67486 + Interview Questions in Secondary School in Physics

1.	Two necessary conditions for a satellite to be geostationary
Answer» Answer: Explanation: following are ESSENTIAL conditions? A . it MUST always be STATIONED above the equator. B . it must be rotate from west to east. C . it must be about 36,000km above the earth surface. D . it's orbit must be circular, and not ELLIPTICAL.

1.

Two necessary conditions for a satellite to be geostationary

Answer»

Answer:

Explanation:

following are ESSENTIAL conditions?

A . it MUST always be STATIONED above the equator.

B . it must be rotate from west to east.

C . it must be about 36,000km above the earth surface.

D . it's orbit must be circular, and not ELLIPTICAL.

Discussion

2.	Now last question a body moving with velocity 10 m/s, experience a retardation of 4 m/s². Find the distance travelled in 3 seconds.
Answer» ANSWER: Explanation: Where v is 10 m/s, Retardation is 4 m/s^2, TIME is 3 seconds. v-u/t=retardation, 10-u/3=4, 10-u=4*3, 10-u=12, -u=12-10, -u=2, So 10-2, 8 m is the distance travelled. I think it is correct. Hope it helps you.

2.

Now last question a body moving with velocity 10 m/s, experience a retardation of 4 m/s². Find the distance travelled in 3 seconds.

Answer»

ANSWER:

Explanation:

Where v is 10 m/s,

Retardation is 4 m/s^2,

TIME is 3 seconds.

v-u/t=retardation,

10-u/3=4,

10-u=4*3,

10-u=12,

-u=12-10,

-u=2,

So 10-2,

8 m is the distance travelled.

I think it is correct.

Hope it helps you.

Discussion

3.	A shunt generator delivers 50 kW at 250 V when running at 400 rpm. The armature and field resistance are 0.02 Ω and 50 Ω respectively. Calculate the speed of the machine when running as a shunt motor and taking 50 kW input at 250V. Allow 1 V per brush for contact drop.
Answer» ANSWER: the GOVERNMENT is not a problemwithandofandandandandand yet5778878

3.

A shunt generator delivers 50 kW at 250 V when running at 400 rpm. The armature and field resistance are 0.02 Ω and 50 Ω respectively. Calculate the speed of the machine when running as a shunt motor and taking 50 kW input at 250V. Allow 1 V per brush for contact drop.

Answer»

ANSWER:

the GOVERNMENT is not a problemwithandofandandandandand yet5778878

Discussion

4.	What angle made by the hands of clock if the time is 3:20AM
Answer» Answer: The HANDS of the CLOCK MAKE an angle of 30° when the time is 3:20 AM.

4.

What angle made by the hands of clock if the time is 3:20AM

Answer»

Answer:

The HANDS of the CLOCK MAKE an angle of 30° when the time is 3:20 AM.

Discussion

5.	Represent graphically a force of 20N due South,it's very important please answer fast.
Answer» the ANSWER download hsed RFH yhhh hvyyh H U u hhh j j h h HU

Discussion

6.	Write the formula for the amount for heat observed(raised) by a substance andexplain the terms in it?
Answer» ANSWER: abcdefghijklmnopqrs

6.

Write the formula for the amount for heat observed(raised) by a substance andexplain the terms in it?

Answer»

ANSWER:

abcdefghijklmnopqrs

Discussion

7.	Defineresolving powerof a Telescope?
Answer» Answer: Resolving power is defined as the ABILITY of a MICROSCOPE or TELESCOPE to distinguish two close together images as being separate. An example of resolving power is how well a telescope can show two STARS as being separate stars.

7.

Defineresolving powerof a Telescope?

Answer»

Answer:

Resolving power is defined as the ABILITY of a MICROSCOPE or TELESCOPE to distinguish two close together images as being separate. An example of resolving power is how well a telescope can show two STARS as being separate stars.

Discussion

8.	An ammeter has 10 divisions graduated between 0 and 0.5 ampere.What is the least count of ammeter
Answer» Answer: 0 is the LEAST COUNT of AMMETER

8.

An ammeter has 10 divisions graduated between 0 and 0.5 ampere.What is the least count of ammeter

Answer»

Answer:

0 is the LEAST COUNT of AMMETER

Discussion

9.	resistance of a metal wire of length 1m is 26ohm at 20degree C. if the diameter pf the wire is 4m. what will be the resistivity of the metal at that temperature
Answer» Answer: Resistivity = 3110^-5 OHM meter EXPLANATION:* Resistance = 26 ohm length = 1m Diameter = 4m Radius = 2 m Ar. of cross section = πr^2 = 3.1422 = (314/25) we know that , R = eL/A = eL/A e = L/AR = eL/A e = L/AR e = 1/ (314/25)26* = eL/A e = L/AR e = 1/ (314/25)26 e =* 25/ 31426 e = 25/ 8164 e = 0.00306 e = 306 10^ -5 ohm meter e = 3110^-5 ohm* meter

9.

resistance of a metal wire of length 1m is 26ohm at 20degree C. if the diameter pf the wire is 4m. what will be the resistivity of the metal at that temperature

Answer»

Answer:

Resistivity = 31*10^-5 OHM meter

EXPLANATION:

Resistance = 26 ohm

length = 1m

Diameter = 4m

Radius = 2 m

Ar. of cross section = π*r^2 = 3.14*2*2 = (314/25)

we know that ,

R = e*L/A

= e*L/A e = L/A*R

= e*L/A e = L/A*R e = 1/ (314/25)*26

= e*L/A e = L/A*R e = 1/ (314/25)*26 e = 25/ 314*26

e = 25/ 8164

e = 0.00306

e = 306* 10^ -5 ohm meter

e = 31*10^-5 ohm meter

Discussion

10.	Source of magnetism in matter is
Answer» Answer: Magnetism is CAUSED by the motion of electric charges. Every substance is made up of tiny UNITS called atoms. Each ATOM has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the NUCLEUS, or core, of an atom. *PLEASE* *MARK* AS *BRAINLLIST* *ANSWER* *AND* *FOLLOW* ME

10.

