67486 + Interview Questions in Secondary School in Physics

1.	1 g cm-3 = _ kg m-3
Answer» Answer: 1 G / CM3 = 0.001kg/0.0000001m3 = 1000kg/m3 pls MARK as BRANLIEST

1.

1 g cm-3 = _ kg m-3

Answer»

Answer:

1 G / CM3 = 0.001kg/0.0000001m3

= 1000kg/m3

pls MARK as BRANLIEST

Discussion

2.	What is a good conductor?
Answer» Answer: *GOOD* *CONDUCTORS* is the *substance* that allows to flow current through them. Hope it helps you**.

2.

What is a good conductor?

Answer»

Answer:

GOOD CONDUCTORS is the substance that allows to flow current through them.

Hope it helps you.

Discussion

3.	Definition of BOT? What is it's relation with joule?
Answer» Answer: 1kw HOUR= 1000w hour EXPLANATION: BOARD of trade unit =BOT

3.

Definition of BOT? What is it's relation with joule?

Answer»

Answer:

1kw HOUR= 1000w hour

EXPLANATION:

BOARD of trade unit =BOT

Discussion

4.	Check the dimensional consistency of the following equations: (i) de–Broglie wavelength = h/mv
Answer» Answer: dimension is same as that of Length DE Broglie Wavelength FORMULA Questions: 1) A certain photon has momentum . What is the photon's de Broglie wavelength? Answer: The de Broglie wavelength of the photon can be found using the formula: λ = 4.42 X 10(-7) m λ = 442 x 10(-9) m λ = 442 nm The de Broglie wavelength of the photon is 442 nm. This wavelength is in the blue-violet part of the visible light spectrum

4.

Check the dimensional consistency of the following equations: (i) de–Broglie wavelength = h/mv

Answer»

Answer:

dimension is same as that of Length

DE Broglie Wavelength FORMULA Questions:

1) A certain photon has momentum . What is the photon's de Broglie wavelength?

Answer: The de Broglie wavelength of the photon can be found using the formula:

λ = 4.42 X 10(-7) m

λ = 442 x 10(-9) m

λ = 442 nm

The de Broglie wavelength of the photon is 442 nm. This wavelength is in the blue-violet part of the visible light spectrum

Discussion

5.	Can someone give explanation pllsssssCorrect explanation will be marked branliest
Answer» ANSWER: 2 (C) is the answer HOPE it HELPS

5.

Can someone give explanation pllsssssCorrect explanation will be marked branliest

Answer»

ANSWER:

2 (C) is the answer HOPE it HELPS

Discussion

6.	The force produced between two poles of a magnet is inversely proportional to the square of the distance between the poles. Justify this statement with the help of a law or mathematical relation
Answer» ANSWER: POLES of ELECTRIC mangnet

6.

The force produced between two poles of a magnet is inversely proportional to the square of the distance between the poles. Justify this statement with the help of a law or mathematical relation

Answer»

ANSWER:

POLES of ELECTRIC mangnet

Discussion

7.	I need help for each question.
Answer» Answer: . Circuit Diagram main window Easy to Use Design DIAGRAMS visually by placing components with your cursor. Modify their values using the properties EDITOR. . Plugins are AVAILABLE for additional formats. Export as images Includes all COMMON Components Symbols for most commonly-used components are included, from RESISTORS and capacitors to logic gates and transistors. Custom Components Find many more components made by other Circuit Diagram users in the components section. Create your own for ones that haven't been made yet. Share Circuit Designs Browse circuits designed by others, and upload your own in the circuits section.

7.

I need help for each question.

Answer»

Answer:

.

Circuit Diagram main window

Easy to Use

Design DIAGRAMS visually by placing components with your cursor. Modify their values using the properties EDITOR.

.

Plugins are AVAILABLE for additional formats.

Export as images

Includes all COMMON Components

Symbols for most commonly-used components are included, from RESISTORS and capacitors to logic gates and transistors.

Custom Components

Find many more components made by other Circuit Diagram users in the components section.

Create your own for ones that haven't been made yet.

Share Circuit Designs

Browse circuits designed by others, and upload your own in the circuits section.

Discussion

8.	What is the dimension of de-broglie wavelength
Answer» Answer: PLEASE MARK AS BRAINLIEST FOLLOW ME Explanation: i think.that it has no dimensions but it ie EXPRESSED in meters

8.

What is the dimension of de-broglie wavelength

Answer»

Answer:

PLEASE MARK AS BRAINLIEST
FOLLOW ME

Explanation:

i think.that it has no dimensions
but it ie EXPRESSED in meters

Discussion

9.	Part of a racing track is to be designed for a curvature of 72 m. We are not recommending the vehicles to drive faster than 216 kmph. With what angleshould the road be tilted? By what heightwill its outer edge be, with respect to theinner edge if the track is 10 m wide?
Answer» Answer: Ө = tan inverse( 5 ) Ө = 78.69 degree h = 9.805 meter Explanation: GIVEN data :- radius of curvature r = 72m VMAX = 216 km/hr = 216 x (5/18 ) = 60 m/s width of TACK = w = 10 m What we have to find out :- 1) angle should the road be tilted i.e angle of banking = Ө= ? 2) height of outer edge h = ? Solution :- 1)The angle of banking is given by, Ө = ( / RG ) = $tan^{-1}$ ( $60^{2}$ / 72 x10 ) g = 10 m/ $s^{2}$ = (3600 /720 ) Ө = ( 5 ) Ө = 78.69 degree 2) now, h = w (sin Ө) h = 10 (sin 78.69 degree ) h = 10 ( 0.9805 ) h = 9.805 meter

9.

