Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What must be the height of the antenna of FM radio station so that people in a circular region of 3140 km² can enjoy the programme of an FM radio station? [R = 6400 km] [Ans: 78.125 m]

Answer» SEARCH on GOOGLE
2.

The A.C current gain of a PNP common emitter circuit is 100. The value of the input resistance is 1 kΩ. What should be the value of the load resistor RL in order to obtain power gain of 2000 ?[Ans:RL= 200 Q]

Answer»
3.

The collector current changes by 10 mA when the input voltage of the NPN common emitter amplifier changes by 100 mV. The A.C current gain of this circuit is equal to 150. If We have to obtain a power gain of 4500 then what should be the value of the load resistance? [ RL= 300 Ω]

Answer»
4.

In order to cover a circular region of radius 16 km, by a TV transmitter What must be the height of the transmitting antenna? (Radius of the earth = 6400 km),choose the correct option from the given options. (A) 0.02 km (B) 0.2 km (C) 0.1 km (D) 2 km

Answer»

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5.

If the frequency of 3 kHz signal has to be transmitted through amplitude modulation. Which of the following frequency should use as a carrier frequency?choose the correct option from the given options. (A) 30 HZ (B) 300 HZ (C) 3000 HZ (D) 3 MHZ

Answer»
6.

The Width of a depletion region is 400 nm.The intensity of the electric field at the depletion region is 5*10⁵ V/m. Then calculate the following quantities : (1) The value of the potential barrier. (2) The minimum energy required by an electron to move from the N-type to the P-type region of the diode. [Ans: 0.2 V, 0.2 eV]

Answer» N. A. = 2 × 10. 16 cm. −3 . Calculate the built-in potential V BI in eV and the total width of the DEPLETION region W = xn0 + xp0 at zero.
7.

If an LED has to emit 662 nm wavelength of light Lhen what should be the band gap energy of its semiconductor? [h= 6.62*10⁻³⁴ J S] [Ans: 1.875 eV]

Answer»

udent,◆ Answer -BGE = 1.875 eV◆ Explaination -BAND gap energy of LED is SEMICONDUCTOR is -BGE = hc/λIn electron VOLTS, this is represented as -BGE = hc/eλBGE = (6.62×10^-34 × 3×10^8) / (1.6×10^-19 × 662×10^-9)BGE = 1.875 eVThanks for ASKING. Hope this helps you...

8.

The density of electron hole pair in a pure semiconductor at 300 K temperature is 1.5*10¹⁶ m⁻³. The number density of the majority charge carriers becomes equal to 4.5*10²²m⁻³ on adding trivalent impurity atoms. What will be the number density of the minority charge carriers in the above sample? [ 5*10⁹ m⁻³]

Answer»

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9.

There are 6*10¹⁹ electrons per unit cubic metre of pure semiconductor. What will be the number of holes for this semiconductor of dimension 1 cm*1 cm*2 cm? [Ans: 12*10¹³ ]

Answer»

udent,◆ Answer -Nh = 1.2×10^14 holes◆ Explaination -No of ELECTRONS in the semiconductor is -NE = 1×10^-2 × 1×10^-2 × 2×10^-2 × 6×10^19Ne = 1.2×10^14 e-We know that no of holes is EQUAL to no of electrons, thus no of holes in semiconductor is 1.2×10^14. i.e. Nh = 1.2×10^14 holes.Hope this HELPS you..

10.

Draw the logic diagram of a NAND gate. Give the symbol, Boolean expression and truth table of it.

Answer»

your ANSWER. HOPE it HELPS.........

11.

Find the position of the image of an object placed at a distance of 12 cm from a convex mirror of focal length 10cm​

Answer»

given OBJECT distance u = - 12cm (by using SIGN convention). The FOCAL length of the convex mirror, f = 10cm.From mirror formula,The image distance is 5.45 CM.

12.

the refractive index of atmospheric layers decreases with increase in height above the earths surface . if we view near the horizon , the apparent position of a star will be​

Answer»

i THINK POSITION of STAR will be FARTHER from the actual PLACE

13.

Question for You ♦Brainliest Question​

Answer» X = 9Explanation:PLEASE LOOK at the ATTACHMENT.
14.

- The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through adistance of 10 m is:​

Answer» 98 JExplanation:PLEASE MARK ME AS BRAINLIEST IF YOU LIKE MY ANSWER!!!
15.

Aboit auditory nerve​

Answer»

Heya MATE.....The auditory nerve is a BUNDLE of nerve FIBERS that carries HEARING INFORMATION between the cochlea the brain.Hope it helps.....

