An artificial satellite is moving in a circular orbit of radius 42.250

1.	An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.?
Answer» ANSWER :- $\implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }} \:$ Explanation :- ACCORDING to the QUESTION , $\implies \sf{radius \: (r) = 42.250 \: km \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{r= \: \: \: 42.250 \times 1000 \: metre \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ r = 42250 \: m \: } \\ \\ \to \sf{time \: (t) = 24 \: hours = 86400 \: seconds \: }$ LET distance covered by satellite is D . Distance covered by satellite in 24 hours is - $\to \sf{ D \: = 2 \pi \: r} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 42250 \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 265330 \: m \:$ Hence ,linear velocity(v) is - $\implies \sf{ v \: = \frac{D}{t}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{265330}{86400} = 3.07 \: \frac{m}{s} \\ \\ \implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }}$

An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.?

Answer»

ANSWER :-

$\implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }} \:$

Explanation :-

$\implies \sf{radius \: (r) = 42.250 \: km \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{r= \: \: \: 42.250 \times 1000 \: metre \: } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ r = 42250 \: m \: } \\ \\ \to \sf{time \: (t) = 24 \: hours = 86400 \: seconds \: }$

LET distance covered by satellite is D .

Distance covered by satellite in 24 hours is -

$\to \sf{ D \: = 2 \pi \: r} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 42250 \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 265330 \: m \:$

Hence ,linear velocity(v) is -

$\implies \sf{ v \: = \frac{D}{t}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{265330}{86400} = 3.07 \: \frac{m}{s} \\ \\ \implies \boxed{\sf{ velocity \: = 3.07 \: \: \frac{m}{s} }}$