This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Difference 5mass and wieght |
|
Answer» Explanation: There is a basic DIFFERENCE, because mass is the ACTUAL amount of material contained in a body and is measured in kg, gm, etc. Whereas weight is the force EXERTED by the gravity on that object mg. NOTE that mass is independent of EVERYTHING but weight is different on the earth, moon, etc. |
|
| 2. |
Calculate the wavelength associated with 1) 1mev electron 2) 1mev proton |
|
Answer» Answer: W of electron = 5.76 ×10^-23 W of proton = 1.04× 10^-23 Explanation:it will depend on both proton and electron MASS as W=h/(2ME)^1/2 E=energy in EV E=1mev= 10^6ev Now, Mass of proton = 1.6 ×10^-27kg Mass of electron = 9.01 × 10^-31kg W(electron)= 6.65 ×10^-34÷(2×9.01×10^-31×10^6)^1/2 =5.76×10^-23 W(proton)= 6.65×10^-34÷(2×1.6×10^-27×10^6)^1/2 =1.04×10^-23 I hope that this is the answer If i am wrong then please LET me know. |
|
| 3. |
1. Two vectors their magnitude are to unit. Angle between them is60°. Find the value of Resultant ? |
| Answer» | |
| 4. |
Calculate the wavelength associated with 1 mev electron |
|
Answer» F=frequency (in per second) W= wavelength(in metre) E=energy(in joule) C= velocity of LIGHT(3×10^8m/s) h=planks constant(6.65×10^-34) E=hF F=C/W E=hC/W we have to find W E=1Mev= 1.6×10^-19 ×10^6 E=1.6×10^-13 (1EV= 1.6×10-19 Joule 1M=10^6 Joule) Now, hC=6.65×10^-34×3×10^8 hC= 2×10^-25 W=hC/E W=2×10^-25÷1.6×10^-13 W=20 ×10^-12÷16 W=1.25×10^-12metre I hope this is the answer if I am wrong then please LET me know
|
|
| 6. |
Dimension of the density |
|
Answer» Answer: DENSITY is measured in KILOGRAM per cubic metres (kg/m^3). In order to change a unit into DIMENSION, mass in kg, is represented by M, length in metres, by L and time in seconds by |
|
| 7. |
2. If A = (10.0 +-0.1) and B = (5.0 +- 0.1), then2A - B is equal to(1) (15.0 + 0.3) (2) (15.0 + 0.1)(3) (10.0 + 0.3) (4) (20.0 + 0.3) |
|
Answer» ANSWER:as A=(10.0+-0.1),then 2A=(20.0+-0.2) B=(5.0+-0.1) 2A-B= (20.0-5.0)+-(0.2-0.1) =15.0+-0.1 Explanation: |
|
| 8. |
an object starting from rest travels with an acceleration of 5m/s^. what will be its velocity after 3m/s |
|
Answer» Explanation: 2ms |
|
| 9. |
Distinguish between Ohmic and non-ohmic substances; explain with the helpof example.DC current flows in a metal piece of non-uniform cross-section. Which of thesequantities remains constant along theconductor: current, current density ordrift speed?219 |
|
Answer» The MAIN difference between an OHMIC and a non-Ohmic conductor is whether they follow Ohm's law. An Ohmic conductor would have a linear relationship between the current and the voltage. With non-Ohmic CONDUCTORS, the relationship is not linear. A GOOD example of an Ohmic conductor is the resisto |
|
| 10. |
Plz answer this blink service dgke |
|
Answer» hey this is the que of METAL and NON metal i STUDY same chapter |
|
| 11. |
when the current flowing through a straight conductor is increased, what happen to the strength of its magnetic field? |
Answer» ★ Answer:→ The STRENGTH of magnetic FIELD ALSO increases. #ThankYuH..@JoY..❤️ |
|
| 12. |
A person suffering from myopia can see clearly upto 2.0 meter. Which kind of lens if necessary for clear vision and also find focal length and power of lens. |
| Answer» | |
| 13. |
what will happen if a bar magnet is broken into two pieces and if each piece is further broken into two pieces? |
Answer» ★ Answer:→ If bar magnet is broken into two PIECES, then each PART will behave as a complete magnet with two poles [N and S]. If each piece is for the broken into two pieces, then each please will behave as a complete magnet with two poles. #ThankYuH..@JoY..❤️ |
|
| 14. |
What happens when a hollow and a solid is heated at same temperature |
| Answer» | |
