A body of mass 17kg is initially at rest on a horizontal frictionless

1.	A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?And the work done by the force in kilo joules?
Answer» Explanation: by second law of motion by newton FORCE =Mass×Acceleration 50N=17kg×A A=3m/s² (approx) time =v-u/a v=final VELOCITY u=initial velocity 18-0/3=6seconds DISTANCE =ut+1/2at² (second EQUATION of motion) distance =0×6+1/2×3×6² =0+1/2×3×36 =54m work =force×displacement 50×54 2700J or N.m 1000J=1KJ 2700J=2.7KJ hope you got it please mark me the brainliest

A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?And the work done by the force in kilo joules?

Answer»

Explanation:

by second law of motion by newton

FORCE =Mass×Acceleration

50N=17kg×A

A=3m/s² (approx)

time =v-u/a

v=final VELOCITY u=initial velocity

18-0/3=6seconds

DISTANCE =ut+1/2at² (second EQUATION of motion)

distance =0×6+1/2×3×6²

=0+1/2×3×36

=54m

work =force×displacement

50×54

2700J or N.m

1000J=1KJ

2700J=2.7KJ

hope you got it

please mark me the brainliest

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A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?And the work done by the force in kilo joules?

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