Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

One horse power is how much watt

Answer» HEYA dear..


746 WATT in ONE HORSE power.
2.

Given that sound travels in air at 340 m/s, find the wavelength of the waves in air produced by a 20kHz sound source. If the same source is put in a water tank, what would be the wavelength of the sound waves in water? Speed of sound in water = 1,480 m/s.

Answer»

Here is your ANSWER ...
WAVELENGTH = VELOCITY / frequency
hope it HELPS !!;

3.

Question 8.15: Answer the following questions: (a) Long distance radio broadcasts use short-wave bands. Why? (b) It is necessary to use satellites for long distance TV transmission. Why? (c) Optical and radio telescopes are built on the ground but X-ray astronomy is possible only from satellites orbiting the earth. Why? (d) The small ozone layer on top of the stratosphere is crucial for human survival. Why? (e) If the earth did not have an atmosphere, would its average surface temperature be higher or lower than what it is now? (f) Some scientists have predicted that a global nuclear war on the earth would be followed by a severe ‘nuclear winter’ with a devastating effect on life on earth. What might be the basis of this prediction?Class 12 - Physics - Electromagnetic Waves Electromagnetic Waves Page-287

Answer» (a)\text{electromagnetic waves in the frequency}\\\text{of short-wave band reflect from}\\\text{ionosphere where lower frequency radio waves}\\\text{e.g., medium waves are absorbed}
so , short waves are suitable for long distance radio broadcast.

(b) yes , it is necessary to use satellite for long distance TV transmission. actually very high frequency (VHF) and ultra high frequency (UHF) electromagnetic waves used in TV transmission . after frequency modulation do not reflect from ionosphere and can only be transmitted straight from antenna.so, the range is highly limited . in order to SEND the transmission for long distances , satellite is used.

(c) atmosphere absorb X-rays , while visible and radiowaves can penetrate through it. hence, optical telescope can work on the ground but X-ray astronomical telescope only work above Atmosphere, hence installed on satellite orbiting AROUND the earth.

(d) The thin ozone layer absorbs harmful ultraviolet radiations , gamma rays, cosmic rays etc. all these high energy radiations can cause damage to the living cells. thus, the thin ozone layer on the top of the stratosphere is crucial for human SURVIVAL.

(e) in the absence of atmosphere, the day temperature can rise to many fold and temperature at night will be much below 0°C . although the average temperature will be reduced in the absence of green house effect.

(f) the thick clouds produced by global nuclear war will prevent solar radiation to reach down across the globe . this would cause severe 'nuclear Winter'
4.

The ratio of minimum wavelength of lyman and balmer series will be

Answer»

Here min WAVELENGTH means MAX energy so energy will be max at INFINITY so each case n2=infinite
For lyman-n1=1and balmer series-n1=2.so si the ratio will be 1/4.

5.

Write the principle of working of an electric motor.

Answer»

A electric motor is a electric machine which CONVERT ELECTRICAL ENERGY into MECHANICAL energy

6.

What is uniform motion

Answer» HEY MATE here ur ANSWER.....

moving in a same speed

HOPE it helps u
7.

a car moving with constant acceleration covers the distance between two points 180 M apart in 60 Seconds its speed as it passes the second point is 45 M per second what is its acceleration and its speed at the first.

Answer»

180+45/(2*60)_speed
45-180/60_acceleration

8.

Draw a distance time graph from following data showing distance travelled by a car .calculate it's speed

Answer» HOPE this HELPS.. MAKE this BRAINLIEST
9.

Two persons each of mass m are standing at the two extremes of a railroad car of mass M resting on a smooth track (figure 9-E10). The person on left jumps to the left with a horizontal speed u with respect to the state of the car before the jump. Thereafter, the other person jumps to the right, again with the same horizontal speed u with respect to the state of the car before his jump. Find the velocity of the car after both the persons have jumped off.

Answer»

Solution:

There will be TWO cases.

CASE - 1

Let the velocity of the railroad car with RESPECT to earth is V after jump of left man.

0 = - mu + (M + m) VV = mu / (M + m) towards right.

