67486 + Interview Questions in Secondary School in Physics

1.	Determine the moment of the force about point P
Answer» Answer: HEY PLZZ refer to attachment.. moment of force means torque HOPE it helps..

1.

Determine the moment of the force about point P

Answer»

Answer:

HEY PLZZ refer to attachment..

moment of force means torque

HOPE it helps..

Discussion

2.	When one unit electric charge from one point to another point in a electric circuit then the amount of work done in joule is known as
Answer» ANSWER: it is CALLED POTENTIAL ENERGY ......

2.

When one unit electric charge from one point to another point in a electric circuit then the amount of work done in joule is known as

Answer»

ANSWER:

it is CALLED POTENTIAL ENERGY ......

Discussion

3.	GAUSS’ S LAW help me.I'm looking for a genius of physics.
Answer» Explanation: 1st one is DERIVATION you can go to YouTube In SECOND one you have to be clear about induction of CHARGE and then find electric field at different positions As inner surface is NEGATIVELY CHARGED and outer one is positively charged And the charge will be equal at all surfaces (3microcoulmb) In third one I m not getting it clearly

3.

GAUSS’ S LAW help me.I'm looking for a genius of physics.

Answer»

Explanation:

1st one is DERIVATION you can go to YouTube

In SECOND one you have to be clear about induction of CHARGE and then find electric field at different positions

As inner surface is NEGATIVELY CHARGED and outer one is positively charged

And the charge will be equal at all surfaces (3microcoulmb)

In third one I m not getting it clearly

Discussion

4.	State the various factors affecting the rate of evaporation of a liquid.
Answer» Explanation: Factors That AFFECT the RATE of Evaporation temperature of the liquid. A cup of hot WATER will evaporate more quickly than a cup of cold water. exposed surface area of the liquid. ... presence or absence of other substances in the liquid. ... air movement. ... concentration of the evaporating substance in the air. hope it WORKS out mark as Brain list .....

4.

State the various factors affecting the rate of evaporation of a liquid.

Answer»

Explanation:

Factors That AFFECT the RATE of Evaporation

temperature of the liquid. A cup of hot WATER will evaporate more quickly than a cup of cold water.

exposed surface area of the liquid. ...

presence or absence of other substances in the liquid. ...

air movement. ...

concentration of the evaporating substance in the air.

hope it WORKS out

mark as Brain list .....

Discussion

5.	The resultant of two forces 2 KN and 6 kN which are acting at an angle 300 is
Answer» Units are not written in calculation. Answer: 2√13 kN. Explanation: 300° can be written as 360° - 60° ⇒ 2π - 60°. We know, period of cosine is 2π, so cos( 300° ) will be as same as cos( - 60° ) which is cos( 60° ), SINCE cos( - 60° ) = cos( 60° ). Resultant of those forces : ⇒ √[(2)^2 + (6)^2 + 2(26cos60°)] ⇒ √[ 4 + 36 + 2(261/2)] ⇒ √[ 40 + 12 ] ⇒ √52 ⇒ 2√13 HENCE, resultant is 2√13 kN.

5.

The resultant of two forces 2 KN and 6 kN which are acting at an angle 300 is

Answer»

Units are not written in calculation.

Answer:

2√13 kN.

Explanation:

300° can be written as 360° - 60° ⇒ 2π - 60°.

We know, period of cosine is 2π, so cos( 300° ) will be as same as cos( - 60° ) which is cos( 60° ), SINCE cos( - 60° ) = cos( 60° ).

Resultant of those forces :

⇒ √[(2)^2 + (6)^2 + 2(2*6*cos60°)]

⇒ √[ 4 + 36 + 2(2*6*1/2)]

⇒ √[ 40 + 12 ]

⇒ √52

⇒ 2√13

HENCE, resultant is 2√13 kN.

Discussion

6.	What will be the minimum diameter of a steel wire, which is used to raise a load of 4000N if the stress in the rod is not to exceed 95 MN/m2?
Answer» ANSWER : From the Question, Force (F) = 4 × 10³ N Stress = 95 MN/m² = 95 × 10^-3 N/m² To finD Diameter of the STEEL WIRE Stress : Force acting per unit area of the object $\sf Stress = \dfrac{F}{A} \\ \\ \dashrightarrow \sf Stress = \dfrac{F}{\pi r^<klux>2</klux>}$ Putting the values, we get : $\dashrightarrow \: \sf \: 95 \times {10}^{ - 2} = \dfrac{4 \times {10}^{3} }{3.14 \: \times {r}^{2} } \\ \\ \dashrightarrow \: \sf \: {r}^{2} = \dfrac{4 \times {10}^{5} }{3.14 \times 95} \\ \\ \dashrightarrow \: \sf \: r {}^{2} = \dfrac{4 \times {10}^{7} }{298.3} \\ \\ \dashrightarrow \: \sf \: {r}^{2} = 13.41 \\ \\ \dashrightarrow \: \boxed{ \boxed{ \sf r =3.66 \: m }}$ WKT, D = 2r = 2(3.66) = 7.32 m Thus,the diameter of the steel wire should be atleast 7.32 m

6.

What will be the minimum diameter of a steel wire, which is used to raise a load of 4000N if the stress in the rod is not to exceed 95 MN/m2?