Part of a racing track is to be designed for a curvature of 72 m. We are not recommending the vehicles to drive faster than 216 kmph. With what angleshould the road be tilted? By what heightwill its outer edge be, with respect to theinner edge if the track is 10 m wide?

Answer»

Answer:

Ө = tan inverse( 5 )

Ө = 78.69 degree

h = 9.805 meter

Explanation:

GIVEN data :-

radius of curvature r = 72m

VMAX = 216 km/hr = 216 x (5/18 ) = 60 m/s

width of TACK = w = 10 m

What we have to find out :-

1) angle should the road be tilted i.e angle of banking = Ө= ?

2) height of outer edge h = ?

Solution :-

1)The angle of banking is given by,

Ө = ( / RG )

= $tan^{-1}$ ( $60^{2}$ / 72 x10 ) g = 10 m/ $s^{2}$

= (3600 /720 )

Ө = ( 5 )

Ө = 78.69 degree

2) now,

h = w (sin Ө)

h = 10 (sin 78.69 degree )

h = 10 ( 0.9805 )

h = 9.805 meter

Discussion

10.	Can someone help me with this qn?Correct ans will be given branliest
Answer» Answer: (4) ...6.45 s is a CORRECT answer i hope UR ANSWR help .....

10.

Can someone help me with this qn?Correct ans will be given branliest

Answer»

Answer:

(4) ...6.45 s is a CORRECT answer i hope UR ANSWR help .....

Discussion

11.	calculate the resistance of 1 kilometre long copper wire of radius 1 millimetre stability of copper 1.72 into 10 power minus 8 ohm metre
Answer» $\color{darkblue}\underline{\underline{\sf Given-}}$ Lenght of copper WIRE ${\sf (\ell)=1km\:\implies\:1000m}$ Radius (R) = ${\sf 1mm\:\implies\: 10^{-3}m}$ Resistivity ${\sf (\rho)=1.72×10^{-8}ohm.m}$ $\color{darkblue}\underline{\underline{\sf To \: Find-}}$ RESISTANCE (R) ━━━━━━━━━━━━━━━━━━━━━━━━━ $\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$ $\large\color{violet}\bullet\underline{\boxed{\sf R=\rho\dfrac{\ell}{A}}}$ A = Area = πr² ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\implies{\sf R=1.7×10^{-8}×\dfrac{1000}{π×(10^{-3})^2} }$ $\implies{\sf R=1.7×10^{-8}×\dfrac{10^3}{3.14×10^{-6}}}$ $\implies{\sf R=1.7×10^{-8}\dfrac{10^{3+6}}{3.14}}$ $\implies{\sf R= \dfrac{17}{3.14}}$ $\color{red}\implies{\sf R=5.4\:Ω}$ $\color{darkblue}\underline{\underline{\sf Answer-}}$ Resistance of copper wire is $\color{red}{\sf 5.4Ω}$

11.

calculate the resistance of 1 kilometre long copper wire of radius 1 millimetre stability of copper 1.72 into 10 power minus 8 ohm metre

Answer»

$\color{darkblue}\underline{\underline{\sf Given-}}$

Lenght of copper WIRE ${\sf (\ell)=1km\:\implies\:1000m}$
Radius (R) = ${\sf 1mm\:\implies\: 10^{-3}m}$
Resistivity ${\sf (\rho)=1.72×10^{-8}ohm.m}$

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

RESISTANCE (R)

━━━━━━━━━━━━━━━━━━━━━━━━━

$\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$

$\large\color{violet}\bullet\underline{\boxed{\sf R=\rho\dfrac{\ell}{A}}}$

A = Area = πr²

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\implies{\sf R=1.7×10^{-8}×\dfrac{1000}{π×(10^{-3})^2} }$

$\implies{\sf R=1.7×10^{-8}×\dfrac{10^3}{3.14×10^{-6}}}$

$\implies{\sf R=1.7×10^{-8}\dfrac{10^{3+6}}{3.14}}$

$\implies{\sf R= \dfrac{17}{3.14}}$

$\color{red}\implies{\sf R=5.4\:Ω}$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Resistance of copper wire is $\color{red}{\sf 5.4Ω}$

Discussion

12.	on what factor does resistance of conducter depends and find out the formula for resistance in term of resisiativity
Answer» ANSWER: R=rho ×length of WIRE / AREA(CROSS SECTION)

12.

on what factor does resistance of conducter depends and find out the formula for resistance in term of resisiativity

Answer»

ANSWER:

R=rho ×length of WIRE / AREA(CROSS SECTION)

Discussion

13.	On what factor resistance of conductor depend and find out the formula
Answer» ANSWER: rjdoejz ekdodueoi KNOW WHEO ziebkwbd you veiskjzid dkkdndk

13.

