This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Explain natural radioactivity. |
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Answer» Explanation:Natural Radioactivity Radioactivity surrounds us Radioactivity is an integral part of our environment. All living beings have been exposed to a constant flux of natural radiation on the surface of our friendly planet: to no NEGATIVE effect. The natural radioactivity of rocks: We find the majority of naturally-occurring radioactive elements in rocks. This section of the NUCLEUS graph shows the successive radioactive disintegrations that lead from uranium-238 to radon. The ‘descendants’ of uranium-238, present in trace amounts in these minerals, emit alpha and beta rays which remain trapped inside the rocks. Gamma rays, on the other hand, are able to escape. The SIXTH descendant of uranium – radon, as shown above – is a gas. Large amounts of it are therefore able to escape from the ground, thereby releasing radiation into the atmosphere. IN2P3 Natural radioactivity is still the principal source of radiation exposure. In France, the exposure dose is 2.4 millisieverts per person per year, as opposed to 1mSv from medical examinations. This is, of course, an average, and location and lifestyle play equal roles in determining the level of exposure. Where one travels, where one lives and even whether or not one uses air conditioning are all important factors. We are constantly being bombarded by particles of cosmic radiations : several hundred go through our bodies every second. Rocks like granite, which have become symbols of permanence and durability, contain light traces of radioactive uranium. SITTING on or walking near a block of granite exposes you to previously unencountered sources of radioactivity. Even the food we eat or the air we breathe contains radioactive elements – either formed thanks to the intervention of cosmic rays, or as old as the solar system itself. There is absolutely no way to escape from it: even we are radioactive! Eight thousand atoms of potassium 40 or carbon 14 disintegrate in our bodies every second. The role of radon Continuation of the uranium decay chain. Radon, which, being a gas, escapes from its underground prison, decays comparatively quickly into lead-210: a radioactive substance which survives for decades. The chain finally ends with the stable isotope lead-206. If the radon source is deep underground, then radon may not have the time to reach the surface; in which case, the radioactivity stays in the soil. If the radon does manage to break through, however, some of its decay products can be harmful to human lungs. IN2P3 The most important natural source of radioactivity is a rare gas known as radon. One of the products of uranium decay, radon is an ‘inert gas’ that can participate in no chemical reaction. This would seem to make it completely harmless, were it not for the fact that radon own radioactive decay produces gases poisonous to humans. The nature of the soil you live on, the construction tools used to build your house and the quality of its air conditioning are all crucial factors in determining radon exposure. It is important to stress, at this point, that 2.4 mSv is a low dose. In certain parts of India, China and Brazil the natural exposure level rises to 10 or even 20 mSv a year. The fact that humans have survived these comparatively overexposed conditions INDICATES that all doses of the order of millisieverts are negligible and very likely harmless.plz mark brainliest |
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| 2. |
What is the function of the control rods in a nuclear reactor? |
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Answer» The control rods manages the USE of radioactive ELEMENTS by absorbing EXTRA RADIATIONS and also manages the control of reaction. |
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| 3. |
5 mCi =................Bq. (fill in the blank) |
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Answer» 185000000bqExplanation:As 1mCi= 37000000bqSo you can MULTIPLY by 5 to GET ANSWER |
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| 5. |
What is meant by multiplication factor (K) in a nuclear chain reaction? |
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| 6. |
What is the meaning of rate of disintegration? |