| 15. |
An object is moving with speed 10 m/s along thedirection of a vector 4i’ - 3j’. Velocity of the object(1) 8i’ - 6j’ m/s(2) 10i’ - 10j’ m/s(3) 40i’ -30j’ m/s(4) 6i’ – 8j’ m/s. ( ’ )means cap |
|
Answer» Dear Student, ◆ Answer - (1) Velocity = 8I’ - 6j’ m/s ● Explanation - # Given - Speed = 10 m/s Direction = 4i’ - 3j’ # Solution - UNIT vector ALONG 4i’ - 3j’ is - Unit vector = (4i’ - 3j’) / √(4^2 + 3^2) Unit vector = (4i’-3j’)/5 Velocity of the OBJECT is given by - Velocity = speed × unit vector Velocity = 10 × (4i’-3j’)/5 Velocity = 8i’ - 6j’ m/s Therefore, velocity of object is 8i’-6j’ m/s. Hope that helps you... |
|
| 16. |
Plzzz plzzz solve fastlyyyy will mark as the brainliest one |
|
Answer» Answer: When a BULLET is fired from a GUN, the gun EXERTS a force on the bullet in the forward DIRECTION. This is the action force. The bullet also exerts an equal force on the gun in the backward direction. This is the reaction force.Hope it will help you dear friend and KINDLY mark my answer as brainliest.... |
|
| 17. |
A 200 train moving at 11 m|s crosses a man running on the platform along the same direction in 20s then speed of the man is |
|
Answer» then SECOND number |
|
| 18. |
Plzz answer fast will mark as brainliest |
|
Answer» SORRY I can't UNDERSTAND your QUESTION |
|
| 19. |
If momentum is increased by 20%,the 9ncrease on kinetic energy will be |
|
Answer» here MOMENTUM is directly proportional to kinetic ENERGY . k=mv^2 /2 thus the % increase will be same therefore % increase in kinetic energy will be 20% |
|
| 20. |
28 = Root of 9x² +25x² +15x^2 |
|
Answer» x=-0.755 Explanation: 49X^2 = 28 X=-0.755 |
|
| 22. |
Why is an ammeter placed in series of conductor or resistor in a circuit? |
Answer» ★ Answer:→ An ammeter placed in series of conductor/resistor in a circuit because ammeter is a LOW RESISTANCE INSTRUMENT, so the current flowing through the circuit REMAINS virtually unaffected. #ThankYuH..@JoY..❤️ |
|
| 23. |
Why is a voltmeter connected in parallel across the conductor/resistor in a circuit? |
|
Answer» Answer: The voltmeter is CONNECTED in a parallel connection in an ELECTRIC circuit, because when the current is switched on, the voltmeter SHOWS some resistance. Leading to INCORRECT value of current through the circuit when calculating. Therefore, to avoid the resistance and incorrect reading of current, voltmeter is connected in parallel in a circuit. |
|
| 24. |
How is friction useful to us? |
|
Answer» Answer: IF THERE WAS NO FRICTION E COULD NOT WALK ON THE GROUND BECAUSE FRICTION PROVIDES NECESSARY REACTION FORCE FOR WALKING...... |
|
| 25. |
Sailent points of cast iron |
|
Answer» Explanation: CAST iron is a group of iron carbon alloys with a carbon content greater than 2 % .its USEFULNESS derives from it's relatively low melting TEMPERATURE .The alloy constituents affect its colour when fractured: white cast iron has carbon impurities which allows crack to pass through .grey cast iron has graphite flakes which DEFLECT a passing crack. |
|
| 26. |
Calculate the density of paraffin oil, if glasscapillary of diameter 0.25 mm dipped in paraffinoil of the surface tension 0.0245 N/m rises aheight of 4 cm.(angle of contact of paraffin oilwith glass is 28° and g = 9.8m/second squere) |
|
Answer» Answer: DENSITY ( p ) = 897 kg / m³ [ For Paraffin Oil ] ★ FLUID MECHANICS ★ ★ GIVEN ; FOR _____________ [ GLASS CAPILLARY] ___________ » Diameter of Glass Capillary ( d ) = 0.25 mm ≈ 2.5 × 10-⁴ m » Surface Tension ( T ) = 0.025 N / m » Gravitational acceleration ( g ) = 9.8 m/s² ____________" WHEN GLASS CAPILLARY DIPPED IN PARAFFIN OIL " ___________ : Following changes occur :::: ---- ★ Angle made by Capillary with PARAFFIN oil = Cos ∅ →{ ∅ = 28° } ← ★ Surface Tension rises by a HIEGHT ( H ) = 4cm ★ Density of PARAFFIN oil ( p ) = ??? ______ [ By Using FORMULA ] ______ ★ p = ( 2 × T × Cos ∅ ) / r × h × g ★ p = ( 2 × 0.025 × Cos 28° ) / ( 1.25 × 10-⁴ × 4 × 10-² × 9.8 ) » p = ( 0.05 × 0.88 ) / 5 × 9.8 × 10^-6 » p = 0.044 / 49 × 10^-6 » p = 89.7 × 10^-5 × 10^6 ★ » p = 897 Kg / m³ « ★ _________________________________________ ANSWER :- Density Of Paraffin Oil after insertion of Glass Cappilary is :- ♣ p = 897 kg / m³ |