Answer»

ANSWER :

From the Question,

Force (F) = 4 × 10³ N

Stress = 95 MN/m² = 95 × 10^-3 N/m²

To finD

Diameter of the STEEL WIRE

Stress : Force acting per unit area of the object

$\sf Stress = \dfrac{F}{A} \\ \\ \dashrightarrow \sf Stress = \dfrac{F}{\pi r^<klux>2</klux>}$

Putting the values, we get :

$\dashrightarrow \: \sf \: 95 \times {10}^{ - 2} = \dfrac{4 \times {10}^{3} }{3.14 \: \times {r}^{2} } \\ \\ \dashrightarrow \: \sf \: {r}^{2} = \dfrac{4 \times {10}^{5} }{3.14 \times 95} \\ \\ \dashrightarrow \: \sf \: r {}^{2} = \dfrac{4 \times {10}^{7} }{298.3} \\ \\ \dashrightarrow \: \sf \: {r}^{2} = 13.41 \\ \\ \dashrightarrow \: \boxed{ \boxed{ \sf r =3.66 \: m }}$

WKT,

D = 2r = 2(3.66) = 7.32 m

Thus,the diameter of the steel wire should be atleast 7.32 m

Discussion

7.	The normal force between two surfaces is 100 N and the coefficient of friction is 0.4. The force required to pull the object is
Answer» Answer: CLEARLY force = coefficient of FRICTION /NORMAL force f= 0.4/100 =0.004 N

7.

The normal force between two surfaces is 100 N and the coefficient of friction is 0.4. The force required to pull the object is

Answer»

Answer:

CLEARLY

force = coefficient of FRICTION /NORMAL force

f= 0.4/100

=0.004 N

Discussion

8.	a force of 1.2N is applied to an object of mass 1.5kg. object is accelerating at 0.5m/s2(left). Determine the force of friction that is acting on it.
Answer» Answer: 0.45 N. Explanation: Here, Force applied on the object is 1.2 N. According the equation F = ma. force of 1.2 N MUST equal to the product of 1.5 kg( m ) and 0.5m/s^2 ( a ). But, 1.2 ≠ 1.5 x 0.5, it MEANS, there's some FRICTION and a little amount of force is USED to overcome that friction. apparent force( which LOOKS like acted upon the body ) is 1.5 x 0.5 N Force by friction = force applied - the apparent force ⇒ Force by friction = 1.2 N - ( 1.5 x 0.5 ) N ⇒ 1.2 N - 0.75 N ⇒ 0.45 N Hence the friction force of 0.45 N is acting on the body.

8.

a force of 1.2N is applied to an object of mass 1.5kg. object is accelerating at 0.5m/s2(left). Determine the force of friction that is acting on it.

Answer»

Answer:

0.45 N.

Explanation:

Here,

Force applied on the object is 1.2 N.

According the equation F = ma.

force of 1.2 N MUST equal to the product of 1.5 kg( m ) and 0.5m/s^2 ( a ).

But, 1.2 ≠ 1.5 x 0.5, it MEANS, there's some FRICTION and a little amount of force is USED to overcome that friction.

apparent force( which LOOKS like acted upon the body ) is 1.5 x 0.5 N

Force by friction = force applied - the apparent force

⇒ Force by friction = 1.2 N - ( 1.5 x 0.5 ) N

⇒ 1.2 N - 0.75 N

⇒ 0.45 N

Hence the friction force of 0.45 N is acting on the body.

Discussion

9.	When wire cable exist?????
Answer» Answer: A wire is a single, USUALLY cylindrical, flexible strand or rod of metal. Wires are used to bear mechanical loads or ELECTRICITY and telecommunications signals. Wire is commonly formed by drawing the metal through a hole in a DIE or draw plate. Wire gauges come in various standard sizes, as EXPRESSED in terms of a gauge number. The term 'wire' is also used more loosely to refer to a bundle of such strands, as in "multistranded wire", which is more correctly termed a wire rope in mechanics, or a cable in electricity.

9.

When wire cable exist?????

Answer»

Answer:

A wire is a single, USUALLY cylindrical, flexible strand or rod of metal. Wires are used to bear mechanical loads or ELECTRICITY and telecommunications signals. Wire is commonly formed by drawing the metal through a hole in a DIE or draw plate. Wire gauges come in various standard sizes, as EXPRESSED in terms of a gauge number. The term 'wire' is also used more loosely to refer to a bundle of such strands, as in "multistranded wire", which is more correctly termed a wire rope in mechanics, or a cable in electricity.

Discussion

10.	two particles A and B having charges of +2x10^-6 & - 4x10^-6 respectively are held fixed at a seperation of 20 cm. Locate the points on the line AB where (a) electric field is 0 (b) the electric potential is 0
Answer» Since two charges are of OPPOSITE sign , so the point at which electric field is zero lies outside the system. let x cm be the distance of the point from charge 2×10-6 C. distance from the -4×10-6 C is (20+x) cm. therefore,k×2×10-6x2 = k×4×10-6(20+x)2we getx = 20(1±2)since point lies outside the system , we take only positive sign.x = 20(1+2) cm Let d be the distance from the charge 2×10-6 C at which potential is zero. Since potential is scalar quantity , this point lies inside the system. k×2×10-6d + k×-4×10-620-d = 0we getd = 20/3 cm If you satisfy on my answer PLEASE mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️

10.

two particles A and B having charges of +2x10^-6 & - 4x10^-6 respectively are held fixed at a seperation of 20 cm. Locate the points on the line AB where (a) electric field is 0 (b) the electric potential is 0