Source of magnetism in matter is

Answer»

Answer:

Magnetism is CAUSED by the motion of electric charges. Every substance is made up of tiny UNITS called atoms. Each ATOM has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the NUCLEUS, or core, of an atom.

PLEASE MARK AS BRAINLLIST ANSWER AND FOLLOW ME

Discussion

11.	What is electronic configuration? ???with examples.
Answer» Answer: In atomic physics and QUANTUM CHEMISTRY, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the NEON atom is 1S2 2s2 2p6, using the notation explained below. follow me please guys love you BYE bye

11.

What is electronic configuration? ???with examples.

Answer»

Answer:

In atomic physics and QUANTUM CHEMISTRY, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the NEON atom is 1S2 2s2 2p6, using the notation explained below.

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love you

BYE bye

Discussion

12.	It takes 8 minutes for light from sun to reach the earth surface.If the speed of light is 3×10⁸ m/s,find the distance of the sun from earth in S I unit
Answer» Answer: 150 MILLION KILOMETERS = 1AU Explanation: HOPE it is helpful Mark as BRAINLIEST!!!!!!

12.

It takes 8 minutes for light from sun to reach the earth surface.If the speed of light is 3×10⁸ m/s,find the distance of the sun from earth in S I unit

Answer»

Answer:

150 MILLION KILOMETERS = 1AU

Explanation:

HOPE it is helpful

Mark as BRAINLIEST!!!!!!

Discussion

13.	Disscus the factor on which vertical shift due to glass slab depends
Answer» Explanation: The PATH followed by a reflected light which is ALONG the path of the light FACES is called lateral shift It is calculated by the perpendicular distance between incident ray and reflected rays This depends UPON the following factors; Thickness of the glass SLAB Angle of incidence and angle of refraction, or in order words this depends on refractive index of glass slab

13.

Disscus the factor on which vertical shift due to glass slab depends

Answer»

Explanation:

The PATH followed by a reflected light which is ALONG the path of the light FACES is called lateral shift

It is calculated by the perpendicular distance between incident ray and reflected rays

This depends UPON the following factors;

Thickness of the glass SLAB

Angle of incidence and angle of refraction, or in order words this depends on refractive index of glass slab

Discussion

14.	The third equation of motion using graphically
Answer» Here's your answer! • Consider an object starts moving with a velocity u at t = 0 second. • Consider the object stopping motion with velocity v at t = t SECONDS. • Take trapezium WXZTS, • The AREA of trapezium = ½ ( sum of parallel sides ) × height ( distance between the parallel sides ) • Area = ½ ( ZT + XS ) × TS • s = ½ ( u + v ) × time - equation "a" From equation = t = v - u / a - equation "b" • Let the eq. "b" be SUBSTITUTED in eq. "a" • s = ½ ( u + v ) ( v - u / a ) • s = ½×a ( v - u ) ( v + u ) • s = ½.a ( v² - u² ) • 2as = v² - u² • Hence shown! Hope it helps!

14.

The third equation of motion using graphically

Answer»

Here's your answer!

• Consider an object starts moving with a velocity u at t = 0 second.

• Consider the object stopping motion with velocity v at t = t SECONDS.

• Take trapezium WXZTS,

• The AREA of trapezium = ½ ( sum of parallel sides ) × height ( distance between the parallel sides )

• Area = ½ ( ZT + XS ) × TS

• s = ½ ( u + v ) × time - equation "a"

From equation = t = v - u / a - equation "b"

• Let the eq. "b" be SUBSTITUTED in eq. "a"

• s = ½ ( u + v ) ( v - u / a )

• s = ½×a ( v - u ) ( v + u )

• s = ½.a ( v² - u² )

• 2as = v² - u² •

Hence shown!

Hope it helps!

Discussion

15.	প্রমাণ বায়ুমণ্ডলের চাপের মান নির্ণয় করো।
Answer» ANSWER: what LANGUAGE is this I didn't UNDERSTAND

15.

প্রমাণ বায়ুমণ্ডলের চাপের মান নির্ণয় করো।

Answer»

ANSWER:

what LANGUAGE is this

I didn't UNDERSTAND

Discussion

16.	What do you understand by interface in light chapter ?
Answer» Answer: hi here is ur answer Explanation: An interface is a boundary shared by two MEDIA. To a wave entering a medium with a SLOWER wave SPEED,the interface is more like a fixed end than a free end. hope it HELP u

16.

What do you understand by interface in light chapter ?

Answer»

Answer:

hi here is ur answer

Explanation:

An interface is a boundary shared by two MEDIA. To a wave entering a medium with a SLOWER wave SPEED,the interface is more like a fixed end than a free end.

hope it HELP u

Discussion

17.	What is the difference between the mass of an object and its weight...?
Answer» Answer: Difference between mass and weight are- Mass is the amount of matter contain in the body.Weight is the force equal to the gravitational pull exerted by the planet. Mass is a constant quantity and does not change with respect to position or place. Weight is variable quantity and changes with the change ine acceleration due to gravity of a place. Mass of a body can never be zero. Weight of the body can be zero during free fall. Mass is measured by USING a PHYSICAL BALANCE. Weight is measured by using a SPRING balance.

17.

What is the difference between the mass of an object and its weight...?

Answer»

Answer:

Difference between mass and weight are-

Mass is the amount of matter contain in the body.Weight is the force equal to the gravitational pull exerted by the planet.
Mass is a constant quantity and does not change with respect to position or place. Weight is variable quantity and changes with the change ine acceleration due to gravity of a place.
Mass of a body can never be zero. Weight of the body can be zero during free fall.
Mass is measured by USING a PHYSICAL BALANCE. Weight is measured by using a SPRING balance.

