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An object is moving with speed 10 m/s along thedirection of a vector 4i’ - 3j’. Velocity of the object(1) 8i’ - 6j’ m/s(2) 10i’ - 10j’ m/s(3) 40i’ -30j’ m/s(4) 6i’ – 8j’ m/s. ( ’ )means cap |
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Answer» Dear Student, ◆ Answer - (1) Velocity = 8I’ - 6j’ m/s ● Explanation - # Given - Speed = 10 m/s Direction = 4i’ - 3j’ # Solution - UNIT vector ALONG 4i’ - 3j’ is - Unit vector = (4i’ - 3j’) / √(4^2 + 3^2) Unit vector = (4i’-3j’)/5 Velocity of the OBJECT is given by - Velocity = speed × unit vector Velocity = 10 × (4i’-3j’)/5 Velocity = 8i’ - 6j’ m/s Therefore, velocity of object is 8i’-6j’ m/s. Hope that helps you... |
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