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ANSWER:

Explanation:

This is due to inertia of REST of the rider.Hope you UNDERSTOOD.

ANSWER: The FOCAL LENGTH is 15 cm and the image is formed at 10 cm from the lens.

Explanation:

Given that,

Distance of the OBJECT u = -30 cm

Magnification

We know that,

The magnification is

The image is formed at 10 cm from the lens.

Using lens's formula

Hence, The focal length is 15 cm and the image is formed at 10 cm from the lens.

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✔HYDROGEN is considered as a good FUEL . This is because it is ENVIRONMENT friendly . the BURNING of Hydrogen only produces Hydrogen and Oxygen . These gases are not harmful for the environment at all . HENCE it is considered as a pollution free fuel .

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Answer ⇒ Option (c). 0

Explanation ⇒ According to the QUESTION, the BODY is uniformly ROTATING thus the resultant FORCE on the particle P will be in the radial direction.

∴ The DIRECTIONS of A and B will be perpendicular to each other.

Mathematically,

Angle between them = θ = 90°

∴ A.B = |A|.|B|. Cos90° [A.B. is the dot product of vectors.]

= |A|.|B|. 0

= 0

Hence, the answer is Option (c).

Hope it helps.

Let 60 KG man has mass m1
let his VELOCITY be v1
let 40 kg man has mass m2
Initial kinetic energy = m1v^2/2
=(60×10×10)/2=3000J
According to CONSERVATION of MOMENTUM,
m1v1 +m2v2 =( m1+m2)V
60×10 + 40×0 =(60+40)V
V=6m/s
Final kinetic energy ={(m1+m2)v^2}/2=(100*6*6)/2= 1800J.
Therefore loss in kinetic energy = 3000-1800=1200J

State and prove LAW of conservation of momentum. Law of conservation of momentum statesthat total momentum of system remains conserved in the ABSENCE of external force. ... Aristotle's law of MOTION states that an external force is REQUIRED to keep the body in motion.


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Resistance of coil ,R = 60 ohm
mass of water , M = 42KG
current passing through it , I = 7A
time taken , t = 1 min = 60 sec

you know , heat dissipates , H = I²Rt
= 7² × 60 × 60 = 49 × 3600 J

we also know, Q = Ms ∆T
here M is the mass of water , s is SPECIFIC heat capacity. and ∆T is the temperature.
so, Q = 42 × 4200 × ∆T

now, Q = H
42 × 4200 × ∆T = 49 × 3600
∆T = 1°C

hence, temperature change is 1°C

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1. When frequency of the INCIDENT light is increased, the RESOLVING power of the telescope increases.
2. When the focal LENGTH of the OBJECTIVE lens is increased, the resolving power does not change.
3. When aperture if the objective lens is HALVED, the resolving power of the Telescope is also halved

(a)
As it is clear from the above electric FIELD vector that electric field is in the negative x direction. Therefore, the direction of propagation of the vector will be in negative y-direction i.e. –j.

(b) ) As we know that the general equation for electric field vector in the POSITIVE x-direction is:
here, K is propagation constant.
so, propagation constant , k = 1.8 = 2π/wavelength
wavelength = 2π/1.8 = 3.49 m

(c) angular velocity, =5.4 × 10^8 rad/s
so, angular frequency = /2π
=5.4× 10^8/2π = 86 MHZ

(d) AMPLITUDE of magnetic field part ,
so,

(e) expression for magnetic field part of wave

The PLANCK’s CONSTANT (h) can be defined as a PROPORTIONALITY constant that relates the energy (E) of a photon to the frequency (ν) of its associated electromagnetic wave.

Mathematically,
Planck’s Constant (h) = Energy(E) / frequency (ν).

Dimensional Formula of energy = M1L2T-2.
Dimensional Formula of frequency = M0L0T-1.

Putting these values in above equation we GET,
Dimensional Formula of Planck’s constant = M1L2T-


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F =MA

10 = 5*a

a=2

V^2 - u^2 =2as

V^2 = u^2 + 2as

V^2 = 0 + 2(2*25)

In AB PART of journey

V^2 = 100

V=10m/sec

Your answer ----

Given, time t = 1s current I = 1A

we KNOW that

I = Q/t

=> Q = I × t

=> Q = 1 × 1 = 1

We know that

Q = ne

where ,

Q = charge

N = number of electron

e = elementary charge ( = 1.6 × 10^-19 )

put the values , we get

1 = n × 1.6 × 10^-19

=> n = 1/(1.6×10^-19)

=> n = 6.25 × 10^18 electrons


Hence, 6.25 × 10^18 electrons flows per second to constitute a current of one ampere.