Discussion

18.	Does the number of significant figures depend on the choice of unit?
Answer» You can count the number of Significant figures from these rules: All the reported non-zero NUMBERS in a measurement are significant. For example, 22.13 has 4 and 299792458 has 9 significant DIGITS. Zeroes sandwiched anywhere between the non-zero digits are significant. For example, 299007900002400000058 has 21 significant digits, 102.4 has 4 and 1.024 ALSO has 4. Zeroes to the left of a first non-zero digit are not significant. For example, 007 has 1 significant figure and 0.0000102 has 3. The trailing zeroes or the zeroes to the right of the last non-zero digit are significant if the number has a decimal point otherwise they are insignificant. For example, 0.00001020 has 4 and 70000000000000 has 1 significant figure only

18.

Does the number of significant figures depend on the choice of unit?

Answer»

You can count the number of Significant figures from these rules:

All the reported non-zero NUMBERS in a measurement are significant. For example, 22.13 has 4 and 299792458 has 9 significant DIGITS.

Zeroes sandwiched anywhere between the non-zero digits are significant. For example, 299007900002400000058 has 21 significant digits, 102.4 has 4 and 1.024 ALSO has 4.

Zeroes to the left of a first non-zero digit are not significant. For example, 007 has 1 significant figure and 0.0000102 has 3.

The trailing zeroes or the zeroes to the right of the last non-zero digit are significant if the number has a decimal point otherwise they are insignificant. For example, 0.00001020 has 4 and 70000000000000 has 1 significant figure only

Discussion

19.	Given r = 4j and p = 2i+3j+k. The angular momentum isa)4i-8kb)8i-4kc)8jd)9k
Answer» Here's your answer! • Angular Momentum, L = p × r • l = ( 2I + 3J + K ) × ( 4j ) • l = 4i + 8k Hope it helps!

19.

Given r = 4j and p = 2i+3j+k. The angular momentum isa)4i-8kb)8i-4kc)8jd)9k

Answer»

Here's your answer!

• Angular Momentum, L = p × r

• l = ( 2I + 3J + K ) × ( 4j )

• l = 4i + 8k

Hope it helps!

Discussion

20.	35. A projectile shot at an angle of 45° above thehorizontal strikes the wall of a building 30m awayat a point 15m above the point of projection. Initialvelocity of the projectile is1)14 m/s 2) 1472 m/s3) 1413 m/s4) 1415 m/sERILAISELLASERSACLIO
Answer» ANSWER: here COMES your SOLUTION

20.

35. A projectile shot at an angle of 45° above thehorizontal strikes the wall of a building 30m awayat a point 15m above the point of projection. Initialvelocity of the projectile is1)14 m/s 2) 1472 m/s3) 1413 m/s4) 1415 m/sERILAISELLASERSACLIO

Answer»

ANSWER:

here COMES your SOLUTION

Discussion

21.	State and explain gauss law in Electrostatics
Answer» ANSWER: gauss law states total FLUX enclosing to the surface is 1 /EO TIME of total charge Q enclosed in it. electric flux = q/Eo

21.

State and explain gauss law in Electrostatics

Answer»

ANSWER:

gauss law states total FLUX enclosing to the surface is 1 /EO TIME of total charge Q enclosed in it.

electric flux = q/Eo

Discussion

22.	Answer my all questions
Answer» Answer: 1. c 2. a 3. d 4. B 5. a 6. a 7. a 8. b 9. c 10. b

22.

Answer my all questions

Answer»

Answer:

1. c

2. a

3. d

4. B

5. a

6. a

7. a

8. b

9. c

10. b

Discussion

23.	Half of the rectangular plates of length l as shown in the figure is made up of a material of density p and other half of density 3p distance of centre of mass from O is
Answer» GIVEN that, Length of half of the PLATES = l Density = ρ Density of half other = 3ρ We need to calculate the MASS of half of rectangular plate Using FORMULA of mass $m_{1}=\rho_{1}\times V_{1}$ Put the value into the formula $m_{1}=\rho\times\dfrac{V}{2}$ We need to calculate the mass of other half of rectangular plate Using formula of mass $m_{2}=\rho_{2}\times V_{2}$ Put the value into the formula $m_{2}=3\rho\times\dfrac{V}{2}$ We need to calculate the CENTER of mass from O Using formula of center of mass $C.M=\dfrac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$ Put the value into the formula $C.M=\dfrac{\rho\times\dfrac{V}{2}\times\dfrac{l}{2}+{3\rho\times\dfrac{V}{2}\times\dfrac{l}{2}}}{\rho\times\dfrac{V}{2}+3\rho\times\dfrac{V}{2}}$ $C.M=\dfrac{\rho Vl}{2\rho V}$ $C.M=\dfrac{l}{2}$ Hence, The center of mass from O is $\dfrac{l}{2}$

23.

Half of the rectangular plates of length l as shown in the figure is made up of a material of density p and other half of density 3p distance of centre of mass from O is

Answer»

GIVEN that,

Length of half of the PLATES = l

Density = ρ

Density of half other = 3ρ

We need to calculate the MASS of half of rectangular plate

Using FORMULA of mass

$m_{1}=\rho_{1}\times V_{1}$

Put the value into the formula

$m_{1}=\rho\times\dfrac{V}{2}$

We need to calculate the mass of other half of rectangular plate

Using formula of mass

$m_{2}=\rho_{2}\times V_{2}$

Put the value into the formula

$m_{2}=3\rho\times\dfrac{V}{2}$

We need to calculate the CENTER of mass from O

Using formula of center of mass

$C.M=\dfrac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$

Put the value into the formula

$C.M=\dfrac{\rho\times\dfrac{V}{2}\times\dfrac{l}{2}+{3\rho\times\dfrac{V}{2}\times\dfrac{l}{2}}}{\rho\times\dfrac{V}{2}+3\rho\times\dfrac{V}{2}}$

$C.M=\dfrac{\rho Vl}{2\rho V}$

$C.M=\dfrac{l}{2}$

Hence, The center of mass from O is $\dfrac{l}{2}$

Discussion

24.	Equation for effective resistance when three resistance in series and parallel.
Answer» The current is the same through each resistor. The TOTAL resistance of the circuit is found by simply adding up the resistance values of the INDIVIDUAL resistors: EQUIVALENT resistance of resistors in series : R = R1 + R2 + R3 + ... A series circuit is SHOWN in the DIAGRAM above Mark me as brain list.... thanks

24.