Answer»

Since two charges are of OPPOSITE sign , so the point at which electric field is zero lies outside the system.

let x cm be the distance of the point from charge 2×10-6 C.

distance from the -4×10-6 C is (20+x) cm.

therefore,k×2×10-6x2 = k×4×10-6(20+x)2we getx = 20(1±2)since point lies outside the system , we take only positive sign.x = 20(1+2) cm

Let d be the distance from the charge 2×10-6 C at which potential is zero. Since potential is scalar quantity , this point lies inside the system.

k×2×10-6d + k×-4×10-620-d = 0we getd = 20/3 cm

If you satisfy on my answer PLEASE mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️

Discussion

11.	Please give clear explination if u know the right answer
Answer» Answer: 8m/s , 6m/s2 Explanation: for third second it is 19 , for seventh second it is 43 , so, 43 - 19 = 24, and TIME DIFFERENCE is 4 sec. putting this all together in 2 formulae (I.e) VELOCITY and acceleration and get the answer.

11.

Please give clear explination if u know the right answer

Answer»

Answer:

8m/s , 6m/s2

Explanation:

for third second it is 19 ,

for seventh second it is 43 ,

so, 43 - 19 = 24, and TIME DIFFERENCE is 4 sec. putting this all together in 2 formulae (I.e) VELOCITY and acceleration and get the answer.

Discussion

12.	A long wire and a short wire of the same material are connected to the same circuit tofind their respective resistance. Which one will have lower resistance? Give reason.
Answer» Answer: small WIRE will have low resistance because it is one of the FACTOR lenght is DIRECTLY proportional to the area of cross SECTION

12.

A long wire and a short wire of the same material are connected to the same circuit tofind their respective resistance. Which one will have lower resistance? Give reason.

Answer»

Answer:

small WIRE will have low resistance because it is one of the FACTOR lenght is DIRECTLY proportional to the area of cross SECTION

Discussion

13.	An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.?
Answer» ANSWER :- $\implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }} \:$ Explanation :- ACCORDING to the QUESTION , $\implies \sf{radius \: (r) = 42.250 \: km \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{r= \: \: \: 42.250 \times 1000 \: metre \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ r = 42250 \: m \: } \\ \\ \to \sf{time \: (t) = 24 \: hours = 86400 \: seconds \: }$ LET distance covered by satellite is D . Distance covered by satellite in 24 hours is - $\to \sf{ D \: = 2 \pi \: r} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 42250 \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 265330 \: m \:$ Hence ,linear velocity(v) is - $\implies \sf{ v \: = \frac{D}{t}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{265330}{86400} = 3.07 \: \frac{m}{s} \\ \\ \implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }}$

13.

An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.?

Answer»

ANSWER :-

$\implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }} \:$

Explanation :-

ACCORDING to the QUESTION ,

$\implies \sf{radius \: (r) = 42.250 \: km \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{r= \: \: \: 42.250 \times 1000 \: metre \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ r = 42250 \: m \: } \\ \\ \to \sf{time \: (t) = 24 \: hours = 86400 \: seconds \: }$

LET distance covered by satellite is D .

Distance covered by satellite in 24 hours is -

$\to \sf{ D \: = 2 \pi \: r} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 42250 \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 265330 \: m \:$

Hence ,linear velocity(v) is -

$\implies \sf{ v \: = \frac{D}{t}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{265330}{86400} = 3.07 \: \frac{m}{s} \\ \\ \implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }}$

Discussion

14.	The velocity-time graph shows the motion of a cyclist. Find(i) its acceleration(ii) its velocity(iii) the distance covered by the cyclist in 15 seconds
Answer» Explanation: (1) since VELOCITY of cyclist is not changing so, acceleration will be zero(0). (2) reading the graph, velocity = 20ms^-1. (3) s = ut = 20×15 = 300m. please FOLLOW me and mark it as BRAINLIEST.

14.

The velocity-time graph shows the motion of a cyclist. Find(i) its acceleration(ii) its velocity(iii) the distance covered by the cyclist in 15 seconds

Answer»

Explanation:

(1) since VELOCITY of cyclist is not changing so, acceleration will be zero(0).

(2) reading the graph, velocity = 20ms^-1.

(3) s = ut = 20×15 = 300m.

please FOLLOW me and mark it as BRAINLIEST.

Discussion

15.	Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (v0v0) and the braking capacity, or deceleration, ?a that is caused by the braking. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s2. Find the stopping distance of the car
Answer» ANSWER is 80 m Explanation:

15.

Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (v0v0) and the braking capacity, or deceleration, ?a that is caused by the braking. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s2. Find the stopping distance of the car

Answer»

ANSWER is 80 m

Explanation:

Discussion

16.	Kindly help me with this
Answer» Is *this* *QUESTION* is of *CLASS* *8TH*???

Discussion

17.	If the space around the body with mass is gravitational field and the space around the body with electric charge is electric field and proton is a body with mass and electric charge, what is the space around a proton called? Does that mean that electric and gravitational fields are the same thing?
Answer» Answer: GOOD QUESTION i m not sure what is the space called but electric and gravitational field cannot be the same. Explanation: electric field completely DEPENDS on charges and is not at all connected with mass of the OBJECT it doesn't depend on mass of the object but surely depends on charge which is carried by the object gravitational field has no connection with charges it is irrelevant to charge of the object but completely depends on mass of the object. HOPE it helps u if not then let me know I will surely COME up with more info and then HELP u again with this BUT YAAR THIS WAS REALLY A GOOD QUESTION........