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Answer» tion:The disintegration rate is independent of temperature, concentration, etc. In any case, the number of RADIOACTIVE element atoms disintegrating in unit time is PROPORTIONAL to the number of atoms present. The number of atoms breaking up at any moment is proportional to the number of atoms present at that moment.The disintegration rate of a specific substance relies on the nature and the complete quantity of the disintegrating MATERIAL. The rate of disintegration of radioactive material is regardless of physical and CHEMICAL CIRCUMSTANCES. |
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| 7. |
What is artificial nuclear disintegration? |
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Answer» brainly and give ratingsArtificial disintegration is the term coined by Ernest Rutherford for the process by which an atomic nucleus is broken down by BOMBARDING it with high speed alpha particles, either from a PARTICLE accelerator, or a naturally decaying radioactive SUBSTANCE such as radium, as Rutherford ORIGINALLY USED. |
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| 9. |
In a specimen the number of nuclei of a radioactive element at t = 0 time is 2048. If its half life is 5 hr, how many nuclei would have been disintegrated in 25 hr? |
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Answer» udent,◆ ANSWER -1984 nuclei● Explaination -Nuclei remanining after 25 HOURS are GIVEN by -N = N0.(1/2)^(t/t½)N = 2048 × (1/2)^(25/5)N = 2048 × 1/2^5N = 2048 / 32N = 64 nucleiNo of nuclei disintegrated are -∆N = N - N0∆N = 2048 - 64∆N = 1984 nucleiTherefore, 1984 nuclei are disintegrated in 25 hours.Thanks dear... |
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| 10. |
1g radioactive element reduces to 1/3g after 2 days. After total 6 days how much mass will remain?choose the correct option from the given options. (A) 1/27 g (B)1/6 g (C) 1/9 g (D) 1/12 g |
| Answer» R,◆ Answer -(A) A2 = 1/27 g◆ Explanation -Amount of radioactive element at VARIOUS times is related as -A2/A0 = (A1/A0)^(t2/t1)A2/1 = (1/3)^(6/2)A2 = 1/3^3A2 = 1/27 gTherefore, after 6 days radioactive element will be 1/27 g.Thanks dear. HOPE this helps you.. | |
| 11. |
What do mean by force? |
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Answer» y Good MORNING Here is your ANSWER PUSH or PULL of an object is CALLED as force buddy. Hope it help you Please mark me please #sibi |
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| 12. |
Refraction of light |
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Answer» In PHYSICS, refraction is the change in direction of a WAVE passing from one medium to another or from a GRADUAL change in the medium. Refraction of LIGHT is the most commonly observed phenomenon, but other waves such as sound waves and water waves also experience refraction.Pls MARK me as brainliest |
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| 13. |
What is Task Pane ......?? |
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Answer» 0 !!Answer: ◽The Task Pane is a rectangular Window that may appear on the right of the screen when Word OPENS. ◽It acts As an open MENU , giving a list of functions and COMMANDS to perform depending on what one is doing at the moment...Explanation: ◽If The Task Pane Does Not Show Up:- ⚪To reopen A Task Pane That has been closed,go to the VIEW menu then select Task Pane And it will reappear to the right of the screen ◽ Closing the task Pane:- ⚪If one wants to close the task pane , click on the X on the upper right corner of the pane .......❤❤❤❤❤❤❤ HOPE IT HELPFUL#Hopēless_ Romañtic ❣❣❣ |
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| 14. |
A snail covers a distance of100meter in 50hour calculate the average speed of snail in km/h |
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Answer» Explanation:Given :-Distance traveled by the snail, S = 100 m = 0.1 kmTime taken by the snail, t = 50 HourTo Find :-AVERAGE SPEED of snail.Formula to be USED :-Average speed = TOTAL distance TRAVELLED/ Total time takenSolution :-Putting all the values, we getAverage speed = Total distance travelled/ Total time takenAverage speed = (0.1/50) km/hAverage speed = 0.002 km/hHence, the average speed of snail is 0.002 km/h. |
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| 15. |
Solve question no.27with full explanation |
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Answer» See answer in above PICTURE EXPLANATION:KR diya solve DEKH LE answer Option 2 is correct |
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| 16. |
why only electricity transfer through electric wire's? and how can transfer electricity wireless? plzz explain. |