Equation for effective resistance when three resistance in series and parallel.

Answer»

The current is the same through each resistor. The TOTAL resistance of the circuit is found by simply adding up the resistance values of the INDIVIDUAL resistors: EQUIVALENT resistance of resistors in series : R = R1 + R2 + R3 + ... A series circuit is SHOWN in the DIAGRAM above

Mark me as brain list.... thanks

Discussion

25.	Sir plz solve the 36th question as fast as you can please
Answer» ANSWER: PLEASE TEACH me PHYSICS

25.

Sir plz solve the 36th question as fast as you can please

Answer»

ANSWER:

PLEASE TEACH me PHYSICS

Discussion

26.	A train travelling at 20 ms-1 accelerates at 0.5 ms-2, calculate the time interval in which it covers a distance of 825m
Answer» ANSWER: answer is 30SEC PLEASE FOLLOW me I follow you

26.

A train travelling at 20 ms-1 accelerates at 0.5 ms-2, calculate the time interval in which it covers a distance of 825m

Answer»

ANSWER:

answer is 30SEC

PLEASE FOLLOW me I follow you

Discussion

27.	you are given three resistors each of 6 ohm .How will You connect them to obtain the resistance of 9 ohm?
Answer» Answer: Explanation: To OBTAIN a COMBINED resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a PARALLEL circuit and one in series. In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances. Hope this will be helpful to you and PLEASE mark my answer as the BRAINLEAST answer.plz plz plZ....,......

27.

you are given three resistors each of 6 ohm .How will You connect them to obtain the resistance of 9 ohm?

Answer»

Answer:

Explanation:

To OBTAIN a COMBINED resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a PARALLEL circuit and one in series. In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances.

Hope this will be helpful to you and PLEASE mark my answer as the BRAINLEAST answer.plz plz plZ....,......

Discussion

28.	Given r = 4j and p = 2i+3j+k. The angular momentum is
Answer» ANSWER: l=p×r (2i+3j+k)×4j =2i+k since CROSS PRODUCT of J × j is ZERO

28.

Given r = 4j and p = 2i+3j+k. The angular momentum is

Answer»

ANSWER:

l=p×r

(2i+3j+k)×4j

=2i+k

since CROSS PRODUCT of J × j is ZERO

Discussion

29.	Draw a circuit diagram to showtwo 4 volts lamp can be lot brightly from two volts cell.
Answer» HOPE it HELPS you mark as BRILLIANT

29.

Draw a circuit diagram to showtwo 4 volts lamp can be lot brightly from two volts cell.

Answer»

HOPE it HELPS you

mark as BRILLIANT

Discussion

30.	Two similar circular loops of radius R, are lying concentrically with their planes at right angles to each otherespectively.The currents flowing in them are I andRoot 3I respectively. The magnetic field at the centre of the coil is
Answer» Explanation: The magnetic field at the center of the CIRCULAR coil of RADIUS R carrying current I is GIVEN by B= 2R μ 0 I . . . . . . .(1) The magnetic field at the center of the circular coil of radius R carrying current 3 I is given by B ′ = 2R 3 μ 0 I =B 3 (from EQUATION 1) The net magnetic field, B n = B 2 +3B 2 =2B B n =2. 2R μ 0 I = R μ 0 I

30.

Two similar circular loops of radius R, are lying concentrically with their planes at right angles to each otherespectively.The currents flowing in them are I andRoot 3I respectively. The magnetic field at the centre of the coil is

Answer»

Explanation:

The magnetic field at the center of the CIRCULAR coil of RADIUS R carrying current I is GIVEN by

B=

2R

μ

0

I

. . . . . . .(1)

The magnetic field at the center of the circular coil of radius R carrying current

3

I is given by

B

′

=

2R

3

μ

0

I

=B

3

(from EQUATION 1)

The net magnetic field,

B

n

=

B

2

+3B

2

=2B

B

n

=2.

2R

μ

0

I

=

R

μ

0

I

Discussion

31.	A 1cm high object is placed 10cm away from cancave mirror with the focal length f=15 cm determine image height
Answer» Answer: virtual in nature having MAGNIFICATION 3. Explanation: Given U = -10cm , v= ? , f = -15cm Applying mirror's formula,1/v +1/u = 1/f 1/v + 1/-10 = 1/-15 1/v = -1/15 + 1/10 =(-2+3)/30 = 1/30 V = 30 cm. Hence, we get ENLARGED image, virtual in nature having magnification 3.

31.

A 1cm high object is placed 10cm away from cancave mirror with the focal length f=15 cm determine image height

Answer»

Answer:

virtual in nature having MAGNIFICATION 3.

Explanation:

Given U = -10cm , v= ? , f = -15cm

Applying mirror's formula,1/v +1/u = 1/f

1/v + 1/-10 = 1/-15

1/v = -1/15 + 1/10

=(-2+3)/30

= 1/30

V = 30 cm.

Hence, we get ENLARGED image, virtual in nature having magnification 3.