17.

If the space around the body with mass is gravitational field and the space around the body with electric charge is electric field and proton is a body with mass and electric charge, what is the space around a proton called? Does that mean that electric and gravitational fields are the same thing?

Answer»

Answer:

GOOD QUESTION

i m not sure what is the space called

but electric and gravitational field cannot be the same.

Explanation:

electric field completely DEPENDS on charges and is not at all connected with mass of the OBJECT it doesn't depend on mass of the object but surely depends on charge which is carried by the object

gravitational field has no connection with charges it is irrelevant to charge of the object but completely depends on mass of the object.

HOPE it helps u if not then let me know I will surely COME up with more info and then HELP u again with this

BUT YAAR THIS WAS REALLY A GOOD QUESTION........

Discussion

18.	Who know Nelson mendela????
Answer» ANSWER: President of South AFRICA Explanation: He was the president of South Africa from 1994 to 1999

18.

Who know Nelson mendela????

Answer»

ANSWER:

President of South AFRICA

Explanation:

He was the president of South Africa from 1994 to 1999

Discussion

19.	Why semiconductor are so usefull while good conductors are already available ?
Answer» Answer: At high temperatures these SEMICONDUCTORS are relatively good conductors because there are a larger number of ELECTRONS in the conduction band and holes in the valence band available for electron MOVEMENT. ... That extra electron is available to carry a current. Explanation: Hope it will help you... Mark me as Brainlist.

19.

Why semiconductor are so usefull while good conductors are already available ?

Answer»

Answer:

At high temperatures these SEMICONDUCTORS are relatively good conductors because there are a larger number of ELECTRONS in the conduction band and holes in the valence band available for electron MOVEMENT. ... That extra electron is available to carry a current.

Explanation:

Hope it will help you...

Mark me as Brainlist.

Discussion

20.	The body has weight of 200N when it is at distance of 4600Km above earth centre.If body is shifted to some distance the weight of body become 50N. Calculate the distance.
Answer» ANSWER: Explanation: EXPLANATORY SOLUTION is ILLUSTRATED in the pictures below :-

20.

The body has weight of 200N when it is at distance of 4600Km above earth centre.If body is shifted to some distance the weight of body become 50N. Calculate the distance.

Answer»

ANSWER:

Explanation: EXPLANATORY SOLUTION is ILLUSTRATED in the pictures below :-

Discussion

21.	Compare the power consumed by the 2 ohm resistance in the following circuit
Answer» ANSWER: Thanks See attach Explanation:

21.

Compare the power consumed by the 2 ohm resistance in the following circuit

Answer»

ANSWER:

Thanks

See attach

Explanation:

Discussion

22.	A coil of 20 Ω resistance is joined in parallel with a coil of R Ω resistance. This combination is then joined in series with a piece of apparatus A, and the whole circuit connected to 100 V mains. What must be the value of R so that A shall dissipate 600 W with 10 A passing through it?
Answer» Given : 20Ω resistance & R is connected in parallel & whole COMBINATION is connected to A such that 600 W power is dissipated from A when connected across 100V & 10 A current passes through it. To Find : VALUE of R Solution: •Power dissipated across A is 600W when 10A of current passes through it . •Also , P = VI where P is power dissipated V is potential DIFFERENCE across A I is current through A => 600 = V(10) => V = 60V •So , potential difference across A is 60V => potential difference across R & 20Ω is 40V •Since , this parallel combination is connected in series with A => Current through parallel combination of 20Ω & R is 10A •By ohm's LAW V = IR 40 = 10Req => Req = 4Ω also , For parallel combination 1/Req = 1/R1 + 1/R2 1/4 = 1/20 + 1/R 1/4 = (R+20)/20R 20R = 4R + 80 16R = 80 => R = 5Ω •Hence , Value of R is 5 Ω

22.

A coil of 20 Ω resistance is joined in parallel with a coil of R Ω resistance. This combination is then joined in series with a piece of apparatus A, and the whole circuit connected to 100 V mains. What must be the value of R so that A shall dissipate 600 W with 10 A passing through it?

Answer»

Given :

20Ω resistance & R is connected in parallel & whole COMBINATION is connected to A such that 600 W power is dissipated from A when connected across 100V & 10 A current passes through it.

To Find :

VALUE of R

Solution:

•Power dissipated across A is 600W when 10A of current passes through it .

•Also , P = VI

where P is power dissipated

V is potential DIFFERENCE across A

I is current through A

=> 600 = V(10)

=> V = 60V

•So , potential difference across A is 60V

=> potential difference across R & 20Ω is 40V

•Since , this parallel combination is connected in series with A

=> Current through parallel combination of 20Ω & R is 10A

•By ohm's LAW

V = IR

40 = 10Req

=> Req = 4Ω

also , For parallel combination

1/Req = 1/R1 + 1/R2

1/4 = 1/20 + 1/R

1/4 = (R+20)/20R

20R = 4R + 80

16R = 80

=> R = 5Ω

•Hence , Value of R is 5 Ω

Discussion

23.	What work is performed in dragging a block 100m horizontally when a 60 n force is applied by a rope making an angel of 60 degree with the ground?
Answer» SEE the attachment hope it will be cleared to you please MARK as BRAINLIEST ANSWER

23.