On what factor resistance of conductor depend and find out the formula

Answer»

ANSWER:

rjdoejz ekdodueoi KNOW WHEO ziebkwbd you veiskjzid dkkdndk

Discussion

14.	A coin is made up of Al and weighs 0.75 g. It has a squareshape and its diagonal measures 17 mm. It is electricallyneutral and contains equal amounts of positive andnegative charges. The magnitude of these charges is
Answer» ANSWER: EXPLANATION: Mass of the coin =0.75g Atomic mass of aluminium 26.98g Number of Al atoms in the coin, N= 26.98 6.02×10 23 ×0.75=1.67×10 22 As charge number (z) Al is 13, each atom of Al CONTAIN 13s protons and 13 electrons. MAGNITUDE of positive and negative charges is one paise coin =NZe=1.67×10 22 ×13×1.6×10 ^−19 C=3.47×10 4 C

14.

A coin is made up of Al and weighs 0.75 g. It has a squareshape and its diagonal measures 17 mm. It is electricallyneutral and contains equal amounts of positive andnegative charges. The magnitude of these charges is

Answer»

ANSWER:

EXPLANATION:

Mass of the coin =0.75g

Atomic mass of aluminium 26.98g

Number of Al atoms in the coin,

N=

26.98

6.02×10

23

×0.75=1.67×10

22

As charge number (z) Al is 13, each atom of Al CONTAIN 13s protons and 13 electrons. MAGNITUDE of positive and negative charges is one paise coin

=NZe=1.67×10

22 ×13×1.6×10 ^−19

C=3.47×10

4

C

Discussion

15.	How do wind currents form? explain
Answer» Answer: HI....✋✋ Explanation: friends......WIND CURRENTS form from wind....☺️☺️☺️☺️☺️☺️☺️

15.

How do wind currents form? explain

Answer»

Answer:

HI....✋✋

Explanation:

friends......WIND CURRENTS form from wind....☺️☺️☺️☺️☺️☺️☺️

Discussion

16.	What is resistance of conductor
Answer» Answer: resistance is defined as the opposition to the flow of ELECTRICAL CURRENT through a conductor it's important to point out that conductivity and resistivity( the property that determines final resistance )are inversely PROPORTIONAL. the more CONDUCTIVE something is the less resistance it will have.

16.

What is resistance of conductor

Answer»

Answer:

resistance is defined as the opposition to the flow of ELECTRICAL CURRENT through a conductor it's important to point out that conductivity and resistivity( the property that determines final resistance )are inversely PROPORTIONAL. the more CONDUCTIVE something is the less resistance it will have.

Discussion

17.	A football player kicks a 0.94 kg football with a force of 2.4 N.Calculate the acceleration of the football as the player kicks the ball. Round your answer to the nearest tenth of a m/s2.The acceleration of the football is m/s2.
Answer» GIVEN that, Mass of football, m = 0.94 kg Force acting on the ball by the player, F = 2.4 N To FIND, The acceleration of the football as the player kicks the ball. SOLUTION, Let a is the acceleration of the football. We KNOW that force acting on an object is equal to the product of mass and acceleration. So, $F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{2.4}{0.94}\\\\a=2.55\ m/s^2$ So, the acceleration of the football as the player kicks the ball is $2.55\ m/s^2$ . Learn more, Force brainly.in/question/14814510

17.

A football player kicks a 0.94 kg football with a force of 2.4 N.Calculate the acceleration of the football as the player kicks the ball. Round your answer to the nearest tenth of a m/s2.The acceleration of the football is m/s2.

Answer»

GIVEN that,

Mass of football, m = 0.94 kg

Force acting on the ball by the player, F = 2.4 N

To FIND,

The acceleration of the football as the player kicks the ball.

SOLUTION,

Let a is the acceleration of the football. We KNOW that force acting on an object is equal to the product of mass and acceleration. So,

$F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{2.4}{0.94}\\\\a=2.55\ m/s^2$

So, the acceleration of the football as the player kicks the ball is $2.55\ m/s^2$ .

Learn more,

Force

brainly.in/question/14814510

Discussion

18.	A Car travels along a straight road 100m towards east and then 50mtowards west. Find distance and displacement of the car?
Answer» ANSWER: this is the best Explanation: MAKE me BRAINLIEST

18.

A Car travels along a straight road 100m towards east and then 50mtowards west. Find distance and displacement of the car?

Answer»

ANSWER:

this is the best

Explanation:

MAKE me BRAINLIEST

Discussion

19.	Why semiconductor are useful in compression with vaccum tube?
Answer» Answer: if you satisfied with my answer please mark me as a brainlist EXPLANATION: Unlike VACUUM tubes, semiconductors are shock-proof. Moreover, they are smaller in size and occupy less space and CONSUME less power. Compared to vacuum tubes,semiconductors are extremely SENSITIVE to temperature and radiation.

19.

Why semiconductor are useful in compression with vaccum tube?

Answer»

Answer:

if you satisfied with my answer please mark me as a brainlist

EXPLANATION:

Unlike VACUUM tubes, semiconductors are shock-proof. Moreover, they are smaller in size and occupy less space and CONSUME less power. Compared to vacuum tubes,semiconductors are extremely SENSITIVE to temperature and radiation.

