Mass of block is 8 kg. The minimal force required to move the block up

1.	Mass of block is 8 kg. The minimal force required to move the block up if the coffiction of friction µ = 0.3. Take g = 10 m.s-2
Answer» Answer: 67.3 N Explanation: An diagram is attached for better understanding. Here, Normal REACTION is EQUAL to mg.cos37° So, Friction on block is μ . mg. cos37° ⇒ 0.3 x mg x cos37° Also, one of the component of weight is acted with the friction. Total force acted opposite the force for lifting is ( 0.3 mg . cos37° ) + ( mg sin37° ) MINIMUM force required = ( 0.3 mg cos37° ) + ( mg sin37° ) ⇒ mg( 0.3 cos37° + sin37° ) You can USE the approx values of cos37° and sin37°, here, I am directly writing 0.3 cos37° + sin37° as 0.8414 ⇒ 8 x 10( 0.8414 ) N ⇒ 8 x 8.414 N ⇒ 67.3 N ( approx ) MIN. force required is 67.3 N

Mass of block is 8 kg. The minimal force required to move the block up if the coffiction of friction µ = 0.3. Take g = 10 m.s-2

Answer»

Answer:

67.3 N

Explanation:

An diagram is attached for better understanding.

Here,

Normal REACTION is EQUAL to mg.cos37°

So,

Friction on block is μ . mg. cos37°

⇒ 0.3 x mg x cos37°

Also, one of the component of weight is acted with the friction.

Total force acted opposite the force for lifting is ( 0.3 mg . cos37° ) + ( mg sin37° )

MINIMUM force required = ( 0.3 mg cos37° ) + ( mg sin37° )

⇒ mg( 0.3 cos37° + sin37° )

You can USE the approx values of cos37° and sin37°, here, I am directly writing 0.3 cos37° + sin37° as 0.8414

⇒ 8 x 10( 0.8414 ) N

⇒ 8 x 8.414 N

⇒ 67.3 N ( approx )

MIN. force required is 67.3 N

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