What work is performed in dragging a block 100m horizontally when a 60 n force is applied by a rope making an angel of 60 degree with the ground?

Answer»

SEE the attachment

hope it will be cleared to you

please MARK as BRAINLIEST ANSWER

Discussion

24.	A car increases its speed from 20km/hr to 30km/hr in 10 seconds . What is its acceleration
Answer» EXPLANATION: a=v-u/t a=(30-20) /10 a=1

24.

A car increases its speed from 20km/hr to 30km/hr in 10 seconds . What is its acceleration

Answer»

EXPLANATION:

a=v-u/t

a=(30-20) /10

a=1

Discussion

25.	Please help me to find the answers ..........................An object is placed in front of a concave mirror of focal length 20 cm . The image formed is three times the size of the object . Calculate two possible distance of the object from the mirror.
Answer» ANSWER: EXPLANATION: Mirror: CONCAVE. Focal LENGTH = -20cm h'=3h According to magnification formula, -v/u=h'/h -v/u=3h/h -v/u=3 -v=3u v= -3u According to mirror formula, 1/f=1/v+1/u 1/-20= 1/-3u+1/u -1/20= -1/3u+(1/u)×3/3 -1/20= -1/3u+3/3u -1/20= (-1+3)/3u -1/20= 2/3u -1×3u=2×20 -3u=40 u=40/-3 u= -40/3 u= -13.33m

25.

Please help me to find the answers ..........................An object is placed in front of a concave mirror of focal length 20 cm . The image formed is three times the size of the object . Calculate two possible distance of the object from the mirror.

Answer»

ANSWER:

EXPLANATION:

Mirror: CONCAVE.

Focal LENGTH = -20cm

h'=3h

According to magnification formula,

-v/u=h'/h

-v/u=3h/h

-v/u=3

-v=3u

v= -3u

According to mirror formula,

1/f=1/v+1/u

1/-20= 1/-3u+1/u

-1/20= -1/3u+(1/u)×3/3

-1/20= -1/3u+3/3u

-1/20= (-1+3)/3u

-1/20= 2/3u

-1×3u=2×20

-3u=40

u=40/-3

u= -40/3

u= -13.33m

Discussion

26.	Refraction of light through a triangular glass prism or glass slab
Answer» ☆____hey *mate* *here* is UR *answer* *____☆ A glass prism is a transparent object having two triangularends and three RECTANGULAR sides. Therefraction of light in glass prism is different from a glass slab. This is because in glass prism, the incident RAY of light is not parallel to emergent ray of light. hope* it *helps* U ..✌ *mark* as *brainliest*..

26.

Refraction of light through a triangular glass prism or glass slab

Answer»

☆____hey mate here is UR answer ____☆

A glass prism is a transparent object having two triangularends and three RECTANGULAR sides. Therefraction of light in glass prism is different from a glass slab. This is because in glass prism, the incident RAY of light is not parallel to emergent ray of light.

hope it helps U ..✌

mark as brainliest..

Discussion

27.	An electric geyser consumes energy at a rate of 1000watt when heating is at the maximum rate. And 500 watt when the heating is at the minimum rate. The voltage is 220Volt what are the value of the current and resistance in each case
Answer» EXPLANATION: PLEASE SEE the ANSWER and FOLLOW me

27.

An electric geyser consumes energy at a rate of 1000watt when heating is at the maximum rate. And 500 watt when the heating is at the minimum rate. The voltage is 220Volt what are the value of the current and resistance in each case

Answer»

EXPLANATION:

PLEASE SEE the ANSWER and FOLLOW me

Discussion

28.	Three resistors 3ohm, 2ohm, 6ohm are connected in parallel in a circuit . Find the net resistance the circuit
Answer» " $\bf{ \pmb{ \underline{\gray{GIVEN}}}} \\ \sf \: \small{ Three \: resistors \: of \: 2 Ω, 3 Ω \: and \: 6 Ω \: are \: given \: respectively. }\\ \\ \\ \bf{ \pmb{ \underline{\gray{TO \: FIND }}}}\\ \rm \small{Least \: value \: of \: the \: three \: resistances. }\\ \\ \\ \bf { \pmb{ \underline{\gray{ SOLUTION}}}} \\ \tt \tiny{For \: the \: max \: value \: of \: the \: resistances, resistor \: are \: connected \: in \: \bf{\blue{Series \: Combination}} }\\ \tt \tiny{For \: the \: least \ value\ of \: the \: resistances, resistor \: are \: connected \: in\ \bf{\green{Parallel \: Combination}} } \\ \\ \cal \: \small{\red{Connect \: the \: resistor \: in \: parallel \: for \: getting \: least \: value :} }\\ \\ \begin{gathered}\small \rm{\dfrac{1}{R_{eq}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3}} \\ \\ \small \rm{\dfrac{1}{R_{eq}} = \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{6}} \\ \\ \\ \small \rm{\dfrac{1}{R_{eq}} = \dfrac{3 + 2 + 1}{6}} \\ \\ \small \rm{\dfrac{1}{R_{eq}} = \dfrac{6}{6}} \\ \\ \small \rm{\dfrac{1}{R_{eq}} = 1} \\\\ \large { \boxed{\bf \blue{R_{eq} = 1 Ω}}}\end{gathered}$

Discussion

29.	What will have more resistence 60 w bulb or 100
Answer» ANSWER: HEY... gm... 100 w is the CORRECT OPTION and answer

29.

