a body of mass 5kg is connected with a string and hanging at the groun

1.	a body of mass 5kg is connected with a string and hanging at the ground level then a bullet of mass100gm comes with 600m/s and get into the object and the object attain some height from ground level what is the height of the object after collision from ground level
Answer» Answer: 360 m Explanation: Kinetic ENERGY of bullet = 0.5mv² = 0.5 × 0.1 kg × (600 m/s)² = 0.5 × 0.1 × 36 × 10⁴ J = 1.8 × 10⁴ J = 18000 J Potential energy of OBJECT after attaining a HEIGHT "H" = MgH = 5 kg × 10 m/s² × H Kinetic energy of bullet is CONVERTED into potential energy of body 18000 J = 5 kg × 10 m/s² × H H = (18000 J)/(5 kg × 10 m/s²) = 360 m

a body of mass 5kg is connected with a string and hanging at the ground level then a bullet of mass100gm comes with 600m/s and get into the object and the object attain some height from ground level what is the height of the object after collision from ground level

Answer»

Answer:

360 m

Explanation:

Kinetic ENERGY of bullet = 0.5mv²

= 0.5 × 0.1 kg × (600 m/s)²

= 0.5 × 0.1 × 36 × 10⁴ J

= 1.8 × 10⁴ J

= 18000 J

Potential energy of OBJECT after attaining a HEIGHT "H" = MgH

= 5 kg × 10 m/s² × H

Kinetic energy of bullet is CONVERTED into potential energy of body

18000 J = 5 kg × 10 m/s² × H

H = (18000 J)/(5 kg × 10 m/s²)

= 360 m

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a body of mass 5kg is connected with a string and hanging at the ground level then a bullet of mass100gm comes with 600m/s and get into the object and the object attain some height from ground level what is the height of the object after collision from ground level

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