Discussion

32.	Example 83 A particle is moving in a straight line underacceleration a = kt, where k is a constant. Find the velocityin terms of t. The motion starts from rest.
Answer» GIVEN, the acceleration, $\longrightarrow\sf{a(t)=kt}$ But we know that acceleration is the FIRST DERIVATIVE of VELOCITY with respect to time. $\longrightarrow\sf{a(t)=\dfrac {d}{dt}[v(t)]}$ Then, $\longrightarrow\sf{\dfrac {d}{dt}[v(t)]=kt}$ $\longrightarrow\sf{d[v(t)]=kt\ dt}$ $\displaystyle\longrightarrow\sf{v(t)=\int kt\ dt}$ $\displaystyle\longrightarrow\sf{v(t)=k\int t\ dt}$ $\displaystyle\longrightarrow\sf{v(t)=k\cdot\dfrac {t^2}{2}+c}$ $\displaystyle\longrightarrow\sf{v(t)=\dfrac {1}{2}kt^2+c}$ Since the MOTION starts from rest, $\displaystyle\sf{v=0}$ at $\displaystyle\sf{t=0.}$ Thus, $\displaystyle\longrightarrow\sf{v(0)=0}$ $\displaystyle\longrightarrow\sf{\dfrac {1}{2}k(0)^2+c=0}$ $\displaystyle\longrightarrow\sf{c=0}$ Therefore, $\displaystyle\longrightarrow\sf{\underline {\underline {v(t)=\dfrac {1}{2}kt^2}}}$

32.

Example 83 A particle is moving in a straight line underacceleration a = kt, where k is a constant. Find the velocityin terms of t. The motion starts from rest.

Answer»

GIVEN, the acceleration,

$\longrightarrow\sf{a(t)=kt}$

But we know that acceleration is the FIRST DERIVATIVE of VELOCITY with respect to time.

$\longrightarrow\sf{a(t)=\dfrac {d}{dt}[v(t)]}$

Then,

$\longrightarrow\sf{\dfrac {d}{dt}[v(t)]=kt}$

$\longrightarrow\sf{d[v(t)]=kt\ dt}$

$\displaystyle\longrightarrow\sf{v(t)=\int kt\ dt}$

$\displaystyle\longrightarrow\sf{v(t)=k\int t\ dt}$

$\displaystyle\longrightarrow\sf{v(t)=k\cdot\dfrac {t^2}{2}+c}$

$\displaystyle\longrightarrow\sf{v(t)=\dfrac {1}{2}kt^2+c}$

Since the MOTION starts from rest, $\displaystyle\sf{v=0}$ at $\displaystyle\sf{t=0.}$ Thus,

$\displaystyle\longrightarrow\sf{v(0)=0}$

$\displaystyle\longrightarrow\sf{\dfrac {1}{2}k(0)^2+c=0}$

$\displaystyle\longrightarrow\sf{c=0}$

Therefore,

$\displaystyle\longrightarrow\sf{\underline {\underline {v(t)=\dfrac {1}{2}kt^2}}}$

Discussion

33.	The equivalent potential betteryA and B is(A)28/9MF(B) 4MF(C) 5MF(D) 18 MF
Answer» ANSWER: 18MF is your CORRECT answer

33.

The equivalent potential betteryA and B is(A)28/9MF(B) 4MF(C) 5MF(D) 18 MF

Answer»

ANSWER:

18MF is your CORRECT answer

Discussion

34.	If a substance has 58 electrons and 53 protons then find the net charge on the substance?
Answer» hey mate here is ur ANSWER CHARGE due to 58 ELECTRON =-58 charge due to 54 proton=+53 Net=-58+53=-5. net charge= -5. hope it helps. ☆☆☆

34.

If a substance has 58 electrons and 53 protons then find the net charge on the substance?

Answer»

hey mate here is ur ANSWER

CHARGE due to 58 ELECTRON =-58

charge due to 54 proton=+53

Net=-58+53=-5.

net charge= -5.

hope it helps.

☆☆☆

Discussion

35.	Answer plzz give me and explain it
Answer» Answer: 1. Q=N×E here Q is charge and n is no. of ELECTRON and e is electronic charge (1.6×10-19c) then 1×10-6=n×1.6×10-19 then e is 6.25×10-12 electron deficit and 2. c

35.

Answer plzz give me and explain it

Answer»

Answer:

1. Q=N×E here Q is charge and n is no. of ELECTRON and e is electronic charge (1.6×10-19c) then 1×10-6=n×1.6×10-19 then e is 6.25×10-12 electron deficit and 2. c

Discussion

36.	write the two intersecting situations around us which involve the phonomenon of total internal refection
Answer» Answer: diamond where TOTAL internal reflections is there i GREATER than ic prism ALSO it also included REFRACTION

36.

write the two intersecting situations around us which involve the phonomenon of total internal refection

Answer»

Answer:

diamond where TOTAL internal reflections

is there i GREATER than ic

prism ALSO it also included REFRACTION

Discussion

37.	Pls explain what happens here. and no spam plss
Answer» Answer: hii freind though i have recently GIVEN my 12 boards so i can understand it here the distance between twoo charges is r which is more greater than the distance between another charge whichs distance is a.. if u subtract a square of r with square of a it will not readily effect the value of r. just like if u subtract 5 with 0.001 u GOT the ans 4.999 which is readily aceeptable as 5. so in that way here suppose 5 is r and a is 0.001 it will readily effect because it is of square of it.. so we neglect it it doesn't effect the ans.. HOPE u can understand it... thnks for any other info. comment it i will REPLY ..if u like the ans mark it brainellist.. thnks

37.

Pls explain what happens here. and no spam plss

Answer»

Answer:

hii freind

though i have recently GIVEN my 12 boards so i can understand it

here the distance between twoo charges is r which is more greater than the distance between another charge whichs distance is a.. if u subtract a square of r with square of a it will not readily effect the value of r. just like if u subtract 5 with 0.001 u GOT the ans 4.999 which is readily aceeptable as 5. so in that way here suppose 5 is r and a is 0.001 it will readily effect because it is of square of it.. so we neglect it it doesn't effect the ans..