CASE - 2

When man on right jumps , the velocity of it with respect to car is u.

0 = mu - Mv'v' = mu/Mv' is the change in velocity of platform when platform is taken as reference and we ASSUMED car to be at rest.

Therefore , net velocity towards left i.e. velocity of car with respect to earth = mv/M - mv/(M + m)= (MMU + m²v - Mmu) / M(M + m)= m²v / M(M + m)

Hope it helps!

10.

What is law of conservation of linear momentum

Answer»

Conservation of linear momentum expresses the FACT that a body or system of bodies in motion retains its TOTAL momentum the product of mass and VECTOR VELOCITY, UNLESS an external force is applied to it.

11.

a balloon is moving upwards with a speed of 5m/s when it is height 98m.a packet dropped from it.what is velocity of packet when it strikes the ground?

Answer»

When the packet FALLS from the BALLOON it has an initial velocity of 5 m/s.

The ACCELERATION is the acceleration due to GRAVITY which is 10m/s²

S = 98m

We will use the following equation of motion :

V² = U² + 2gs

V² = 25 + 2 × 10 × 98

V² = 1985

V = 44.55 m/s

12.

Magnetic field on the axis of a circular current loop

Answer»

The Magnetic FIELD along the axis of a CIRCULAR loop.We derived an expression for the magnetic field at the CENTRE if a circular CURRENT loop of RADIUS R.

13.

10 neuton = is how much kgf

Answer» 10 NEUTONS = 1.01971621 KGF
14.

Alternating current can not be measured by D.C ammeter because??

Answer»

DC AMMETER reads instantaneous CURRENT where as ac ammeter reads RMS value

15.

Define vector............?

Answer»

Which has MAGNITUDE and DIRECTIONS

16.

two cells of emf 3v and 4v and internal resistance 1ohm and 2ohm respectivly are connected in parallel so as to send current in same direction through a external resistance of 5 ohm find current b/w each branch.

Answer» E= 5*2/3 = 10/3 so I = 10/3 / 5 = 2/3A
17.

A bullet train is moving with velocity 180km/h and it takes 5 seconds to stop after brakes applied find the force exerted by brakes on the wheel if mass is 2000 kg.

Answer»

HEYA!!!


HERE IS YOUR ANSWER,


=> Speed of TRAIN = 180 km/hr = 50 m/s.

=> Time TAKEN to stop the train = 5 sec.

=> Total mass = 2000 kg.

=> Retardation = (Speed)/(time)

=> 50/5

=> 10 m/s²

Now,

=> F = m × a

=> F = 2000 × 10

=> F = 20,000 N.


HOPE IT HELPS YOU,
THANK YOU.☺️

18.

Why submarine are manufactured fom hard thick metal sheet?

Answer»

The main REASON to manufacture submarines with HARD thick metal SHEET is because under water PRESSURE is high, this pressure might crush any steel with less thickness. Hence, to deal with this pressure hard thick metal sheet are used.

19.

The effective acceleration of a body when thrown upwards with acceleration a is

Answer»

So the ACCELERATION of any OBJECT you THROW UPWARDS is about 9.8 m/s^2downward.

20.

the near point of a person suffering from hypermetropia is 75cm calculate thefocal length and power of lens required to enable him to read news paper which is kept at 25cm from the eye?

Answer»

Answer:

Explanation:

Given :-

u = - 25 cm

v = - 75 cm

To Find :-

f = ??

P = ??

Solution :-

Using, 1/v - 1/u = 1/f we get

⇒ 1/- 75 - 1/- 25 = 1/f

⇒ 1/- 75 + 1/25 = 1/f

⇒ 2/75 = 1/f

⇒ f = 75/2

f = 37.5 cm

Hence, the focal length is 37.5 cm.

Now, P = 100/37.5 cm

P = 2.6 D

Hence, the power of lens REQUIRED to enable him to read NEWS PAPER is 2.6 D.

21.

Value of sin (37degree)cos (53degree)is

Answer»

Both have same VALUE =3/5
therefore ANSWER is 9/25

22.