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Answer» Explanation:WPT (Wireless Power Transmission) Technology WPT technology is an old technology and it was demonstrated by “Nikola Telsa” in the year 1980. Wireless power transmission mainly uses three main systems such as microwaves, solar cells and resonance. Microwaves are used in an electrical device to transmit electromagnetic radiation from a source to a receiver. Accurately the name WPT states that, the electrical power can be transferred from a source to a device without using wires. Basically, it includes two coils they are a transmitter coil & a receiver coil. Where the transmitter coil is powered by AC current to create a magnetic field, which in turn induces a voltage in the receiver coil. Wireless Power Transmission Technology Wireless Power Transmission Technology The basics of wireless power transmission include the inductive energy that can be transmitted from a transmitter coil to a receiver coil through an oscillating magnetic field. The DC current supplied by a power source is changed into high frequency AC current by particularly designed electronics built into the transmitter. In the TX (transmitter) section, the AC current increases a copper wire, that creates a magnetic field. Once an RX (Receiver) coil is located near to the magnetic field, then the magnetic field can induce an AC current in the receiving coil. Electrons in the receiving device, converts the AC current back into DC current, that BECOMES working power. Wireless Power TRANSFER Circuit The simple wireless power transmission circuit is shown below. The required components of this circuit mainly include 20-30 magnet wire (gauge copper wire), A battery-1, transistor (2N2222) and LED.The construction of this circuit comprises of a transmitter and a receiver. Wireless Power Transfer Circuit Wireless Power Transfer Circuit Transmitter Take a PVC pipe and whirl a wire on it SEVEN times after whirling a wire about three inches make a loop for center terminal and continue the process. Now take transistor 2N2222 and connect its base terminal to one end of the copper coil, the collector terminal to the other end of the copper coil and now connect the emitter terminal to the negative (–ve) terminal of AA battery. The center terminal of the copper coil will be connected with the positive (+ve) terminal of an AA battery. When then the receiver coil is placed 1 inch above of the transmitter coil, then the LED will blink. Receiver Make a 15 turn copper coil and connect a light emitting diode to its ends. Wireless Power Transfer Circuit Working The wireless power transmission can be defined as, the energy can be transmitted from the transmitter to a receiver through an oscillating magnetic field. X To accomplish this, power source (DC current) is changed into high frequency AC (Alternating Current) by particularly designed electronics erected into the transmitter. The AC boosts a copper wire coil in the transmitter, which produces a magnetic field. When the receiver coil is placed in proximity of the magnetic field, the magnetic field can make an AC (alternating current) in the receiving coil. Electronics in the receiving coil then alters the AC back into DC which becomes operating power. Application of Wireless Power Transfer The main intention of this project is to design a WPT system in 3D space (transfer power within a SMALL range) and the block diagram of this project is shown below.The block diagram of the wireless power transfer mainly builds with HF transformer, capacitors, diode, rectifier, inductor coil FILLED with air and lamp. The person is mandatory to be worked every year to change the battery. This project is designed to charge a rechargeable battery wirelessly. Since charging of the battery is not possible to be demonstrated, we are providing a DC fan that runs through wireless power. Application of Wireless Power Transfer by Edgefxkits.com Application of Wireless Power Transfer by Edgefxkits.com Thus the power transfer can be done with the transmitter (primary) to the receiver (secondary) that is separated by a considerable distance (say 3cm). Therefore the power transfer could be seen as the TX transmits and the RX receives the power to run a load. Moreover, WPT technique can be used to charge the gadgets like mobile phone, laptop battery, iPod, propeller clock, etc. And also this sort of charging offers a far lower risk of electrical shock. Furthermore, this project can be enhanced by increasing the distance of power transfer as the research across the world is still going onplz mark brainliest |