16.

What is density... ​

Answer»

The density of the SUBSTANCE is DEFINED as MASS of the substance PER unit VOLUME.Density= Mass / volume

17.

Answerrererrr it will mark it as brailest answer ​

Answer» PLEASE MARK it as BRAINLIEST ANSWER
18.

Draw the circuit of a CE amplifier using NPN transistor. Obtain the expression for the voltage gain and power gain of CE amplifier.

Answer»

mon emitter amplifier is a three basic single stage bipolar JUNCTION transistor and is used as a voltage amplifier. The INPUT of this amplifier is taken from the base terminal, the OUTPUT is COLLECTED from the COLLECTOR terminal and the emitter terminal is common for both the terminals. The basic symbol of the common emitter amplifier is shown below. open the links https://www.elprocus.com/wp-content/uploads/2016/10/What-is-a-Common-Emitter-Amplifier.jpghttps://www.elprocus.com/wp-content/uploads/2016/10/Working-of-Common-Emitter-Amolifier.jpg

19.

Write a short note on P-type semiconductor.

Answer»

e semiconductor is a type of semiconductor. Ordinary semiconductors are made of materials that do not conduct (or CARRY) an electric current very well but are not highly resistant to doing so. They fall half way between CONDUCTORS and insulators. An electric current OCCURS when electrons move through a material. In order to move, there must be an electron 'hole' in the material for the electron to move into. A p-type semiconductor has more holes than electrons. This allows the current to flow along the material from hole to hole but only in one direction. Semiconductors are most often made from silicon. Silicon is an element with four electrons in its OUTER shell. To make a p-type semiconductor extra materials like boron or aluminium are added to the silicon. These materials have only three electrons in their outer shell. When the extra material replaces some of the silicon it leaves a 'hole' where the fourth electron would have been if the semiconductor was pure silicon.

20.

Which are the basic logic gates and universal logic gates?

Answer»

re total 7 LOGICAL gates:- AND, OR, NOT, NAND, NOR, XOR, XNOR. Among all the gates, AND, OR & NOT gate are Basic gates, because these THREE gates have basic operation. NOR & NAND gates are known as universal gates. They are simply a NOT gate ADDED AND & OR gate.

21.

Explain the valence band, conduction band and forbidden gap of Si semiconductor.

Answer»

tion:valence band is the thin LAYER of some wires CONNECTED .it is related to the ELEMENTS CONDUCTION band is the conducting wiresemiconductor conducts both elements and compounds

22.

What is the phase difference between input and output signal of a CE amplifier?

Answer»

i DONT knowExplanation:

23.

Give the relation between Ie, Ic and Ib. Also give the order of their magnitude.

Answer» TION:Ie =Ib+Ic where Ie is proportional to both Ib and Ic.Thus, the VALUE of Ib and Ic can never be individually greater than that of Ie.Let ALPHA (a) be the proportionality constant between Ie and Ic andBeta (B) be the proportionality constant between Ib and IcTherefore, For Active Region,The collector junction is reversed biased (Jc) and the EMITTER junction (Je) is forward biasedTherefore Ic = Ie × a and Ic = Ib × bFor SATURATION region,Both Jc and Je are forward biasedTherefore,Ie(saturation) = aIe and Ic (saturation) =BIb.For Cut off region,Both Jc and Je are reversed biasedTherefore,Ib = Ic = Ie = 0
24.

Write the Boolean equation of a NOR gate.

Answer»

A+BExplanation:The BOOLEAN EQUATION or NOTATION of a NOR GATE is A+B

25.

Write the equation for maximum wavelength of a light emitted from LED.

Answer» AMONG this purple has the LOWEST wavelength and red has MAXIMUM wavelength
26.

What is the value of photovoltage produced in a photo cell?

Answer»

tripically the VOLTAGE of a PHOTO CELL is 0.7v

27.

What is called filter circuits?

Answer»

A FILTER CIRCUIT is a device to remove the A.C. COMPONENTS of the RECTIFIED output but allows D.C. components to reach the load

28.

Draw a circuit symbol of a PN junction diode. What does the arrow indicate?

Answer»

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29.

Draw a band diagram of a N-type semiconductor at room temperature.

Answer»

Explanation:Mark as BRAINLY and give ratings N-type SEMICONDUCTOR. An N-Type semiconductor is created by adding pentavalent impurities like phosphorus (P), arsenic (As), ANTIMONY (Sb), or bismuth (Bi). A pentavalent impurity is called a DONOR ATOM because it is ready to give a free electron to a semiconductor. The impurities are called dopants.

