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Calculate the wavelength associated with 1) 1mev electron 2) 1mev proton |
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Answer» Answer: W of electron = 5.76 ×10^-23 W of proton = 1.04× 10^-23 Explanation:it will depend on both proton and electron MASS as W=h/(2ME)^1/2 E=energy in EV E=1mev= 10^6ev Now, Mass of proton = 1.6 ×10^-27kg Mass of electron = 9.01 × 10^-31kg W(electron)= 6.65 ×10^-34÷(2×9.01×10^-31×10^6)^1/2 =5.76×10^-23 W(proton)= 6.65×10^-34÷(2×1.6×10^-27×10^6)^1/2 =1.04×10^-23 I hope that this is the answer If i am wrong then please LET me know. |
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