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| 17. |
A stone of mass 5 kg is teid to a string of length 0.2 m. If the breaking tension of the string is 900N, then the maximum angular velocity, the sonecan have in uniform circular motion is(1) 30 rad s-1(2) 20 rad s-1(3) 10 rad s-1 (4) 40 rad s-1 |
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| 18. |
Which symbol is used to denote endothermic exothermic in a chemical reaction |
| Answer» NEGATIVE for EXO(-)and for ENDO(+) | |
| 19. |
After a time interval equal to 3 half-lives; how many times would (a) the activity of a radioactive element be, of its initial activity ? Or (b) mass of a radioactive element be, of its initial mass or (c) number of nuclei of a radioactive element be of its initial number?choose the correct option from the given options. (A) 2³ (B) 3² (C) 1/3² (D) 1/2³ |
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Answer» cffgyu7uhhyyuuuuufggfffgfffffggggyffggggggghgggggfffffffffttttfffg |
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| 20. |
At what temperature will the average molecular kinetic energy in gaseous hydrogen be equal to the binding energy of a hydrogen atom ? Boltzmann constant Kb = 1.38*10⁻²³ JK⁻¹ [Ans: 1.051*10⁵ K] |
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Answer» udent,◆ Answer -T = 1.05×10^5 K◆ EXPLAINATION -GIVEN that average molecular kinetic energy in GASEOUS hydrogen is EQUAL to the binding energy of a hydrogen atom.KE(avg) = BE3/2 k.T = 13.6 eV1.5 × 1.38×10^-23 × T = 13.6 × 1.6×10^-19T = 2.176×10^-18 / (2.07×10^-23)T = 1.05×10^5 KTherefore, temperature is 1.05×10^5 K.Hope this helps you... |
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| 21. |
Calculate the energy required to remove an electron from He+ ion. [Ans: 54.4 eV] |
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Answer» Explanation:The atoms with the MISSING or additional electrons are called ions. He II is a helium (chemical element symbol He) atom that misses one electron. NORMAL, neutral helium atoms that still have both electrons are called He I. These ions EMIT ULTRAVIOLET (EUV) EXTREME radiation at 30.4 nm (304 Å) wavelength.The energy required to remove an electron from singly ionized helium atom will beEn = (13.6) ×2²En = 54.4Thus, the energy required to remove an electron from He+ ion is 54.4eV |
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| 22. |
Which one of the following is tme for the relative ionizing power of α, β and γ?choose the correct option from the given options. (A) It is maximum for α particle (B) It is maximum for β Particle. (C) It is maximum for γ radiation (D) It is equal for α, β and γ |
| Answer» AEXPLANATION:ALPHA particles because they are most POWERFUL and these particle was used by scientists for bombarding on gold sheet | |
| 23. |
During the life time of a radioactive element as time passes the number of its nuclei decreases and along with that ..........,choose the correct option from the given options. (A) activity and λ. go on decreasing (B) activity and λ go on increasing (C) activity decreases but λ remains constant (D) activity decreases but λ increases. |
| Answer» MAY be OPTION C can be the ANSWER to the QUESTION | |
| 24. |
The Hα-line in Balmer series of the hydrogen spectrum has a wavelength 6563 Å From this calculate the wavelength for the first line of the Lyman series (Lyα). [Ans: 1215 Å] |
| Answer» HI WELCOME to BRAINLY,..... | |
| 25. |
Estimate the value of the wavelength of Kα-line for silver (Z = 47). R = 1.09737*10⁷ m⁻¹ [Ans: 0.57 Å] |
| Answer» HAMMOCK OFFICIAL LANDLORD DISPENSARY hammock | |
| 26. |
Give two important points of Moseley’s work on X-rays |
| Answer» DISCOVERED a systematic mathematical relationship between the WAVELENGTHS of the X-rays produced and the ATOMIC NUMBERS of the metals that were USED as the targets in X-ray tubes. This has become known as Moseley's law. | |
| 27. |
Explain energy level diagram of Hydrogen spectra. |
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Answer» ctron energy level diagram for the hydrogen atom. He FOUND that the four visible spectral lines corresponded to transitions from higher energy levels down to the second energy level (n=2). This is called the Balmer SERIES. ... Bohr's MODEL was a tremendous success in EXPLAINING the spectrum of the hydrogen atom. HOPES IT HELPS YOU! |
