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Mass of 17^35 CI nucleus is 34.9800 u. Taking the mass of proton as 1.00783 u and that of neutron as 1.00866 u, find the binding energy per nucleon for 17^35 CI nucleus.[Ans: 8.219 Mev/nucleon]

Answer»

udent,◆ Answer -BE/nucleon = 8.2238 MeV◆ Explanation -Mass DEFECT of Cl is calculated by -∆m = (mp.np + mn.nn) - M∆m = (17×1.00783 + 18×1.00866) - 34.98∆m = 0.309 uBinding ENERGY PER nucleon is calculated as -BE/nucleon = 931.5 ∆m/(nm+nn)BE/nucleon = 931.5 × 0.309 / (17 + 18)BE/nucleon = 8.2238 MeVHope this HELPS you...



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