If an LED has to emit 662 nm wavelength of light Lhen what should be the band gap energy of its semiconductor? [h= 6.62*10⁻³⁴ J S] [Ans: 1.875 eV]

If an LED has to emit 662 nm wavelength of light Lhen what should be t

1.	If an LED has to emit 662 nm wavelength of light Lhen what should be the band gap energy of its semiconductor? [h= 6.62*10⁻³⁴ J S] [Ans: 1.875 eV]
Answer» udent,◆ Answer -BGE = 1.875 eV◆ Explaination -BAND gap energy of LED is SEMICONDUCTOR is -BGE = hc/λIn electron VOLTS, this is represented as -BGE = hc/eλBGE = (6.62×10^-34 × 3×10^8) / (1.6×10^-19 × 662×10^-9)BGE = 1.875 eVThanks for ASKING. Hope this helps you...

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If an LED has to emit 662 nm wavelength of light Lhen what should be the band gap energy of its semiconductor? [h= 6.62*10⁻³⁴ J S] [Ans: 1.875 eV]

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