Discussion

20.	A car starts from rest requires a velocity v with uniform acceleration 2 m/s then it comes to stop with uniform retardation 4 m/s . If the total time for which it remains in motion is 3 sec, the total distance travelled is:
Answer» ANSWER: 4m^2 is the CORRECT answer.

20.

A car starts from rest requires a velocity v with uniform acceleration 2 m/s then it comes to stop with uniform retardation 4 m/s . If the total time for which it remains in motion is 3 sec, the total distance travelled is:

Answer»

ANSWER:

4m^2 is the CORRECT answer.

Discussion

21.	Why diodes are useful in rectification?
Answer» $\huge\mathbb\orange{Heya\:Mate..!}$ ${\huge{\red{\underline{\underline{\mathcal Hope it's helps u }}}}}$ DIODES are widely used semiconductor device. A rectifier diode is a two-lead semiconductor that ALLOWS current to pass in only one direction. ... Rectifier diodes are a vital COMPONENT in power supplies where they are used to convert AC VOLTAGE to DC voltage

21.

Why diodes are useful in rectification?

Answer»

$\huge\mathbb\orange{Heya\:Mate..!}$

${\huge{\red{\underline{\underline{\mathcal Hope it's helps u }}}}}$

DIODES are widely used semiconductor device. A rectifier diode is a two-lead semiconductor that ALLOWS current to pass in only one direction. ... Rectifier diodes are a vital COMPONENT in power supplies where they are used to convert AC VOLTAGE to DC voltage

Discussion

22.	2 sulphide is a mixture
Answer» ANSWER: no.... Explanation: its is not a mixture PLEASE give me 5 star... please

22.

2 sulphide is a mixture

Answer»

ANSWER:

no....

Explanation:

its is not a mixture

PLEASE give me 5 star...

please

Discussion

23.	What approximate time it takes to change a day to night
Answer» $\huge\mathbb\orange{Heya\:Mate..!}$ ${\huge{\red{\underline{\underline{\mathcal Hope it's helps u }}}}}$ Our SYSTEM of telling TIME is BASED on the premise that every day is exactly 24 hours LONG ... the way around the sun (because it takes about 365 days to go all the way around .

23.

What approximate time it takes to change a day to night

Answer»

$\huge\mathbb\orange{Heya\:Mate..!}$

${\huge{\red{\underline{\underline{\mathcal Hope it's helps u }}}}}$

Our SYSTEM of telling TIME is BASED on the premise that every day is exactly 24 hours LONG ... the way around the sun (because it takes about 365 days to go all the way around .

Discussion

24.	Write the steps to induce electric current in a circular loop
Answer» Explanation: The induced current will produce induced emf which opposes this increase in the flux. So, a counter CLOCKWISE current is induced in the loop in ORDER to decrease the flux. Thus, the direction of the induced current will be There are two ways to do so. Inducing current on a coil by MOVING the coil in a magnetic field. Inducing current on a coil by by changing the magnetic field across it....

24.

Write the steps to induce electric current in a circular loop

Answer»

Explanation:

The induced current will produce induced emf which opposes this increase in the flux. So, a counter CLOCKWISE current is induced in the loop in ORDER to decrease the flux. Thus, the direction of the induced current will be

There are two ways to do so.

Inducing current on a coil by MOVING the coil in a magnetic field.

Inducing current on a coil by by changing the magnetic field across it....

Discussion

25.	Sky appears dark to passengers in aeroplane why?
Answer» Answer: Here is your answer Explanation: The sky appears dark to the passengers flying at very high altitude because at higher altitude the ATMOSPHERIC medium is very rarer so the scattering of LIGHT taking place there is very low so the passengers at very high altitude see the sky as dark. Hope it hepls GIVE answer of my QUESTION also go to profile to find question *FOLLOW* ME *MAKE* ME *BRAINLIEST*

25.

Sky appears dark to passengers in aeroplane why?

Answer»

Answer:

Here is your answer

Explanation:

The sky appears dark to the passengers flying at very high altitude because at higher altitude the ATMOSPHERIC medium is very rarer so the scattering of LIGHT taking place there is very low so the passengers at very high altitude see the sky as dark.

Hope it hepls

GIVE answer of my QUESTION also go to profile to find question

FOLLOW ME

MAKE ME BRAINLIEST

Discussion

26.	1) 6x1042) 6x10- A body has an electric charge of 10°C
Answer» Answer: 6×104=624 6×10=60 PLEASE MARK as BRANLIEST please please please FOLLOW me

26.

1) 6x1042) 6x10- A body has an electric charge of 10°C

Answer»

Answer:

6×104=624

6×10=60

PLEASE MARK as BRANLIEST

please please please FOLLOW me

Discussion

27.	What is the amount of compound of H2O
Answer» Answer: H2O Explanation: water(H2o)is a compound consisting of two hydrogen atoms bonded to an OXGEN atom the atoms WITHIN a compound can be held together by a variety interactions RANGING from covalent bonds to elctrostatic forces in IONIC bonds ....

27.

