A wheel rotating at a speed of 600 rpm (revolutions per minute) about

1.	A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque. ?
Answer» Given in the question :- $\omega$ Rotation of the WHEEL(INITIAL) = 600 RPM or = 10 revolution / second $\omega'$ Final velocity = 0 Time = 10 second $\alpha$ now we have to find = ? *We know the formula ,* $\omega' = \omega - \alpha t$ PUT all the VALUES in the given formula 0 = 10 - α × 10 *α = 1 revolution /second ²* $\omega''$ *Now the angular velocity at time change t = 5 sec. $\omega'' = \omega - \alpha t$ ω'' = 10 - 1 × 5* *ω'' = 5 revolution/second.* *Hope it Helps :-)*