When do you say light rays are diverging?

Answer»

While REFRACTION........

23.

A body of mass 9kg is lying on a surface of table. calculate the net force acting on it .

Answer»

The NET force ACTING on the table will be ZERO as in a force is equal to mass into acceleration and there is mass 9 KG and acceleration is zero so the net force will become zero

24.

0.5 mole of N₂ gas - Calculate the mass of it.

Answer»

no. of MOLES=GIVEN mass/GMM of NITROGEN

0.5 moles =given mass/28


therefore mass=28*0.5=14 G


14 g is the ANSWER

25.

What is the kinetic energy of 1g of O2 at 47 'C

Answer»

47 degrees C = 320 K

1 g O2 * 1 mol / 32.00 grams = 0.03125 mol O2

Universal gas CONSTANT: R = 8.314 J / mol K.

8.314 J / mol K * 0.03125 mol * 320 K = 83.14 J.

This ANSWER assumes that KINETIC energy is zero when all the gas particles are infinitely FAR away from each other and that the gas is an ideal gas.

26.

When a force is applied on an object, it may change its is in the direction of motion, the speed of the object increases. If direction opposite to the motion, then it results in a decrease in speed. If the applied force the force is applied in the the speed of the object.

Answer»

If the FORCE is APPLIED in the direction of MOTION then SPEED INCREASES

27.

Calculate the equivalent resistance between X and Y

Answer»

The ANSWER to this QUESTION is 2R

28.

Sign convention of real and virtual images I .e of Hi , v , m for mirror or lens

Answer»

                         Note :


  • f = focal length
  • V = distance of image .
  • u = distance of object .

Lens formula :

1 / f = 1 / v - 1 / u


Concave lens :


f = negative

u = negative

v =  negative


Convex lens


f = positive

u = negative

v = positive for real image ,

v = negative for virtual image .


The OPTICAL centre is CHOSEN as the origin of the COORDINATE system.


With respect to optical centre :

The PART which are above are positive, below negative.

The part which are right are positive while left is negative.

This is just like the normal x-axis and y-axis in the co-ordinate system .

29.

A block of mass 2.0 kg moving at 2.0 m/s collides head-on with another block of equal mass kept at rest.(a) Find the maximum possible loss in kinetic energy due to the collision. (b) If the actual loss in kinetic energy is half of the maximum, find the coefficient of restitution.

Answer»

Thanks for asking the question!


ANSWER::


Mass of first block , m₁ = 2 kg

Speed of block , v₁ = 2 m/s

Mass of SECOND block , m₂ = 2 kg

Let final velocity of second block = v₂


Using law of conservation of momentum ,


2 x 2 = (2+2) v


v = 1 m/s


Therefore ,


(a) Loss in Kinetic Energy in ELASTIC collision = (1/2) x 2 x 2² v - (1/2)(2+2) x 1²

= 4 - 2

= 2 J


(B) Actual loss = Maximum Loss / 2 = 2/2 = 1 J


(1/2) x 2 x 2² - (1/2) x 2 x v₁² + (1/2) x 2 x v₂² = 1


4 - (v₁² + v₂²) = 1


4 - [(1 + e²) x 4] / 2 = 1


2(1 + e²) = 3


1 + e² = 3/2


e² = 1/2


e = 1 / √2


Hope it helps!





30.

A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque. ?

Answer»

Given in the question :-


\omegaRotation of the WHEEL(INITIAL) = 600 RPM or = 10 revolution / second

\omega'Final velocity = 0

Time = 10 second

\alphanow we have to find = ?


We know the formula ,


\omega' = \omega - \alpha t

PUT all the VALUES in the given formula

0 = 10 - α × 10

α = 1 revolution /second ²


\omega''Now the angular velocity at time change t = 5 sec.


\omega'' = \omega - \alpha t

ω'' = 10 - 1 × 5

ω'' = 5 revolution/second.



Hope it Helps :-)

31.

What is Pascal law? explain with applications.