What is the amount of compound of H2O

Answer»

Answer:

H2O

Explanation:

water(H2o)is a compound consisting of two hydrogen atoms bonded to an OXGEN atom the atoms WITHIN a compound can be held together by a variety interactions RANGING from covalent bonds to elctrostatic forces in IONIC bonds ....

Discussion

28.	What is magnification mention its formula
Answer» Answer: ANS is EXPLANATION: it is OBJECTIVE lens magnification hope it will HELP you .... plzz plzz plZ folow me and mark brainliest

28.

What is magnification mention its formula

Answer»

Answer:

ANS is

EXPLANATION:

it is OBJECTIVE lens magnification

hope it will HELP you

....

plzz plzz plZ folow me and mark brainliest

Discussion

29.	A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?And the work done by the force in kilo joules?
Answer» Explanation: by second law of motion by newton FORCE =Mass×Acceleration 50N=17kg×A A=3m/s² (approx) time =v-u/a v=final VELOCITY u=initial velocity 18-0/3=6seconds DISTANCE =ut+1/2at² (second EQUATION of motion) distance =0×6+1/2×3×6² =0+1/2×3×36 =54m work =force×displacement 50×54 2700J or N.m 1000J=1KJ 2700J=2.7KJ hope you got it please mark me the brainliest

29.

A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?And the work done by the force in kilo joules?

Answer»

Explanation:

by second law of motion by newton

FORCE =Mass×Acceleration

50N=17kg×A

A=3m/s² (approx)

time =v-u/a

v=final VELOCITY u=initial velocity

18-0/3=6seconds

DISTANCE =ut+1/2at² (second EQUATION of motion)

distance =0×6+1/2×3×6²

=0+1/2×3×36

=54m

work =force×displacement

50×54

2700J or N.m

1000J=1KJ

2700J=2.7KJ

hope you got it

please mark me the brainliest

Discussion

30.	The resistor of resistance R is connected to 25volt supply and heat is produced in it is 125Js^-1. The value of R isA. 25ohmB. 1ohmC. 5ohmD. 2.25ohm
Answer» Answer: HEY dude *this* *QUESTION* *does* *not* *need* *any* *USE* *the* *formula* H=I^*2RT.......to obtain* *the* *answer...... PLEASE* *mark* my *answer* as *BRAINLIEST*

30.

The resistor of resistance R is connected to 25volt supply and heat is produced in it is 125Js^-1. The value of R isA. 25ohmB. 1ohmC. 5ohmD. 2.25ohm

Answer»

Answer:

HEY dude this QUESTION does not need any USE the formula H=I^2RT.......to obtain the answer......

PLEASE mark my answer as BRAINLIEST

Discussion

31.	A stone is projected with a velocity of 5m/s making an angle of 50° with the vertical. us there any other angle of projection the x-y plane having the same range?
Answer» Answer: dtigudyfhjv jjgckb jx jkb kchkjgckhtx kh hkchk hchk ig khckhhckg gihvgi HI h hick kh kgh hkckg kg kg ig LKG kkhjggkdgkcyfohdiyduofyodkgchlvjl hvhcjvuvjvyccjfxkhckgh hicgk. G GJ g U gixkg fu hkg gi gkxjkgxkg ugxgjxggkjf Explanation: .... plzzz plzzz mark me as brainliest

31.

A stone is projected with a velocity of 5m/s making an angle of 50° with the vertical. us there any other angle of projection the x-y plane having the same range?

Answer»

Answer:

dtigudyfhjv jjgckb jx jkb kchkjgckhtx kh hkchk hchk ig khckhhckg gihvgi HI h hick kh kgh hkckg kg kg ig LKG kkhjggkdgkcyfohdiyduofyodkgchlvjl hvhcjvuvjvyccjfxkhckgh hicgk. G GJ g U gixkg fu hkg gi gkxjkgxkg ugxgjxggkjf

Explanation:

....

plzzz plzzz mark me as brainliest

Discussion

32.	An aluminium sheet of length 30m is made into cone for temperature delT=300K, coefficient of longitudinal expansion=23×10^-6 K^-1 find the change in length??A. 303mB. 50.22mC. 1.06×10^-4D. 0.207m
Answer» ANSWER: A OPTION in my OPINION is the RIGHT answer

32.

An aluminium sheet of length 30m is made into cone for temperature delT=300K, coefficient of longitudinal expansion=23×10^-6 K^-1 find the change in length??A. 303mB. 50.22mC. 1.06×10^-4D. 0.207m

Answer»

ANSWER:

A OPTION in my OPINION is the RIGHT answer

Discussion

33.	Distance travel in 2 hour in 25 kilometers find the average speed and average velocity
Answer» ANSWER: SPEED = $\frac{Distance}{Time}$ = $\frac{25}{2}$ kmph = 12.5 kmph Velocity = Speed as Displacement is not GIVEN [ velocity = $\frac{Displacement}{Time}$ ]

33.

Distance travel in 2 hour in 25 kilometers find the average speed and average velocity

Answer»

ANSWER:

SPEED = $\frac{Distance}{Time}$

= $\frac{25}{2}$ kmph

= 12.5 kmph

Velocity = Speed as Displacement is not GIVEN

[ velocity = $\frac{Displacement}{Time}$ ]

Discussion

34.	a point charge q1 exerts a force f upon another point charge q2 .if third charge q3 be placed quite close to the charge q2 then the force that charge q1 exerts on the charge q2 will be
Answer» ANSWER: the FORCE will be same.

