1.

bullet leaves a rifle with a muzzle velocity of 1042m/s while accelerating through the barrel of rifle bullet move a distance of 1.680m determine the acceleration of bullet

Answer»

It is given that, 0.840 m is the distance travelled WITHIN the barrel. Therefore u = 0 m/s, v= 521 m/s. 
This means that a = (v^2 - u^2)/2s from the EQUATION v^2 = u^2 + 2as 
So,
a = (521^2)/(2 x 0.840) 
a = 161.57 m/s^2

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