the near point of a person suffering from hypermetropia is 75cm calcul

1.	the near point of a person suffering from hypermetropia is 75cm calculate thefocal length and power of lens required to enable him to read news paper which is kept at 25cm from the eye?
Answer» Answer: Explanation: Given :- u = - 25 cm v = - 75 cm To Find :- f = ?? P = ?? Solution :- Using, 1/v - 1/u = 1/f we get ⇒ 1/- 75 - 1/- 25 = 1/f ⇒ 1/- 75 + 1/25 = 1/f ⇒ 2/75 = 1/f ⇒ f = 75/2 ⇒ f = 37.5 cm Hence, the focal length is 37.5 cm. Now, P = 100/37.5 cm ⇒ P = 2.6 D Hence, the power of lens REQUIRED to enable him to read NEWS PAPER is 2.6 D.

the near point of a person suffering from hypermetropia is 75cm calculate thefocal length and power of lens required to enable him to read news paper which is kept at 25cm from the eye?

Answer»

Answer:

Explanation:

Given :-

u = - 25 cm

v = - 75 cm

To Find :-

f = ??

P = ??

Solution :-

Using, 1/v - 1/u = 1/f we get

⇒ 1/- 75 - 1/- 25 = 1/f

⇒ 1/- 75 + 1/25 = 1/f

⇒ 2/75 = 1/f

⇒ f = 75/2

⇒ f = 37.5 cm

Hence, the focal length is 37.5 cm.

Now, P = 100/37.5 cm

⇒ P = 2.6 D

Hence, the power of lens REQUIRED to enable him to read NEWS PAPER is 2.6 D.

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the near point of a person suffering from hypermetropia is 75cm calculate thefocal length and power of lens required to enable him to read news paper which is kept at 25cm from the eye?

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