34.

a point charge q1 exerts a force f upon another point charge q2 .if third charge q3 be placed quite close to the charge q2 then the force that charge q1 exerts on the charge q2 will be

Answer»

ANSWER:

the FORCE will be same.

Discussion

35.	The secondary voltage is 220 V, then the current in the secondary collis(A)20 A(8) 2A(C) 4A(D) 22 AThe four steps of manufacturing common sugar are given in wrong orderConcentration and crystallization of juice(b)Purification of juice.(c)Separation and drying of crystals.Extraction of juice from the sourceThe correct art angement of these steps is(A)b, d, c, a(B) da, bt10)a, c, d, b(D) d, b, a,PR (D)-50017
Answer» Answer: hey dude you MUST TRY this QUESTION by your own.......it will COME automatically

35.

The secondary voltage is 220 V, then the current in the secondary collis(A)20 A(8) 2A(C) 4A(D) 22 AThe four steps of manufacturing common sugar are given in wrong orderConcentration and crystallization of juice(b)Purification of juice.(c)Separation and drying of crystals.Extraction of juice from the sourceThe correct art angement of these steps is(A)b, d, c, a(B) da, bt10)a, c, d, b(D) d, b, a,PR (D)-50017

Answer»

Answer:

hey dude

you MUST TRY this QUESTION by your own.......it will COME automatically

Discussion

36.	Definite photons in terms of electromagnetic
Answer» Explanation: Photons are massless particles of definite energy, definite MOMENTUM, and definite spin. In order to explain the photoelectric effect, Einstein assumed heuristically in 1905 that an electromagnetic FIELD consists of particles of energy of amount hν, where h is PLANCK's constant and ν is the wave frequency. hope it WORKS out mark as Brain list ......

36.

Definite photons in terms of electromagnetic

Answer»

Explanation:

Photons are massless particles of definite energy, definite MOMENTUM, and definite spin. In order to explain the photoelectric effect, Einstein assumed heuristically in 1905 that an electromagnetic FIELD consists of particles of energy of amount hν, where h is PLANCK's constant and ν is the wave frequency.

hope it WORKS out

mark as Brain list ......

Discussion

37.	A uniform wire 2m long fixed at its upper end has a weight attached at its lower end. If the strain energy per unit volume of the wire is 2.5 J per m3 and the increase in length per unit length is 2 x 10-2 m, find: (Strain energy= 1⁄2 (strain)^2 E)a. the Young modulusb. the stress in the wire.
Answer» ANSWER: nanoarwej wkowfve eowyqfwn woowd181 w8u2tvw s9e2u2

37.

A uniform wire 2m long fixed at its upper end has a weight attached at its lower end. If the strain energy per unit volume of the wire is 2.5 J per m3 and the increase in length per unit length is 2 x 10-2 m, find: (Strain energy= 1⁄2 (strain)^2 E)a. the Young modulusb. the stress in the wire.

Answer»

ANSWER:

nanoarwej wkowfve eowyqfwn woowd181 w8u2tvw s9e2u2

Discussion

38.	Solar-powered cars use energy from the Sun to work. A panel on the car absorbs light energy from the Sun, which then generates an electric current. This electric current, in turn, allows the car to move. Which shows the correct order of energy transformations that take place in a solar-powered car?electrical, chemical, kineticelectrical, kinetic, radiantradiant, chemical, electricalradiant, electrical, mechanical
Answer» Answer: RADIANT, electrical, MECHANICAL Explanation: the solar panal OBSERVE the light energy and convert into electrical energy it COVERT into mechanical energy

38.

Solar-powered cars use energy from the Sun to work. A panel on the car absorbs light energy from the Sun, which then generates an electric current. This electric current, in turn, allows the car to move. Which shows the correct order of energy transformations that take place in a solar-powered car?electrical, chemical, kineticelectrical, kinetic, radiantradiant, chemical, electricalradiant, electrical, mechanical

Answer»

Answer:

RADIANT, electrical, MECHANICAL

Explanation:

the solar panal OBSERVE the light energy and convert into electrical energy it COVERT into mechanical energy

Discussion

39.	Assuming Young's modulus for brass to be 1010 Pa, find the energy stored in a rod of cross sectional area 1 cm2 and 10 cm in length if compressed by a load of 100 N.
Answer» EXPLANATION: jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa smmsmsmsmsmsmsmsmmsmsms smmsmsm

39.

Assuming Young's modulus for brass to be 1010 Pa, find the energy stored in a rod of cross sectional area 1 cm2 and 10 cm in length if compressed by a load of 100 N.