HOPE u can understand it... thnks for any other info. comment it i will REPLY ..if u like the ans mark it brainellist.. thnks

Discussion

38.	A bullet is fired in east direction with a muzzle velocity of 400metre per second. wind is flowing in east direction with the velocity of 90km/h in west direction. Then find the maximum distance covered by the sound which is produced by gun in west direction. And also find the time taken by the gun sound to reach its maximum distance in West.(speed of sound 330m/s).
Answer» ANSWER: y8vy8vy8vyiviyvuvy8vy8vy8vuvu8vy8viyvuvy8vyivyviyvivi y is ivy8v8yv8yvuvjj

38.

A bullet is fired in east direction with a muzzle velocity of 400metre per second. wind is flowing in east direction with the velocity of 90km/h in west direction. Then find the maximum distance covered by the sound which is produced by gun in west direction. And also find the time taken by the gun sound to reach its maximum distance in West.(speed of sound 330m/s).

Answer»

ANSWER:

y8vy8vy8vyiviyvuvy8vy8vy8vuvu8vy8viyvuvy8vyivyviyvivi y is ivy8v8yv8yvuvjj

Discussion

39.	A body completes one round of a circle of radius R in 20 seconds. What is the ratio of distance to displacement of the body after 10 seconds
Answer» ANSWER: Explanation: given the body completes a full revolution in 20 seconds 2pi r =20 seconds [CIRCUMFRENCE of circle] therefore distance TRAVELLED in 10 seconds=2pir10/20=pir=half of the circle therefore distance travelled in 10 sec=pir displacement in 10 sec=2r [DIAMETRICALLY opposite points] therefore ratio=pir/2r=pi/2 =3.14/2=1.57

39.

A body completes one round of a circle of radius R in 20 seconds. What is the ratio of distance to displacement of the body after 10 seconds

Answer»

ANSWER:

Explanation:

given the body completes a full revolution in 20 seconds

2*pi *r =20 seconds [CIRCUMFRENCE of circle]

therefore distance TRAVELLED in 10 seconds=2*pi*r*10/20=pi*r=half of the circle

therefore distance travelled in 10 sec=pi*r

displacement in 10 sec=2r [DIAMETRICALLY opposite points]

therefore ratio=pi*r/2r=pi/2

=3.14/2=1.57

Discussion

40.	An acid with a base to form a salt and water this type of reaction is called
Answer» ANSWER: These TYPE of reactions are CALLED neutralisation reaction. Hope it HELPS

40.

An acid with a base to form a salt and water this type of reaction is called

Answer»

ANSWER:

These TYPE of reactions are CALLED neutralisation reaction.

Hope it HELPS

Discussion

41.	How is liquefaction different from condensation
Answer» Answer: $\huge\underline{ \underline{ \red{your \: \:answer}}}$ Explanation: LIQUEFACTION refers to the change of phase from a gas to a LIQUID. Condensation refers to the change of phase from a gas to either a liquid or a solid. When ice CRYSTALS condense out of humid air it is just as MUCH a PROCESS of condensation as when water droplets condense out of humid air

41.

How is liquefaction different from condensation

Answer»

Answer:

$\huge\underline{ \underline{ \red{your \: \:answer}}}$

Explanation:

LIQUEFACTION refers to the change of phase from a gas to a LIQUID. Condensation refers to the change of phase from a gas to either a liquid or a solid. When ice CRYSTALS condense out of humid air it is just as MUCH a PROCESS of condensation as when water droplets condense out of humid air

Discussion

42.	What is hard core of earth
Answer» ANSWER: CORE EARTH????? O don't KNOW

42.

What is hard core of earth

Answer»

ANSWER:

CORE EARTH????? O don't KNOW

Discussion

43.	Choose the correct option in the following chemical bonding bits
Answer» Answer: 3) p 4) d 5) i 6) h mark as BRANLIEST

43.

Choose the correct option in the following chemical bonding bits

Answer»

Answer:

3) p

4) d

5) i

6) h

mark as BRANLIEST

Discussion

44.	Pls solve this questionThe correct answer-T1=100/(root 3), T2=200/(root 3), T3=200/(root 3), T4=200
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\tt{\therefore{T_{1}=\frac{100}{\sqrt{3}}\:N}}}\\$ $\green{\tt{\therefore{T_{2}=\frac{200}{\sqrt{3}}\:N}}}\\$ $\green{\tt{\therefore{T_{3}=\frac{200}{\sqrt{3}}\:N}}}\\$ $\green{\tt{\therefore{T_{4}=200\:N}}}\\$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Mass \: of \: block = 10 \: kg \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Tension( T_{1}) = ?\\ \\ \tt: \implies Tension( T_{2}) = ?\\ \\ \tt: \implies Tension( T_{3}) = ?\\ \\ \tt: \implies Tension( T_{4}) = ?$ • ACCORDING to given QUESTION : $\bold{For \:component \: of\: tension( T_{4}) \: at \: point \: B}\\ \tt: \implies Horizontal \: component = T_{4} \: sin \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{4} \:sin \: 60 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{4} \sqrt{3} }{2} \\ \\ \tt: \implies Vertical\: component = T_{4} \: cos \: \theta \\ \\ \tt: \implies Vertical\: component = T_{4} \:cos \: 60 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{4}}{2} \\ \\ \bold{For \: Component \: of\: tension( T_{2} ) \: at \: point \: B}\\ \tt: \implies Horizontal \: component = T_{2} \: cos \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{2} \:cos \: 60 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{2} }{2} \\ \\ \tt: \implies Vertical\: component = T_{2} \: sin \: \theta$ $\tt: \implies Vertical\: component = T_{2} \:sin \: 60 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{2} \sqrt{3} }{2} \\ \\ \bold{For \:component \: of\: tension( T_{2}) \:at \: point \: A } \\ \tt: \implies Horizontal \: component = T_{2} \: sin \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{2} \:sin \: 30 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{2} }{2} \\ \\ \tt: \implies Vertical\: component = T_{2} \: cos \: \theta \\ \\ \tt: \implies Vertical\: component = T_{2} \:cos \: 30 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{4} \sqrt{3} }{2}$ $\bold{At \: point \: A\: in \: horizontal : } \\ \tt: \implies T_{1} = \frac{ T_{2} }{2} \\ \\ \tt: \implies 2T_{1} = T_{2} - - - - - (1) \\ \\ \bold{At \: point \: A \: in \: Vertical : } \\ \tt: \implies \frac{ T_{2} \sqrt{3} }{2} = mg \\ \\ \tt: \implies \frac{ T_{2} \sqrt{3} }{2} = 100 \\ \\ \green{\tt: \implies T_{2} = \frac{200}{ \sqrt{3} } \: N } \ \\ \\ \bold{At \: point \: B \: in \: vertical : } \\ \tt: \implies \frac{ T_{4} }{2} = \frac{ T_{2} \sqrt{3} }{2} \\ \\ \tt: \implies T_{2} = \frac{T_{4} }{ \sqrt{3} } \\ \\ \tt: \implies \frac{200}{ \sqrt{3} } = \frac{ T_{4}}{ \sqrt{3}}$ $\green{\tt: \implies T_{4} = 200 \: N} \\ \\ \bold{At \: point \: B \: in\: horizontal : } \\ \tt: \implies \frac{ T_{4} \sqrt{3} }{2} = T_{3} + \frac{ T_{2} }{2} \\ \\ \tt: \implies T_{4} \sqrt{3} - T_{2} = 2 T_{3} \\ \\ \tt: \implies 200 \sqrt{3} - \frac{200}{ \sqrt{3} } = 2 T_{3} \\ \\ \tt: \implies \frac{600 - 200}{ 2\sqrt{3} } = T_{3} \\ \\ \green{\tt: \implies T_{3} = \frac{200}{ \sqrt{3} } \: N} \\ \\ \text{Putting \: value \: of \: }T_{2} \: \text{in \: (1)} \\ \tt: \implies 2 T_{1} = \frac{200}{ \sqrt{3} } \\ \\ \tt: \implies T_{1} = \frac{200}{ 2\sqrt{3} } \\ \\ \green{\tt: \implies T_{1} = \frac{100}{ \sqrt{3} } \: N }$