Answer»

Pascal's LAW or principle applies to pressure TRANSMISSION in fluids. The principle is applied primarily in the operation of hydraulics such as in car brakes and Falk lifts. Pascal's principle states that pressure in an incompressible FLUID contained in an in expansible VESSEL is transmitted equally in all direction.

32.

The focal length of a converging lens is 20cm. An object is 60cm from the lens. Where will theimage be formed and what kind of image is it?

Answer»

REFER to attachment

PLEASE MARK as BRAIN LIEST

33.

Differentiate between transverse wave and longitudinal wave.

Answer»

TRANSVERSE Waves- Displacement of the medium is perpendicular to the direction of PROPAGATION of the WAVE.

Longitudinal Waves-Displacement of the medium is PARALLEL to the direction of propagation of the wave.

34.

A ball is thrown vertically upwards, with a speed of 10m/s from the top of a tower 200m high and another is thrown vertically downwards, with the same speed simultaneously. What is the time difference between them in reaching ground?

Answer»

HEYA MATE,

HERE IS UR ANSWER.

Thanks for asking this question.

The total time taken by Ball-1 from t-0 to the moment it REACHES ground be t-1 and Ball-2 be t-2

We need (t-1) - (t-2)

t-1

Upward phase, u = 10m/s a= -10m/s^2 v=0, time = v-u/a = -10/-10 = 1 second

Height attained during intial phase = ut + 1/2gt^2 = 10*1 + 1/2(-10)(1)^2 = 5m

Downward Phase, u = 0 height = 205 m,

==> 205m = 0 + 1/2(10)(t^2)

t= SQRT(41)

t-1 = 6.4031+1 = 7.4031

t-2

Height traveled = 200 m, u = 10m/s

==> 200 m = 10t + 1/2(10)(t^2)

5t^2+10t-200 = 0

t^2 + 2t - 40 = 0

t= [-2(+-)Sqrt(4–(4)(1)(-40))]/2 = [-1(+-)(1/2(Sqrt(164))] = -1 (+-) 12.8062/2 = 5.4031

Difference = 7.4031–5.4031 = 2 Seconds.

This big solution is offered as other solutions have already been given.

I HOPE IT HELPS U.

35.

What is the definition of mass

Answer» HI,


the mass of a substance is the amount of MATTER PRESENT in it.


hope it helps..
36.

Define pressure and its si unit

Answer»

Pressure is the FORCE acting perpendicularly on a BODY PER unit area.

PRESSURE = FORCE (N ) / AREA ( m^2)

UNIT OF PRESSURE = Nm^2 or PASCAL.

37.

What is the angle between 2A and 4A ....with solution

Answer» DIRECTION of A is same so that the ANGLE between them is 0°
38.

An erect image 3 times the size of the object is obtained with a concave mirror of radius of curvature 36 cm.find the position of the object

Answer»

Given,
R=36 CM
or f=-36/2=-18 cm (It is a concave mirror)
magnification, m=h' /h=3=-v/u
or v=-3u
Now, USING the mirror formula,
1/f=1/v + 1/u
-1/18=-1/3u + 1/u
or OBJECT DISTANCE, u=-12 cm

39.

A man is standing against a wall such that his right shoulder and right leg are in contact with the surface of the wall along his height. Can he raise his left leg at this position without moving his body away from the wall? Why? Explain.

Answer» FINAL Answer : \red {No}

=> For stable position /Proper Balancing : Our Line of Centre of Gravity must TRY to intersect the Base Support (here area on which our foot is PLACED)

=> When we try to with our Right shoulder and right LEG in contact with the WALL, and trying to lift our left leg up then our line of Centre of gravity moves away from the base support.
This makes us in unstable position, unless we move our body away from the wall.
40.

What makes the middle zone of a candle flame luminous??

Answer»

A candle has three different zones:

  1. innermost zone ---- dark or black in colour
  2. MIDDLE zone -------- luminous zone
  3. outer most zone ------- Non luminous zone
  • Luminous means bright and emits light
  • The YELLOW colour REGION which is the bright part of the flame is middle zone of the candle.
  • It is due to partial or incomplete COMBUSTION of FUEL
41.