|
| 27. |
What is field:Field is an area in which source charge can be felt by test charge .Easiest defination |
| Answer» | |
| 28. |
What can be neither created nor destroyed [any 2 examples] |
| Answer» | |
| 29. |
Give the limitation of dimension analysis? |
|
Answer» Answer: It cannot derive relation or FORMULA if a PHYSICAL quantity depends upon more than three factors having dimensions. It cannot derive a formula containing trigonometric function, EXPONENTIAL function, and logarithmic function. It cannot derive a relation having more than ONE PART in an equation. |
|
| 30. |
What is dimensionless quantity? |
|
Answer» Answer: TRIGONOMETRY QUANTITY and LOGARITHMIC as well as EXPONENTIAL function |
|
| 31. |
How to convert meter in to senti meter |
|
Answer» by MULTIPLYING the LENGTH VALUE by HUNDRED |
|
| 32. |
HELLO GYZZZ...PLZZZ TELL ME THE ANSWER OF MY DOUBT!!The unit of length,velocity and force are doubled. Which of the following is correct change in the other units?a) unit of time is doubled b) unit of mass is doubled c) unit of momentum is doubled d) unit of energy is doubled |
Answer» the UNIT of LENGTH VELOCITY and FORCE the unit of momentum is the DOUBLED is the answer |
|
| 33. |
A human heart pumps 60 cc of blood |
|
Answer» Answer: NOA MAN heard hot pump 72 times in a minute do not KNOW this THING |
|
| 34. |
36. One mole of an ideal gas expands at aconstant temperature of 300 K from aninitial volume of 10 litres to a final volumeof 20 litres. The work done in expandingthe gas is (R=8.31J/mole-K) |
|
Answer» ................... |
|
| 35. |
A ball is thrown horizontally from the top of tower100 m high, with speed 10 m/s. After 2 seconds offall, gravity disappears. Then total time taken by ballto reach the ground is (g = 10 m/s2)(1) 10 s(2) 8s(3) 6 s(4) 4 s |
|
Answer» Answer: Option (3) 6s Explanation: Given, The height of the tower = 100 m Initial HORIZONTAL speed = 10 m/s Ball is THROWN horizontally from the top of the tower therefore its initial vertical speed will be zero Thus using the second equation of motion The vertical distance h covered in 2 seconds or, Therefore the height left = 100 - 20 = 80 m The vertical velocity after 2 seconds using the first equation of motion
Since the gravity disappears after 2 seconds therefore there will be no acceleration in the vertical direction TIME taken to cover 80 m distance = distance/velocity = 80/20 = 4 seconds Therefore, TOTAL time taken by the ball to reach the ground = 2 + 4 =6 seconds |
|
| 36. |
1 112.A point source of light B is placed atdistance L in front of the centre of a mimoof width d hung vertically on a wall.man walks in front of the mirror alongline parallel to the mirror at a distance 21from it as shown. The greatest distanceover which he can see the image of thelight source in the mirror is(1) d/2(2) d(3) 2d(4) 3d |
| Answer» | |
| 37. |
Rational number is denoted byand comes from the word |
| Answer» | |
| 38. |
.How A+B is different from B-A |
|
Answer» Answer: the SECOND case is subtraction |
|
| 39. |
Whysome solid diffuses in gases,but not in liquid |
|
Answer» Explanation: because PARTICLES in liquid move more SLOWLY than in SOLIDS... please follow me...... |
|
| 40. |