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| 28. |
Discuss only results of α-scattering experiment due to Geiger and Marsden. |
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Answer» tion:The Geiger–Marsden experiments were a landmark SERIES of experiments by ... They deduced this by MEASURING how an alpha PARTICLE beam is SCATTERED when it ..... |
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| 29. |
Briefly discuss Thomson’s plum pudding model. |
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Answer» m pudding model is one of SEVERAL HISTORICAL scientific models of the atom. First proposed by J. J. THOMSON in 1904 soon after the discovery of the electron, but before the discovery of the atomic NUCLEUS, the model tried to explain two properties of atoms then known: that electrons are negatively-charged particles and that atoms have no net electric charge. The plum pudding model has electrons surrounded by a volume of positive charge, LIKE negatively-charged "plums" embedded in a positively-charged "pudding". |
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| 30. |
Discuss only an experimental setup of Geiger-Marsden experiment for α-scattering |
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Answer» tion:At RUTHERFORD's behest, Geiger and Marsden performed a series of experiments where they pointed a BEAM of alpha particles at a thin foil of metal and measured the scattering pattern by using a fluorescent screen. They spotted alpha particles BOUNCING off the metal foil in all DIRECTIONS, some right back at the SOURCE. |
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| 31. |
About ear drum in 1-2 lines |
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Answer» The eardrum (4) or tympanic membrane separates the external auditory canal from the middle ear which communicates with the nasopharynx via the Eustachian tube (6). The oval WINDOW (HIDDEN by the STAPES footplate: 3) and the round window (5) separate the middle and inner ears. |
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| 32. |
Who invented liquid fuel |
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Answer» Explanation:Robert H. Goddard IMAGE result for who invented liquid fuel The first flight of a liquid-propellant rocket took place on March 16, 1926 at AUBURN, Massachusetts, when American professor Dr. Robert H. Goddard LAUNCHED a vehicle USING liquid oxygen and gasoline as propellantsplz mark brainliest |
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| 33. |
If the potential energy of the electron in the hydrogen atom is -e²/4π∈₀ r then what is its Kinetic energy?choose the correct option from the given options. (A) -e²/4π∈₀ r (B) e²/8π∈₀ r (C) - e²/8π∈₀ r (D) e²/4π∈₀ r |
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Answer» A is the CORRECT ANSWER...Hope it HELPS you out PLEASE MARK as brainleist ☺️✌️ |
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| 34. |
Light of wavelength 5000Å is incident on a slit of width 2 mm in Fraunhoffer diffraction.Find the width of second maximum on the screen placed at the focal plane of the convex lens of a focal length 100 cm. The lens is placed close to the slit. [ 0.025 cm] |
| Answer» TION:haaaaaaamannajajaajahshshshshssnssssbsbbsbshsshshhshhsjssjsiswoyeiryryievsjsbnzbzjsbjdvejdudhbdhirvdydsggwjskdhsbdhejehrhehejjehehehehhshshsshhshehshshshshshhsshhshwhwshjsjsjshwjdiwoyqweruipadgklzvnmmvgejejw | |
| 35. |
The wavelength of the first line of Lyman series is λ. The wavelength of the first line in Balmer series is ...........,choose the correct option from the given options. (A) 27/5 λ (B) 5/27 λ (C) 9/2 λ (D) 2/5 λ |
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| 36. |
In Young’s experiment, the distance between two slits is 1 mm and the distance between two consecutive bright fringes is 0.03 cm. Now, on displacing the screen away from the slits by 50 cm, the distance between two consecutive dark fringes is doubled. Find the wavelength of light used. [Ans: 6000 Å] |
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Answer» gf findExplanation:find out how to make a difference between us to be a great day of SCHOOL and the answer is no LONGER be a great day of schoolbe a great day of school and the rest of my favorite things that make it through it to you and I am so happy for her and I am so EXCITED about to start my day I am so excited about it was just THINKING about how to make a great day of school and I love you all so I have been trying my best FRIEND is not a great day of school and I have a great day of school and I have a great day of school and I have a great day of school and I have a great day of school and I have a great day of school and I have a great day |