Answer»

EXPLANATION:

jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa jwjsjsijdmssiismdjdismsmooqwkxmxmmmzkaqpaa smmsmsmsmsmsmsmsmmsmsms smmsmsm

Discussion

40.	Velocity of a particle at time t =0 is 2m/s . A constant acceleration of 2 m/s2 acts on the particle for 2 sec at an angle of 60 with its initial velocity . find it magnitude of velocity and displacement of the particle at the end of t = 2s ?
Answer» Answer: final velocity = 4m/s displacement = 12m Explanation: as given initial velocity of particle v=2m/s ACCELERATION of particle in direction of initial velocity a=(2×cos60)m/s^2 a=1m/sec^2 time given, t=2sec to find final velocity we use laws of motion v'=v+at v'=2+(1×2) v'=4m/s to find displacement we use s=vt+1/2a(t^2) s=(2×2)+(2×1×4) s=12m perpendicular component of acceleration balances the weight of the body so we have a VERTICAL equilibrium and it doesn't affect the HORIZONTAL motion of the body so we can IGNORE it

40.

Velocity of a particle at time t =0 is 2m/s . A constant acceleration of 2 m/s2 acts on the particle for 2 sec at an angle of 60 with its initial velocity . find it magnitude of velocity and displacement of the particle at the end of t = 2s ?

Answer»

Answer:

final velocity = 4m/s

displacement = 12m

Explanation:

as given initial velocity of particle

v=2m/s

ACCELERATION of particle in direction of initial velocity

a=(2×cos60)m/s^2

a=1m/sec^2

time given, t=2sec

to find final velocity we use laws of motion

v'=v+at

v'=2+(1×2)

v'=4m/s

to find displacement we use

s=vt+1/2a(t^2)

s=(2×2)+(2×1×4)

s=12m

perpendicular component of acceleration balances the weight of the body so we have a VERTICAL equilibrium and it doesn't affect the HORIZONTAL motion of the body so we can IGNORE it

Discussion

41.	A particle moves in a straight line with constant acceleration . if it covers 10 m in first second and extra 10 m is next second ,find its initial velocity ?
Answer» ANSWER: the answer is in the picture Explanation:

41.

A particle moves in a straight line with constant acceleration . if it covers 10 m in first second and extra 10 m is next second ,find its initial velocity ?

Answer»

ANSWER:

the answer is in the picture

Explanation:

Discussion

42.	What do you mean by charging by Charging by friction, Charging by conduction and Charging by induction???
Answer» Charging by friction:- When you rub one material to another, they are charged by friction. Material LOSING electron is positively charged and material gaining electron is negatively charged. Amount of gained and lost electron is equal to each other. In other words, we can say that charges of the system are conserved.❤️ charging by conduction:-Charging by conduction involves the contact of a charged object to a neutral object. Hence when an uncharged conductor is brought in contact with a charged conductor, charge is SHARED between the TWO conductors and hence the uncharged conductor gets charged.❤️ charging by induction:-Charging by Induction. When charging a conductor by induction, a charged object is brought close to but does not touch the conductor. In the end the conductor has charge of the opposite SIGN as the charge on the object.❤️

42.

What do you mean by charging by Charging by friction, Charging by conduction and Charging by induction???

Answer»

Charging by friction:- When you rub one material to another, they are charged by friction. Material LOSING electron is positively charged and material gaining electron is negatively charged. Amount of gained and lost electron is equal to each other. In other words, we can say that charges of the system are conserved.❤️

charging by conduction:-Charging by conduction involves the contact of a charged object to a neutral object. Hence when an uncharged conductor is brought in contact with a charged conductor, charge is SHARED between the TWO conductors and hence the uncharged conductor gets charged.❤️

charging by induction:-Charging by Induction. When charging a conductor by induction, a charged object is brought close to but does not touch the conductor. In the end the conductor has charge of the opposite SIGN as the charge on the object.❤️

Discussion

43.	How do you find the constant force being applied to an objectmass: 15kg being pulledcoefficient of kinetic friction: 0.30moves 5.0m in 4.0s
Answer» Explanation: hope it may HELP you when a constant force ACTS on a massive BODY , it causes it to accelerate that is to change its VELOCITY ,at a constant rate . In the simplest case , a force applied to an object at rest causes it to accelerate the direction of the force. Plzzzz mark me as brainlist

43.

How do you find the constant force being applied to an objectmass: 15kg being pulledcoefficient of kinetic friction: 0.30moves 5.0m in 4.0s

Answer»

Explanation:

hope it may HELP you

when a constant force ACTS on a massive BODY , it causes it to accelerate that is to change its VELOCITY ,at a constant rate .

In the simplest case , a force applied to an object at rest causes it to accelerate the direction of the force.

Plzzzz mark me as brainlist

Discussion

44.	In the adjoining figure shown three particles A B and C which are equally charged the force acting on B due to a is 2.0 10 to the power minus 6 Newton find out in each figure force exerted on BBC connect one the net force on b
Answer» ANSWER: POST the FIGURE ALSO..

44.

In the adjoining figure shown three particles A B and C which are equally charged the force acting on B due to a is 2.0 10 to the power minus 6 Newton find out in each figure force exerted on BBC connect one the net force on b

Answer»

ANSWER:

POST the FIGURE ALSO..