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ANSWER:

Fluids EXERT drag on the solids moving through them, which is somewhat like friction that tries to OPPOSE the motion of the body and slows it down.Hence, streamlined shape is given to the BODIES moving through fluids, as in ships and submarines.

Gravitation is the ATTRACTIVE force existing between any two OBJECTS that have mass. The force of gravitation PULLS objects TOGETHER. Gravity is the gravitational force that occurs between the EARTH and other bodies. Gravity is the force acting to pull objects toward the earth.

Answer:

Oxide is MO, i.e , M is in +2 OXIDATION STATE

∴ FORMULA of the phosphate is M

3

(PO

4

)

2

.

LET's SAY they collide after time t seconds of throwing first stone. So, we have following equation with bold letters being VECTORS:

r1 = ut + 0.5gt^2

r2 = u(t-3) + 0.5g(t-3)^2

Equating these two equations:

3u = 0.5g[(t-3)^2 - t^2] = -0.5g[(2t-3)(3)] => u = -0.5g(2t-3)

Putting values and assuming positive y-axis in vertically upward direction, we have,

49 j = 0.5*9.8*(2t-3) j

or, (2t-3) = 10 or t = 6.5

Hence, distance = 49*6.5 - 0.5*9.8*6.5^2 = 111.475 m (ANSWER)

Concave MIRROR , f is negative ,  f = -10 cm
   u = ?
 h = 2 cm 
 erect image  so  h' is positive,  h' = 6 cm
     so m = h'/h = 3
         as  m = -V/u = 3  => v = -3 u

   mirror equation  is  1/v + 1/u = 1/f

       1/(-3u) + 1/u = 1/(-10)
          2/(3u) = -1/10
            u = -20 /3 cm = -6.67 cm         and  v = -3 u = 20 cm
           v is positive,  so image is behind the mirror and is virtual.

  in concave mirror , an erect image is obtained when the object is between the pole and the FOCUS. it is magnified and is virtual.  so  you can VERIFY from values of u, v and f.


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Use the condition to FIND minimum velocity ,
at the top NORMAL reaction = 0
let a velocity v is given in the horizontal direction.
now, centripetal FORCE acts
then, inward force = outward force
mg - N = mv²/R
put N = 0 => mg = mv²/R
g = v²/R => v² = gR
taking square root both sides,
v = √gR

hence, minimum horizontal SPEED require , v = √gR

Solution :

Let m be the mass of each fragment.

As and are perpendicular to each other, therefore, RESULTANT momentum of the two fragments

According to the principle of conservation of LINEAR momentum

Negative sign implies that third fragment will FLY in a direction opposite to the direction of resultant momentum of two fragments.

Thanks for asking the QUESTION!

ANSWER::

Mass of the bullet = m

Speed of bullet = v

Mass of BALL = M

Frictional mass from ball = m'

Let velocity after collision = v₁

Using law of conservation of momentum ,

mv + 0 = (m' + m) v' + (M - m') v₁ (v' = final velocity of bullet + frictional mass)

v' = [mv - (M + m')v₁] / (m + m')

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(1)This because the TYRE has unified volume in summer when the PRESSURE increase the volume decreases .it is full MENTIONED in gay Lucca's law.....here your ANSWER

Because the hydronium or hydrogen FREES IONS are only present on AQUEOUS SOLUTIONS


not as gases

State law of conservation of momentum. DEDUCE this law from NEWTON's second law of motion. ... HENCE, in the ABSENCE of an external force, the TOTAL momentum of a group of objects remains unchanged or conserved during the collision. This is the law of conservation of momentum.

Dear Brainly member,
Here is your answer:-
A/Q,
angle i = 50 degrees
RI = 1.5
=>sin i / sin R = 1.5
=>sin 50 / sin r = 1.5
=>50/r = 1.5
=>r = 1.5*50
=>r = 75
deviation angle when light ray ENTERS glass = angle of refraction,r = 75 degrees
/ for division and * for multiplication.