What will have more resistence 60 w bulb or 100

Answer»

ANSWER:

HEY...

gm...

100 w is the CORRECT OPTION and answer

Discussion

30.	What do you understand by the term electric potential at a point and what is the unit of electric potential
Answer» ANSWER: ' sdfasdf Explanation: sdfsdfsfsdf

30.

What do you understand by the term electric potential at a point and what is the unit of electric potential

Answer»

ANSWER:

'

sdfasdf

Explanation:

sdfsdfsfsdf

Discussion

31.	Which is safest speed on banked road as we don't take the help of Friday
Answer» ANSWER: dh Explanation: rytgxgh THB tujvtuijctik XUK F

31.

Which is safest speed on banked road as we don't take the help of Friday

Answer»

ANSWER:

dh

Explanation:

rytgxgh THB tujvtuijctik XUK F

Discussion

32.	Guys plz plz and plz is question ko pen paper mei solve krke upload kr dena ...... har choti se choti steps likh k dena......agar ans accha laga pakka brainliest mark karungi.....agar kahi pe LCM use ho rahi ho toh use bhi solve krke dikhana.....plzzzzzzzzzz
Answer» Answer: HY DEAR it's your Answer! HOPE it's HELPFUL you☺️ MARK BRAINLIEST!

32.

Guys plz plz and plz is question ko pen paper mei solve krke upload kr dena ...... har choti se choti steps likh k dena......agar ans accha laga pakka brainliest mark karungi.....agar kahi pe LCM use ho rahi ho toh use bhi solve krke dikhana.....plzzzzzzzzzz

Answer»

Answer:

HY DEAR it's your Answer!

HOPE it's HELPFUL you☺️

MARK BRAINLIEST!

Discussion

33.	What is the correct order of energy conversions associated with a power plant that uses nuclear fission reactions?1 thermal to nuclear to mechanical to electrical2 thermal to mechanical to nuclear to electrical3 nuclear to mechanical to electrical to thermal 4 nuclear to thermal to mechanical to electrical
Answer» Answer: 4 Explanation: TRUST :)

33.

What is the correct order of energy conversions associated with a power plant that uses nuclear fission reactions?1 thermal to nuclear to mechanical to electrical2 thermal to mechanical to nuclear to electrical3 nuclear to mechanical to electrical to thermal 4 nuclear to thermal to mechanical to electrical

Answer»

Answer:

4

Explanation:

TRUST :)

Discussion

34.	How can a machine multiply the effect of human effort? Explain briefly
Answer» The machine can multiply the effect of the human effort by by the law of equality of the the clockwise and anticlockwise moment. Explanation: in case of a machine there are three important parts that is the effort the LOAD and the fulcrum. The fulcrum is ALWAYS at rest and hence the the moment is calculated based on the DISTANCE from the fulcrum. Since the clockwise and anticlockwise moment are always equal hence if the the effort arm is more than the load arm then the moment due to them must be equal hence for more amount of load the effort is comparatively reduced. To know more about FORCE multiplier, When does a machine act as (a) a force multiplier,(b) a speed .. .brainly.in/question/9081462

34.

How can a machine multiply the effect of human effort? Explain briefly

Answer»

The machine can multiply the effect of the human effort by by the law of equality of the the clockwise and anticlockwise moment.

Explanation:

in case of a machine there are three important parts that is the effort the LOAD and the fulcrum.

The fulcrum is ALWAYS at rest and hence the the moment is calculated based on the DISTANCE from the fulcrum.

Since the clockwise and anticlockwise moment are always equal hence if the the effort arm is more than the load arm then the moment due to them must be equal hence for more amount of load the effort is comparatively reduced.

To know more about FORCE multiplier,

When does a machine act as (a) a force multiplier,(b) a speed ..

.brainly.in/question/9081462

Discussion

35.	If the refractive index from air to glan is 1.52 then find the refractive index from glan to air
Answer» Answer: REFRACTIVE index = 0.657 Explanation: When light travels from AIR to glass Refractive index = Speed of light in air/ Speed of light in glass 1.52=Speed of light in air/Speed of light in glass. When light travels from glass to air, the refractive index will be the reciprocal of refractive index from air to glass. i.e. Refractive index =1/1.52 =0.657 Hope this BRING a smile in your face

35.

If the refractive index from air to glan is 1.52 then find the refractive index from glan to air

Answer»

Answer:

REFRACTIVE index = 0.657

Explanation:

When light travels from AIR to glass

Refractive index = Speed of light in air/ Speed of light in glass

1.52=Speed of light in air/Speed of light in glass.

When light travels from glass to air, the refractive index will be the reciprocal of refractive index from air to glass.

i.e. Refractive index =1/1.52

=0.657

Hope this BRING a smile in your face

Discussion

36.	The bus moves a total distance of 390 m during the journey .Calculate the average speed of the bus ?Plz Answer it =_=
Answer» Answer: 390/60=6.5m/s...............

36.

The bus moves a total distance of 390 m during the journey .Calculate the average speed of the bus ?Plz Answer it =_=

Answer»

Answer:

390/60=6.5m/s...............

Discussion

37.	If the rule is there are no rules, then wouldn't that make the rule that there are no rules a rule? but also the rule is there are no rules.
Answer» ANSWER: the rule is that there are no rules Explanation: The rule is there are no rules because you SAID in the QUESTION that the rule is there are no rules so that MEANS there are no rules at all!