Discussion

45.	please help me solve the following questions. I think Ive got the answers for a-d. But I don't understand question e). please explain the steps for each question
Answer» ANSWER: 54.3N Explanation: FRICTIONAL force is given by (ų)(N) Where ų is coefficient of friction and N is normal force Hence Friction=45N F-45=15a where F is the constant force F=45+15a----(1) Since distance(s)=5m Time(t)=4s Initial velocity(U)=0 Using s=ut+0.5(a)(t^2) 5=8a a=8/5----(2) Using (1) and(2) We get F =54.3N Hope this answer helped you

45.

please help me solve the following questions. I think Ive got the answers for a-d. But I don't understand question e). please explain the steps for each question

Answer»

ANSWER:

54.3N

Explanation:

FRICTIONAL force is given by (ų)(N)

Where ų is coefficient of friction and N is normal force

Hence Friction=45N

F-45=15a where F is the constant force

F=45+15a----(1)

Since distance(s)=5m

Time(t)=4s

Initial velocity(U)=0

Using s=ut+0.5(a)(t^2)

5=8a

a=8/5----(2)

Using (1) and(2)

We get F =54.3N

Hope this answer helped you

Discussion

46.	Drawing free body diagrams for the scenarios below
Answer» EXPLANATION: Free-body diagrams are diagrams USED to show the relative magnitude and DIRECTION of all forces acting upon an object in a GIVEN situation. A free-body diagram is a special example of the vector diagramsthat were discussed in an earlier unit.

46.

Drawing free body diagrams for the scenarios below

Answer»

EXPLANATION:

Free-body diagrams are diagrams USED to show the relative magnitude and DIRECTION of all forces acting upon an object in a GIVEN situation. A free-body diagram is a special example of the vector diagramsthat were discussed in an earlier unit.

Discussion

47.	The resultant of two forces 2 KN and 6 kN which are acting at an angle 30 is
Answer» ANSWER: HEY ! .. √{2²+6²+2×2×6 cos30} =√{4+36+12√3} =√{40+12√3} =7.79 =7.8 kN HOPE it HELPS..

47.

The resultant of two forces 2 KN and 6 kN which are acting at an angle 30 is

Answer»

ANSWER:

HEY ! ..

√{2²+6²+2×2×6 cos30}

=√{4+36+12√3}

=√{40+12√3}

=7.79 =7.8 kN

HOPE it HELPS..

Discussion

48.	A stone is projected with velocity of 5m/s making an angle of 50° with vertical. Calculate the range.
Answer» Answer: 1.29m Explanation: The range is GIVEN by formula R=u SQARE Sine2(angle) divided by g So here R=25sin(250)/9.8 = -1.29m Means it will be opposite diraction of through

48.

A stone is projected with velocity of 5m/s making an angle of 50° with vertical. Calculate the range.

Answer»

Answer:

1.29m

Explanation:

The range is GIVEN by formula

R=u SQARE Sine2(angle) divided by g

So here

R=25*sin(2*50)/9.8

= -1.29m

Means it will be opposite diraction of through

Discussion

49.	Mass of block is 8 kg. The minimal force required to move the block up if the coffiction of friction µ = 0.3. Take g = 10 m.s-2
Answer» Answer: 67.3 N Explanation: An diagram is attached for better understanding. Here, Normal REACTION is EQUAL to mg.cos37° So, Friction on block is μ . mg. cos37° ⇒ 0.3 x mg x cos37° Also, one of the component of weight is acted with the friction. Total force acted opposite the force for lifting is ( 0.3 mg . cos37° ) + ( mg sin37° ) MINIMUM force required = ( 0.3 mg cos37° ) + ( mg sin37° ) ⇒ mg( 0.3 cos37° + sin37° ) You can USE the approx values of cos37° and sin37°, here, I am directly writing 0.3 cos37° + sin37° as 0.8414 ⇒ 8 x 10( 0.8414 ) N ⇒ 8 x 8.414 N ⇒ 67.3 N ( approx ) MIN. force required is 67.3 N

49.

Mass of block is 8 kg. The minimal force required to move the block up if the coffiction of friction µ = 0.3. Take g = 10 m.s-2

Answer»

Answer:

67.3 N

Explanation:

An diagram is attached for better understanding.

Here,

Normal REACTION is EQUAL to mg.cos37°

So,

Friction on block is μ . mg. cos37°

⇒ 0.3 x mg x cos37°

Also, one of the component of weight is acted with the friction.

Total force acted opposite the force for lifting is ( 0.3 mg . cos37° ) + ( mg sin37° )

MINIMUM force required = ( 0.3 mg cos37° ) + ( mg sin37° )

⇒ mg( 0.3 cos37° + sin37° )

You can USE the approx values of cos37° and sin37°, here, I am directly writing 0.3 cos37° + sin37° as 0.8414

⇒ 8 x 10( 0.8414 ) N

⇒ 8 x 8.414 N

⇒ 67.3 N ( approx )

MIN. force required is 67.3 N

Discussion

50.	In the above circuit, find VE – VG. Assume the battery to be ideal.(Resistance between C and D is 2 ohm
Answer» ANSWER: HEY , PLZZ ATTACH the DIGRAM.. hope it helps..

50.

In the above circuit, find VE – VG. Assume the battery to be ideal.(Resistance between C and D is 2 ohm

Answer»

ANSWER:

HEY , PLZZ ATTACH the DIGRAM..

hope it helps..

Discussion

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