44.

Pls solve this questionThe correct answer-T1=100/(root 3), T2=200/(root 3), T3=200/(root 3), T4=200

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{T_{1}=\frac{100}{\sqrt{3}}\:N}}}\\$

$\green{\tt{\therefore{T_{2}=\frac{200}{\sqrt{3}}\:N}}}\\$

$\green{\tt{\therefore{T_{3}=\frac{200}{\sqrt{3}}\:N}}}\\$

$\green{\tt{\therefore{T_{4}=200\:N}}}\\$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Mass \: of \: block = 10 \: kg \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Tension( T_{1}) = ?\\ \\ \tt: \implies Tension( T_{2}) = ?\\ \\ \tt: \implies Tension( T_{3}) = ?\\ \\ \tt: \implies Tension( T_{4}) = ?$

• ACCORDING to given QUESTION :

$\bold{For \:component \: of\: tension( T_{4}) \: at \: point \: B}\\ \tt: \implies Horizontal \: component = T_{4} \: sin \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{4} \:sin \: 60 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{4} \sqrt{3} }{2} \\ \\ \tt: \implies Vertical\: component = T_{4} \: cos \: \theta \\ \\ \tt: \implies Vertical\: component = T_{4} \:cos \: 60 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{4}}{2} \\ \\ \bold{For \: Component \: of\: tension( T_{2} ) \: at \: point \: B}\\ \tt: \implies Horizontal \: component = T_{2} \: cos \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{2} \:cos \: 60 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{2} }{2} \\ \\ \tt: \implies Vertical\: component = T_{2} \: sin \: \theta$

$\tt: \implies Vertical\: component = T_{2} \:sin \: 60 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{2} \sqrt{3} }{2} \\ \\ \bold{For \:component \: of\: tension( T_{2}) \:at \: point \: A } \\ \tt: \implies Horizontal \: component = T_{2} \: sin \: \theta \\ \\ \tt: \implies Horizontal \: component = T_{2} \:sin \: 30 \degree \\ \\ \tt: \implies Horizontal \: component = \frac{ T_{2} }{2} \\ \\ \tt: \implies Vertical\: component = T_{2} \: cos \: \theta \\ \\ \tt: \implies Vertical\: component = T_{2} \:cos \: 30 \degree \\ \\ \tt: \implies Vertical\: component = \frac{ T_{4} \sqrt{3} }{2}$

$\bold{At \: point \: A\: in \: horizontal : } \\ \tt: \implies T_{1} = \frac{ T_{2} }{2} \\ \\ \tt: \implies 2T_{1} = T_{2} - - - - - (1) \\ \\ \bold{At \: point \: A \: in \: Vertical : } \\ \tt: \implies \frac{ T_{2} \sqrt{3} }{2} = mg \\ \\ \tt: \implies \frac{ T_{2} \sqrt{3} }{2} = 100 \\ \\ \green{\tt: \implies T_{2} = \frac{200}{ \sqrt{3} } \: N } \ \\ \\ \bold{At \: point \: B \: in \: vertical : } \\ \tt: \implies \frac{ T_{4} }{2} = \frac{ T_{2} \sqrt{3} }{2} \\ \\ \tt: \implies T_{2} = \frac{T_{4} }{ \sqrt{3} } \\ \\ \tt: \implies \frac{200}{ \sqrt{3} } = \frac{ T_{4}}{ \sqrt{3}}$