30.

Can we consider a hound electron as a free electron? Why?

Answer»

noExplanation:

31.

For detecting the light..................,choose the correct option from the given options. (A) The photodinde has to be forward biased. (B) The photodiocle has tn be reverse biased. (C) The LED has to be connected in forward bias mode. (D) The LED has to be connected in a reverse bias mode.

Answer»

(C)Explanation:The LED has to be CONNECTED in FORWARD bias MODE for detecting the light.hope it helps pls mark me brainliest

32.

The collector has current of the NPN transistor is equal to 10 mA. If 90% of the electron from the emitter reaches collector then ......,choose the correct option from the given options. (A) Ie ≈ 9 mA, Ib ≈ 1mA (B) Ie ≈ 11 mA, Ib ≈ 9 MA (C) Ie ≈ 11 mA, Ib ≈ 1m (D) Ie ≈ 10 mA, Ib ≈ 1m

Answer»

c) Ie ≈ 11 mA, Ib ≈ 1m Explanation:Collector CURRENT = Ic = 10mA (GIVEN)Percentage of the electron reaching the collector = 90% (Given)Thus, Ic = 90% of IeIc = 90/100 × IeIe = Ic × 100/90Ie = 10 × 100/90Ie = 1000/90Ie = 11.11Base current = Ib = Ie-Ic= 11.11 - 10= 1.1Therefore, If 90% of the electron from the emitter reaches collector then there will be Ie ≈ 11 mA, Ib ≈ 1m

33.

The energy band diagram of a Si semiconductor crystal at absolute zero temperature.........,choose the correct option from the given options. (A) has completely empty valence band and completely filled conduction band. (B) has completely empty conduction band and completely filled valence band. (C) has completely empty valence and conduction band and completely filled forbidden gap. (D) the conduction band is partially filled.

Answer»

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34.

Half life of Ra²²⁶ is 4.98*10¹⁰ s. Find the activity of its 1 g specimen. Take Avogadro number as 6.02*10²³ mol⁻¹ [Ans: 1Ci]

Answer»

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35.

Mass of 17^35 CI nucleus is 34.9800 u. Taking the mass of proton as 1.00783 u and that of neutron as 1.00866 u, find the binding energy per nucleon for 17^35 CI nucleus.[Ans: 8.219 Mev/nucleon]

Answer»

udent,◆ Answer -BE/nucleon = 8.2238 MeV◆ Explanation -Mass DEFECT of Cl is calculated by -∆m = (mp.np + mn.nn) - M∆m = (17×1.00783 + 18×1.00866) - 34.98∆m = 0.309 uBinding ENERGY PER nucleon is calculated as -BE/nucleon = 931.5 ∆m/(nm+nn)BE/nucleon = 931.5 × 0.309 / (17 + 18)BE/nucleon = 8.2238 MeVHope this HELPS you...

36.

Two protons in a star are involved in a head on collision. If the kinetic energy of each of these protons is 18 keV, what would be the distance of closest approach between them? (k=9*10⁹ Nm² C⁻²) [Ans: 4*10⁻¹⁴ m]

Answer»

udent,◆ Answer -d = 4×10^-14 m◆ EXPLANATION -# Given -E = 18 KeV E = 18×10^3×1.6×10^-19 JE = 2.88×10^-15 J q1 = +1.6×10^-19 Cq2 = +1.6×10^-19 C# Solution -Closest distance of APPROACH between two protons is CALCULATED as -d = k.q1.q2/E'd = k.e^2/(2E)d = 9×10^9 × (1.6×10^-19)^2 / (2 × 2.88×10^-15)d = 4×10^-14 mTherefore, closest distance of approach between two protons is 4×10^-14 m.Thanks DEAR...

37.

Explain the thermonuclear fusion in the Sun and other stars.

Answer»

this is your CORRECT ANSWER

38.

Discuss nuclear hazards.

Answer»

this is your CORRECT ANSWER

39.

power depend on force time and mass derived the formula for power in term of force time and mass by using dimensional analysis ​

Answer»

Power=force *MASS /timeExplanation:=

40.

What are direct band gap and indirect band gap semiconductors??? plz reply clearly starting from basics to advanced

Answer»

Optical measurement can determine the band gap is direct or not. The absorption spectrum of direct band gap materials should be able to more clearly distinguish intrinsic absorption band and absorption edge, the CHANGE is relatively slow, but that for INDIRECT band gap materials is steep. Explanation:

41.