37.

If the rule is there are no rules, then wouldn't that make the rule that there are no rules a rule? but also the rule is there are no rules.

Answer»

ANSWER:

the rule is that there are no rules

Explanation:

The rule is there are no rules because you SAID in the QUESTION that the rule is there are no rules so that MEANS there are no rules at all!

Discussion

38.	Nuclear energy is currently used in which vehicles?Check all that apply. 1 cars2 submarines3 spacecraft 4 airplanes 5 aircraft carriers
Answer» ANSWER: NUCLEAR ENERGY is USED in CARS .....

38.

Nuclear energy is currently used in which vehicles?Check all that apply. 1 cars2 submarines3 spacecraft 4 airplanes 5 aircraft carriers

Answer»

ANSWER:

NUCLEAR ENERGY is USED in CARS .....

Discussion

39.	Find the number of electrons transferred between two points kept at a potentialdifference of 30 V if 50 J of work is done.
Answer» EXPLANATION: *V=J/C* *V=J/C20=40/C* *V=J/C20=40/CC=2* **V=J/C20=40/CC=21C=6.2510^6* V=J/C20=40/CC=21C=6.2510^62C=(6.2510^6)2* V=J/C20=40/CC=21C=6.2510^62C=(6.2510^6)22C=12.510^6**

39.

Find the number of electrons transferred between two points kept at a potentialdifference of 30 V if 50 J of work is done.

Answer»

EXPLANATION:

V=J/C

V=J/C20=40/C

V=J/C20=40/CC=2

V=J/C20=40/CC=21C=6.25*10^6

V=J/C20=40/CC=21C=6.25*10^62C=(6.25*10^6)*2

V=J/C20=40/CC=21C=6.25*10^62C=(6.25*10^6)*22C=12.5*10^6

Discussion

40.	Which type of energy is in a unlit matchstick
Answer» MARVELLOUS GOOD MORNING dude potential energy

40.

Which type of energy is in a unlit matchstick

Answer»

MARVELLOUS GOOD MORNING dude

potential energy

Discussion

41.	1 rev per min is equal to how many radian per sec
Answer» 1 RPM = 1/60 Hz or approximately 0.0166666666666667 Hz. 1 Radian per Second: 1 Radian per second is comparative to 1/2π Hertz. Radians per second is a measure of ANGULAR FREQUENCY, it can be COMPARED to Hertz or other angular units. hope it helps you.. MARK as brainliest..✌

41.

1 rev per min is equal to how many radian per sec

Answer»

1 RPM = 1/60 Hz or approximately 0.0166666666666667 Hz. 1 Radian per Second: 1 Radian per second is comparative to 1/2π Hertz. Radians per second is a measure of ANGULAR FREQUENCY, it can be COMPARED to Hertz or other angular units.

hope it helps you..

MARK as brainliest..✌

Discussion

42.	What are the changes in the eyes the person can't see the near by object
Answer» *hey* *mate* *here* is ur *ANSWER... Myopia. ALSO called NEARSIGHTEDNESS or shortsightedness, myopia (my-OP-ee-uh) happens when the eye focuses the image of an object in front of the retina instead of directly on it. In most CASES, people can't see well far away, but can see objects clearly CLOSE up. hope* it *helps* *you*..

42.

What are the changes in the eyes the person can't see the near by object

Answer»

hey mate here is ur ANSWER...

Myopia. ALSO called NEARSIGHTEDNESS or shortsightedness, myopia (my-OP-ee-uh) happens when the eye focuses the image of an object in front of the retina instead of directly on it. In most CASES, people can't see well far away, but can see objects clearly CLOSE up.

hope it helps you..

Discussion

43.	Time is not absolute.. give an example stating the theory of simultaneity with respect to two different frame of reference
Answer» Answer: EVENTS that are simultaneous in ONE frame are not simultaneous in a frame moving with respect to that frame: This is expressed by the equation: t2' - t2 = [(t1' - t1) - v^2/c^2 (x1' - x1)] / (1 - v^2 / c^2)^1/2 where t2' - t2 is the time interval in frame 2 moving with respect to frame 1 and x1' - x1 is the spatial separation of the events in frame 1. note that if EITHER t2' - t2 or t1' - t1 is zero (simultaneous in that frame) the events are not simultaneous in the other frame. This can be confusing: suppose a clock is at rest in frame 1 then x1' - x1 = 0 and (1 - v^2/c^2)^1/2 = 1/2. It does not mean that 1 tick on a clock in frame 1 occurs while 2 ticks occur on a clock at rest in frame 2, but rather that the time between ticks in frame 2 is twice as LONG as ticks between the ticks on the clock in rest frame 1. This is called time DILATION.

43.

Time is not absolute.. give an example stating the theory of simultaneity with respect to two different frame of reference

Answer»

Answer:

EVENTS that are simultaneous in ONE frame are not simultaneous in a frame moving with respect to that frame:

This is expressed by the equation:

t2' - t2 = [(t1' - t1) - v^2/c^2 (x1' - x1)] / (1 - v^2 / c^2)^1/2

where t2' - t2 is the time interval in frame 2 moving with respect to frame 1 and x1' - x1 is the spatial separation of the events in frame 1.

note that if EITHER t2' - t2 or t1' - t1 is zero (simultaneous in that frame) the events are not simultaneous in the other frame.