Magnification produced by a concave mirror of a body 4 cm in size is 0.16

Answer»

M=-v/u
0.16=-4/u
u=-4/0.16
u=25

42.

Baking soda - Find out the chemical names and formulae for the given common household substances.

Answer»

Hey
Baking Soda is also know as sodium BICARBONATE or sodium HYDROGEN carbonate.
It has FORMULA Na HCO3.
Hope it HELPS :)

43.

a flat curve on highway has a radius of curvature 400m. a car rounds the curve at a speed of 32 m/s. what is the minimum value of coefficient of friction that will prevent car from sliding. (g-9.8 m/s)

Answer»

32^2/(400×9.8)=.2612

44.

A particle of mass M moves with constant speed V on a circular path of radius R as shown in figure the average force on it during its Motion from A to B is

Answer»

AvgF = m[ v(final) - v(initial) ]/∆t

w = angular velocity
w = 2π/T = V/R

T = time period of oscillation
T = 2πR/V

so ∆t = (2π/3)/(2π/T)
∆t = T/3
∆t = 6πR/V


to solve it in VECTOR form
let the x-axis is from centre to A
and y-axis is PERPENDICULAR to it from centre
and let the unit vector in the direction of x&y axis are " i&j " respectively


therefore
v(initial) = v j

v(final) = v [ cos30i - sin30j ]
v(final) = v [ √3i - j ]÷2


so
=> v(final) - v(initial)
=> v [ √3/2i - 3/2j ]


so
avgF = { mv[ √3i - 3j ]÷2 }/{ 6πR/v }
= mv²[ √3i - 3j ]÷[12πR]


and by taking its mode

= mv²/12πR×[ √(3+9) ]
= √12mv²/12πR
= mv²/2√3πR


I think I made some mistakes in SOLVING
because I'm not USING pen-paper
hope so you GET it that how to solve it
otherwise I have to solve it again


hope it helps you
@di

45.

What are the examples of ohmic and non-ohmic conductors?

Answer» OHMIC CONDUCTOR- copper wire, aluminium, METAL etc.
non ohmic- diode BULB,silicon,germanium
46.

A bullet leaves a rifle with a muzzle velocity of 521m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840m. Determine the acceleration of the bullet (assume a uniform acceleration).

Answer»

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

The question STATES that 0.840 m is the distance travelled within the barrel. Therefore u = 0 m/s, v= 521 m/s. 
This means that a = (v² - u²)/2s. 
This is a reformat of v² = u²+ 2AS 
a = (521^2)/(2 x 0.840) 
a = 161.57 m/s²

HOPE IT HELPS U.
#BE BRAINLY.

47.

Name the physical quantity which is considered to be a measure of the quantity of motion of a body

Answer»

The PHYSICAL QUANTITY is " MOMENTUM"....☺️☺️

48.

a particle is moving along a circle such that it complete one revolution in 40sec.in2 min 20 sec the ratio displacement and distance is

Answer»

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Let the object at point A

As given, object covers WHOLE PARK in 40s

Now, 2 min 20s = 2*60s + 20s
= 140s

In 40s the object takes = 1 ROUND.
In 140s the object takes = 140/40 or 3.5 rounds.

Now, take 1 round from A, and similarly take 2 rounds more.

Now, take a HALF round and you will end you journey at B

So, displacement = diameter of circle
= 2r

DISTANCE = circumference

Circumference = 2πr

As body took 3.5 rounds so,

= 3.5 ( 2* 22/7 * r )
= 3.5 * 44/7 * r
= 0.5*44r or 22r

Now, ratio of displacement and distance

= 2r / 22r = 1/11 or 1 : 11

Hope it helps

49.

the ratio of resistivity of two materials a and b is 1:2, ratio of their length is 3:4 and if the ratio of radii is 2:3 find the ratio of resistance of a and b.

Answer»

The RESISTANCE of a and b are in the ratio 27:32.
See DESCRIPTIVE ANSWER in the PIC

50.

Games and sports in which friction is a help or source of trouble

Answer»