a body of mass 5kg is connected with a string and hanging at the ground level then a bullet of mass100gm comes with 600m/s and get into the object and the object attain some height from ground level what is the height of the object after collision from ground level |
|
Answer» Answer: 360 m Explanation: Kinetic ENERGY of bullet = 0.5mv² = 0.5 × 0.1 kg × (600 m/s)² = 0.5 × 0.1 × 36 × 10⁴ J = 1.8 × 10⁴ J = 18000 J Potential energy of OBJECT after attaining a HEIGHT "H" = MgH = 5 kg × 10 m/s² × H Kinetic energy of bullet is CONVERTED into potential energy of body 18000 J = 5 kg × 10 m/s² × H H = (18000 J)/(5 kg × 10 m/s²) = 360 m |
|
| 41. |
A cricket ball of mass 100 is moving with a velocity of 10 m/s and is nieback and moves with a velocity of 20m/s.Find the impulse and the force, if the forceA) 84 kg m/sB) 3 kg m/s, 300 N C) 5 ke m/s 100 ND 2 kg m/s, 50 Nlocity of 10 m/s and is hit by a bat so that it tunthe impulse and the force,if the force acts for 0.0 |
| Answer» | |
| 42. |
A particle is fired from ground with speed u making an angle theirs with the horizontal. The speed of the projectile just before hitting the ground will be ( neglect air friction)1)u2)ucos3)u/24)usin |
|
Answer» Answer: u Explanation: The initial and final SPEED of a projectile is same. In the GIVEN case:
|
|
| 43. |
What is mean by electroplating ??? |
|
Answer» Electroplating is the process of coating a metal with a thin layer of ANOTHER metal by electrolysis to IMPROVE the metal's corrosion RESISTANCE. |
|
| 44. |
A car accelerates from rest at a constant rate of 2m/s2 for sometime. Then it retards at a constant rate of 4m/s2 and comes torest it remains is motion for 6 sec then the total distance =?pls tell the ans anyone |
|
Answer» Answer: 24 m Explanation: Time taken to travel first part of the journey (while accelerating) = t Time taken to travel rest of the journey = 6 - t Use equation of MOTION: v = U + at In first part of journey v = 0 + 2t v = 2t .....(1) In second part of journey 0 = v - 4(6 - t) v = 4(6 - t) .....(2) Divide equations (1) and (2) v/v = 2t / (4(6 - t)) 1 = t / (2(6 - t)) 2(6 - t) = t 12 - 2t = t 3t = 12 t = 4 s Then, from equation (1) v = 2t = 2 × 4 = 8 m/s DISTANCE covered in first part x = ut + 0.5at² = (0 × 4) + (0.5 × 2 × 4²) = 16 m Distance covered in second part y = vt + 0.5a't² = (8 × 2) + (0.5 × -4 × 2²) = 16 - 8 = 8 m Total distance = 16 m + 8 m = 24 m |
|
| 45. |
Calculate the mass of the water tank. |
|
Answer» Answer: 11556600 kg Explanation: Volume of water in the tank = Length × Width × DEPTH = 11220 m³ Mass of water = Volume of water × Density of water = 11220 m³ × 1030 kg/m³ = 11556600 kg = 11556.6 tonnes |
|
| 46. |
Differences between MA and VR |
|
Answer» Answer: Mechanical Advantage is the amount the force is MULTIPLIED by the machine. It depends on the design of the machine, and also LOSSES to friction ETC. You can only get a value by EXPERIMENT. Velocity Ratio is how much faster the INPUT force moves than the output force. |
|
| 47. |
Where did fourth state of matter is found? |
|
Answer» PLASMA makes up 99 percent of matter in the VISIBLE universe the FOURTH state of matter is it's most COMMON state |
|
| 48. |
एक ट्रक विरामावस्था से किसी पहाड़ी से नीचे की ओर नियत त्वरण से लुढ़कना शुरू करता है यह 20 s में 400 m की दुरी तय करता है। इसका त्वरण ग्यात करे। अगर इसका द्रव्यमान7 टन है तो इस पर लगने वाले बल की गणना करें। (1टन -1000kg) |
| Answer» | |
| 49. |
Which is fourth state of matter? |
|
Answer» Plasma is the fourth STATE of matter... |
|
| 50. |
A uniformly accelerated body in a straight line has velocity 2 m/sat any time. After some time its velocity becomes 4m/s. Find theaverage velocity=3m/s but how |
|
Answer» LET time taken by body is t second distance cover by body = 2T distance cover after UNIFORM time = 4t average velocity =( 2t + 4t)/2t = 3m/s since body follow uniform acceleration so time become same . |
|