And 0.2 ohms internal resistance each are 11. What is the circuit current if 24 cells of 2V enconnected in parallel across a load resistor ofa) 0.199 Ab) 0.299 Asistor of 10 ohmns?c) 0.399 A6 0.499 A​

Answer»

I THINK 0.199 is the CORRECT ANSWER

42.

Explain nuclear reactor with its working.

Answer»

They contain and control nuclear CHAIN REACTIONS that produce HEAT through a physical process called fission. That heat is used to make steam that spins a TURBINE to create electricity.The main job of a reactor is to house and control nuclear fission—a process where atoms split and release energy.Reactors use uranium for nuclear fuel. The uranium is processed into small ceramic pellets and stacked together into sealed METAL tubes called fuel rods. Typically more than 200 of these rods are bundled together to form a fuel assembly. A reactor core is typically made up of a couple hundred assemblies, depending on power level. Inside the reactor vessel, the fuel rods are immersed in water which acts as both a coolant and moderator. The moderator helps slow down the neutrons produced by fission to sustain the chain reaction.

43.

What is meant by the average life of a radioactive element? Obtain its formula.

Answer»

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44.

Which are the radioactive radiations? Mention their properties.

Answer»

tion:RADIOACTIVE RADIATION SANDOZ radiations which has generated by the earth and their moons properties is that they can CAUSE burns to any and everything present on this earth give the DAY

45.

What is a nuclear chain reaction? Explain the difficulties and their removal in its success.

Answer»

Nuclear Chain Reactions. A chain reaction refers to a PROCESS in which neutrons RELEASED in fission PRODUCE an additional fission in at least one further nucleus. This nucleus in turn PRODUCES neutrons, and the process repeats. The process may be controlled (nuclear power) or uncontrolled (nuclear weapons).

46.

Explain the Q-value of a nuclear reaction.

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47.

Define the unit ‘curie’ for the activity.

Answer»

ie is a unit of ionizing radiation (radioactivity). It's symbol is CI. 1Ci=3.7 X 10^10Bq (DISINTEGRATIONS or nuclear transformations per second). This is approximately the amount of radioactivity emitted by one gram (1 g) of radium-226.The unit is named after Pierre Curie, a French PHYSICIST

48.

Explain the rate of disintegration of a radioactive element and the decay constant.

Answer»

The rate of radioactive DECAY, i.e. the rate at which an element disintegrates is measured by counting the number of or -particles emitted per unit time. ... It is found that for any given radioactive element, the rate at which it disintegrates at any INSTANT of time is proportional only to the number of ATOMS present.

49.

Define half—life of a radioactive element and obtain its formula.

Answer»

I don't know the formula ( you can google it) but I can EXPLAIN you what is half life of a RADIOACTIVE element.Half-Life is a period in which the radioactive element gets halved in quantity...i.e. for EXAMPLE , a 100 gram radioactive element have a half life of 5 years.So, after 5 years it will become 50 grams.in next 5 years the amount will be reduced to 25 grams.Similarly, for another five years the amount remaining will be 12.5 grams.So, ACCORDINGLY you can SAY that the radioactive element can never be 100% destroyed.

50.

Give a brief account of nuclear forces.

Answer»

clear Forces Figure 1: The atomic nucleus made up from protons (yellow) and NEUTRONS (blue) and held together by nuclear forces.Nuclear forces (also known as nuclear interactions or strong forces) are the forces that act between two or more nucleons. They bind protons and neutrons (“nucleons”) into atomic nuclei. The nuclear force is about 10 millions times stronger than the chemical binding that holds ATOMS together in molecules. This is the reason why nuclear reactors produce about a million times more energy per kilogram fuel as compared to chemical fuel like oil or coal. HOWEVER, the range of the nuclear force is short, only a few femtometer (1 FM =10−15 m), beyond which it decreases rapidly. That is why, in spite of its enormous strength, we do not feel anything of this force on the atomic scale or in everyday life. The development of a proper theory of nuclear forces has occupied the MINDS of some of the brightest physicists for seven decades and has been one of the main topics of physics research in the 20th century. The original idea was that the force is caused by the exchange of particles lighter than nucleons known as mesons, and this idea gave rise to the birth of a new sub-field of modern physics, namely, (elementary) particle physics. The modern perception of the nuclear force is that it is a residual interaction (similar to the van der Waals force between neutral atoms) of the even stronger force between quarks, which is mediated by the exchange of gluons and holds the quarks together inside a nucleon.