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Given,
length of the ROD , l = 1 m
angular frequency , = 400rad/s
magnetic field strength,B = 0.5T
one end of the rod has zero linear velocity while other end of rod has a linear velocity of .
average linear velocity of the end,
emf developed between the centre and RING,


now, e = 0.5 × 1 × 1 × 400/2 = 100V
hence, emf developed between the centre and the ring is 100V

According to Faraday law of electromagnetic induction,
the induced emf is
thus, a relation between electric FIELD and rate of change of flux can be established.
e.g.,
exist along circumstance of RADIUS 'a' due to change in magnetic flux.


Linear charge density on rim is .so,total charge on rim is
so, F = QE =

in term of angular velocity,

now, INTEGRATE both sides,


As direction of Angular velocity is along AXIS.

It is +ve in 1 CASE as in that the MOMENTUM of gun and BULLET is of before firing
In 2 case the momentum of gun will be in NEGATIVE as the gun recoils

E1=k×300

For the second part it depends on the connection of cell if NEGATIVE terminal on same side then :

E1+E2=k×100

If it travels in the OPPOSITE direction then :

E1-E2=k×100

So, the question here is INCOMPLETE and this is all the DATA that can be concluded.

(a) The peak value of a.c SUPPLY is given by 300V.
e.g.,.so, RMS voue of voltage,
here, Ev is rms voltage.
now, Ev = 300/√2 = 150√2 = 212.1V

(b) Here, RMS value of current in a.c CIRCUIT is 10A.e.g., Iv = 10A
THUS, the peak current,
so, =√2 × 10 = 14.14 A

u= -30cm

f= +20cm

ho= +1cm

Using mirror formula,

1/V+1/u=1/f

1/v+1/-30=1/20

1/v-1/30=1/20

1/v=1/20+1/30

1/v=3+2/60

1/v=5/60=1/12

=>v= +12cm

Therefore, the image will be formed at a distance of 12cm BEHIND the mirror.

m= -v/u

m= -12/-30

m= +0.4

m=hi/ho

0.4=hi/ho

0.4=hi/1

=>hi= +0.4cm

Therefore, the image formed is diminished in SIZE.

The WAVE produced is TRANSVERSE .
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It is given that, 0.840 m is the distance travelled WITHIN the barrel. Therefore u = 0 m/s, v= 521 m/s. 
This means that a = (v^2 - u^2)/2s from the EQUATION v^2 = u^2 + 2as 
So,
a = (521^2)/(2 x 0.840) 
a = 161.57 m/s^2

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Thanks for ASKING the question!

ANSWER::

P₁(incidence) = (h/λ) cos Ф i - (h/λ) sin Ф j

P₂(REFLECTED) = -(h/λ) cos Ф i - (h/λ) sin Ф j

Change in MOMENTUM will be in x-axis direction ::

ΔP = (h/λ) cos Ф - [(h/λ) cos Ф] = (2h/λ) cos Ф

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Latent heat is ENERGY released or absorbed, by a body or a thermodynamic system, during a constant-temperature process. Two COMMON forms of latent heat are latent heat of FUSION (melting) and latent heat of VAPORIZATION ( boiling ) .....



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Since R=[(RHO)*L]/A
So r depends upon
1. AREA of conductor
2. LENGTH of the conductor

1.All distances should be MEASURED from the pole.
2.The distances measured in the direction of incident light, to be taken positive and measured in the opposite direction of incident light to be taken negative.
3.H eight of object and height of image are positive if measured upward from the axis and negative if measured downward.
4. For a concave mirror 'F and ‘R’ are negative and for a CONVEX mirror these are positive.
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It is a DEVICE USED to MEASURE SPEED in VEHICLES

Answer:

The car can be STOPPED by this force in 180 m.

Explanation:

GIVEN that,

velocity of car = 10 m/s

distance s = 20 m

Let the mass of the car be m.

Case (I).

Using equation of motion

Negative sign shows the retardation because the speed is decreasing.

For case (II),

Velocity v = 30 m/s

The force is same.

So, The acceleration will be same.

Using equation of motion again

Hence, The car can be stopped by this force in 180 m.