$\green{\tt: \implies T_{4} = 200 \: N} \\ \\ \bold{At \: point \: B \: in\: horizontal : } \\ \tt: \implies \frac{ T_{4} \sqrt{3} }{2} = T_{3} + \frac{ T_{2} }{2} \\ \\ \tt: \implies T_{4} \sqrt{3} - T_{2} = 2 T_{3} \\ \\ \tt: \implies 200 \sqrt{3} - \frac{200}{ \sqrt{3} } = 2 T_{3} \\ \\ \tt: \implies \frac{600 - 200}{ 2\sqrt{3} } = T_{3} \\ \\ \green{\tt: \implies T_{3} = \frac{200}{ \sqrt{3} } \: N} \\ \\ \text{Putting \: value \: of \: }T_{2} \: \text{in \: (1)} \\ \tt: \implies 2 T_{1} = \frac{200}{ \sqrt{3} } \\ \\ \tt: \implies T_{1} = \frac{200}{ 2\sqrt{3} } \\ \\ \green{\tt: \implies T_{1} = \frac{100}{ \sqrt{3} } \: N }$

Discussion

45.	தேனீவில் உள்ள குழுக்கள் என்ன, don't answer if u don't know
Answer» ANSWER: மகரந்தம் ஆண் இனத்தை உற்பத்தி செய்யும் விதை செடிகளின் ஆண் நுண்ணுயிரிகளான மகரந்த தானியங்களைக் கொண்டிருக்கும் நுண்துகள்கள் நிறைந்ததாக இருக்கும். plzz MARK me as BRAINLIST ❣️❣️

45.

தேனீவில் உள்ள குழுக்கள் என்ன, don't answer if u don't know

Answer»

ANSWER:

மகரந்தம் ஆண் இனத்தை உற்பத்தி செய்யும் விதை செடிகளின் ஆண் நுண்ணுயிரிகளான மகரந்த தானியங்களைக் கொண்டிருக்கும் நுண்துகள்கள் நிறைந்ததாக இருக்கும்.

plzz MARK me as BRAINLIST ❣️❣️

Discussion

46.	A man travels a distance of 3km towards east
Answer» ANSWER: so, what is QUESTION......

46.

A man travels a distance of 3km towards east

Answer»

ANSWER:

so, what is QUESTION......

Discussion

47.	The measurement of the amountof heat in a body is called its______..(i will make you Brainlist )
Answer» BODY TEMPERATURE is the MEASUREMENT of body HEAT.

Discussion

48.	The amount of flux on a surface that is not perpendicular to the magnetic field is
Answer» Answer: Hope this helps. Please FOLLOW me and mark as Brainliest!:) Explanation: For a closed SURFACE, the sum of magnetic flux is always EQUAL to zero (Gauss' law for magnetism). No matter how small the volume, the magnetic SOURCES are always dipole sources (LIKE miniature bar magnets), so that there are as many magnetic field lines coming in (to the south pole) as out (from the north pole)

48.

The amount of flux on a surface that is not perpendicular to the magnetic field is

Answer»

Answer:

Hope this helps. Please FOLLOW me and mark as Brainliest!:)

Explanation:

For a closed SURFACE, the sum of magnetic flux is always EQUAL to zero (Gauss' law for magnetism). No matter how small the volume, the magnetic SOURCES are always dipole sources (LIKE miniature bar magnets), so that there are as many magnetic field lines coming in (to the south pole) as out (from the north pole)

Discussion

49.	The feeling of hotness and coldness of a body is called _______ ( I will make you Brainlist )
Answer» the FEELINGS of HOTNESS and coldness of a body is CALLED temperature

Discussion

50.	An ant travels a distance of 8 cm from p to q and then moves a distance of 6 cm at right angles to pq. What is the distance
Answer» ANSWER: From Q to P the ant travelled 8 cm. Then at P it moves 6 cm to QP at right angle. So, if you make a diagram, you will notice that a right angle will be formed if you draw a line. Displacement is the shortest distance between TWO points. So, the shortest path is the hypotenuse of the triangle. Using PYTHAGORAS theorem, Legs are 8 cm and 6 cm. 8^2 + 6^2 = 64 + 36 = 100 Square root of 100 = 10 So, the displacement should be 10 cm. *hope* it *helps... mark* as *Brainliast*

50.

An ant travels a distance of 8 cm from p to q and then moves a distance of 6 cm at right angles to pq. What is the distance

Answer»

ANSWER:

From Q to P the ant travelled 8 cm.

Then at P it moves 6 cm to QP at right angle.

So, if you make a diagram, you will notice that a right angle will be formed if you draw a line.

Displacement is the shortest distance between TWO points.

So, the shortest path is the hypotenuse of the triangle.

Using PYTHAGORAS theorem,

Legs are 8 cm and 6 cm.

8^2 + 6^2 = 64 + 36 = 100

Square root of 100 = 10

So, the displacement should be 10 cm.

hope it helps...

mark as Brainliast

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Two necessary conditions for a satellite to be geostationary​

Now last question a body moving with velocity 10 m/s, experience a retardation of 4 m/s². Find the distance travelled in 3 seconds.​

Where v is 10 m/s,

Retardation is 4 m/s^2,

TIME is 3 seconds.

10-u/3=4,

10-u=4*3,

10-u=12,

-u=12-10,

-u=2,

So 10-2,

8 m is the distance travelled.

I think it is correct.

Hope it helps you.

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• ACCORDING to given QUESTION :

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plzz MARK me as BRAINLIST ❣️❣️

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Answer my all questions

Equation for effective resistance when three resistance in series and parallel.

Sir plz solve the 36th question as fast as you can please

you are given three resistors each of 6 ohm .How will You connect them to obtain the resistance of 9 ohm?

Given r = 4j and p = 2i+3j+k. The angular momentum is

Draw a circuit diagram to showtwo 4 volts lamp can be lot brightly from two volts cell.

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Answer plzz give me and explain it

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Pls explain what happens here. and no spam plss

An acid with a base to form a salt and water this type of reaction is called

How is liquefaction different from condensation

What is hard core of earth

Choose the correct option in the following chemical bonding bits

தேனீவில் உள்ள குழுக்கள் என்ன, don't answer if u don't know

The measurement of the amountof heat in a body is called its______..(i will make you Brainlist )

The feeling of hotness and coldness of a body is called _______ ( I will make you Brainlist )