000 x 10 x 2/25 x 18 x 1000/3600 = 4000 Watt or 4 KW

A car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph. If g=10ms, the power of its engine is

Answer»

Answer:

The POWER of the engine is 4 KW

Explanation:

According to the problem the weight of the car is 1000kg

and the slope is 2 in 25

it means it will go 2 meter towards head and then it will cover the HYPOTENUSES 25 m

Now the sinθ = 2/25

Now the speed is 18 km /hr

Now we NEED to find the power,

As we know the power is = work done/time = force x displacement/ time

Now displacement/ time = velocity

Therefore Power = force x velocity

Now as the car is in the slope the therefore it has two components of force : mg ad mgsinθ

Therefore, Power = mgsinθ x v

= 1000 x 10 x 2/25 x 18 x 1000/3600

= 4000 Watt or 4 KW

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