This can be confusing: suppose a clock is at rest in frame 1 then x1' - x1 = 0 and (1 - v^2/c^2)^1/2 = 1/2. It does not mean that 1 tick on a clock in frame 1 occurs while 2 ticks occur on a clock at rest in frame 2, but rather that the time between ticks in frame 2 is twice as LONG as ticks between the ticks on the clock in rest frame 1. This is called time DILATION.

Discussion

44.	What are the changes in the eye the person can't see the object faraway
Answer» *hey* *mate* *here* is ur *answer... Myopia. Also called nearsightedness or SHORTSIGHTEDNESS, myopia (my-OP-ee-uh) happens when the eye focuses the image of an OBJECT in front of the retina instead of directly on it. In most cases, people can't see WELL far away, but can see OBJECTS clearly close up.. hope* it *helps* *you..✌✌ mark* as *brainliest*..

44.

What are the changes in the eye the person can't see the object faraway

Answer»

hey mate here is ur answer...

Myopia. Also called nearsightedness or SHORTSIGHTEDNESS, myopia (my-OP-ee-uh) happens when the eye focuses the image of an OBJECT in front of the retina instead of directly on it. In most cases, people can't see WELL far away, but can see OBJECTS clearly close up..

hope it helps you..✌✌

mark as brainliest..

Discussion

45.	Why is fusion nuclear energy currently not widely used as a source of electricity?1 Fusion reactions have not yet been achieved. 2 Fusion reactions cannot be controlled.3 Fusion reactions require very high temperatures and pressure.4 Fusion reaction energy cannot be converted into electricity.
Answer» Answer: Fusion reactions cannnot be CONTROLLED Explanation: hope this is your answer MARK me BRAINLIEST if you WISH! :)

45.

Why is fusion nuclear energy currently not widely used as a source of electricity?1 Fusion reactions have not yet been achieved. 2 Fusion reactions cannot be controlled.3 Fusion reactions require very high temperatures and pressure.4 Fusion reaction energy cannot be converted into electricity.

Answer»

Answer: Fusion reactions cannnot be CONTROLLED

Explanation:

hope this is your answer MARK me BRAINLIEST if you WISH! :)

Discussion

46.	How are electric power lines connected in series against in parallel?
Answer» As we know that in PARALLEL connection of resistance the RESULTANT resistance will be lower than the LEAST. That implies current to flow more through the least reistance path. As we know by CONNECTING LINES in series voltage drop takes place.

46.

How are electric power lines connected in series against in parallel?

Answer»

As we know that in PARALLEL connection of resistance the RESULTANT resistance will be lower than the LEAST. That implies current to flow more through the least reistance path. As we know by CONNECTING LINES in series voltage drop takes place.

Discussion

47.	●State the equation linking average speed ,distance moved ,and time taken .PLZ answer it guys :/
Answer» ANSWER: Equation will be => SPEED =distance ÷time TAKEN. HOPE IT'S HELP U

47.

●State the equation linking average speed ,distance moved ,and time taken .PLZ answer it guys :/

Answer»

ANSWER:

Equation will be => SPEED =distance ÷time TAKEN.

HOPE IT'S HELP U

Discussion

48.	Explain division germer,s experiment with neat and clean diagram.
Answer» ANSWER: The Davisson–Germer experiment was a 1923-27 experiment by CLINTON Davisson and Lester Germer at Western Electric (later BELL LABS),[1] in which electrons, scattered by the surface of a crystal of nickel metal, displayed a diffraction pattern. This confirmed the hypothesis, advanced by Louis de Broglie in 1924, of wave-particle DUALITY, and was an experimental milestone in the creation of quantum mechanics.

48.

Explain division germer,s experiment with neat and clean diagram.

Answer»

ANSWER:

The Davisson–Germer experiment was a 1923-27 experiment by CLINTON Davisson and Lester Germer at Western Electric (later BELL LABS),[1] in which electrons, scattered by the surface of a crystal of nickel metal, displayed a diffraction pattern. This confirmed the hypothesis, advanced by Louis de Broglie in 1924, of wave-particle DUALITY, and was an experimental milestone in the creation of quantum mechanics.

Discussion

49.	Calculate the potential difference between the two terminals of a battery, if 150 joulesof work is required to transfer 20 coulombs of charge from one terminal of the battery to the other.
Answer» EXPLANATION: V=W/Q or VOLT=Joule/Coulomb v=150Joule/20coulomb VOLTAGE=15/2 =7.5Volt P.d. or Voltage of BATTERY is 7.5 Volt THANKS

49.

Calculate the potential difference between the two terminals of a battery, if 150 joulesof work is required to transfer 20 coulombs of charge from one terminal of the battery to the other.

Answer»

EXPLANATION:

V=W/Q or VOLT=Joule/Coulomb

v=150Joule/20coulomb

VOLTAGE=15/2

=7.5Volt

P.d. or Voltage of BATTERY is 7.5 Volt

THANKS

Discussion

50.	(1+2x)^6 expand using binomial theorem
Answer» EXPLANATION: here is the ANSWER of the QUESTION

50.

(1+2x)^6 expand using binomial theorem

Answer»

EXPLANATION:

here is the ANSWER of the QUESTION

Discussion

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If you satisfy on my answer PLEASE mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️

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SEE the attachment

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MARVELLOUS GOOD MORNING dude

potential energy

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What are the changes in the eye the person can't see the object faraway

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