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| 37. |
Define unpolarized light and polarized light. |
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Answer» ized light : A light wave that is more than one plane is referred as unpolarized light.Unpolarized light : Light WAVES in which the VIBRATIONS OCCUR in a single plane is referred as unpolarized light. HOPE this will help you....!!!! |
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| 38. |
Define resolving power of an optical instrument.Answer the given question in brief. |
| Answer» TION:I HOPE this ANSWERS is CORRECT | |
| 39. |
Give relation between optical path length and geometrical path length.Answer the given question in brief. |
| Answer» TION:HOPE it HELPS you..PLS mark me as brainliest....... | |
| 40. |
Explain the use of wavefront to understand wave propagation. |
| Answer» TION:I HOPE this ANSWERS is RIGHT | |
| 41. |
Ordinary light incident on a glass slab, at the polarizing angle, suffers a deviation of 22°.The value of angle of refraction is..........,choose the correct option from the given options. (A) large value of magnification (A) 74° (B) 22° (C) 90° (D) 34° |
| Answer» HT ANSWER is OPTION no.A | |
| 42. |
Detailed information can be obtained by the oil immersion objective of a microscope because the objective has ...........,choose the correct option from the given options. (A) large value of magnification (B) greater value of resolution (C) large diameter (D) none of the above |
| Answer» HT ANSWER in the GIVEN OPTION is B | |
| 43. |
(2.) Where are the isotopes of the same elements having different atomic masses placed in the periodic table? |
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Answer» actually all the isotope are not mentioned in periodic tabletheir average ATOMIC mass is calculated and it is mentioned in the periodic tableplease MARK it as brainliest ANSWER please |
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| 44. |
About pinna 1-2 lines |
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Answer» pinna is a vescicle ORGAN of the HUMAN bodyit is present in the earhope it HELPED uplz mark brainliest |
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| 45. |
15. A gardener waters plants by a pipe of cross section 1 mm2. The water comes out at the rateof 100 cc/s. The reactionary force exerted on thehand of the gardener is(1) 10 N(2) 100 N(3) 1000 N(4) 500 N |
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Answer» : OPTION (1) 10N explanation : given, cross sectional area of pipe , A = 1mm² = 10^-6 m² WATER comes out at the rate 100cc/s or 100cm³/sec. so, volume of water comes out in a second , V = 100cm³ = 100 (10^-2)³ m³ = 10^-4 m³ we know, density of water , ρ = 1000 kg/m³ so, mass of water comes out in a second = ρV = 1000 × 10^-4 = 0.1 kgso, mass of water comes out in ∆t seconds , m = (0.1∆t)Kg now, find velocity of water flows , v = rate of flow of water/cross sectional area of pipe = V/A = (10^-4)/(10^-6) = 100 m/s from Newton's 2nd law, force = rate of change of momentum with RESPECT to time.or, F = ∆p/∆t = (mv)/∆t = (0.1∆t)(100)/∆t = 10 N hence, reactionary force exerted on the hand of the GARDENER is 10N. |
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| 46. |
5 % of the total energy of a 100 W bulb is converted into visible light. Calculate the average intensity at a spherical surface which is at a distance of 1 m from the bulb. Consider the bulb to be a point source and let the medium be isotropic.[Ans : 0.4 Wm⁻²] |
| Answer» HALO gamecocks SPECIAL it LANDLORD is still IDK | |
| 47. |
The magnetic field of an electromagnetic plane Wave travelling along the negative X—direction is given by By = 2*10⁻⁷sin (0.5*10³x+1.5*10¹¹t) T. Calculate (a) the wavelength and frequency of the wave. (b) Write the equation of the electric field. [Ans : λ=1.26cm, f=23.9 GHz, Ez=60 sin(0.5*10³x+1.5*10¹¹t) vm⁻¹] |
| Answer» GO iconic DHL PICK USB in DHL of FM is hmm TV TVonions Knicks | |
| 48. |
Drawing necessary figure, explain the inductive and radiated components of electromagnetic waves. |
| Answer» TION:compartmentalised CONFIRMED Spanish-American vice-presidential CONSISTING | |
| 49. |
Drawing the figure of Hertz’s experiment, explain the generation of electromagnetic waves |
| Answer» TION:handmaiden DHL picks EPIDURAL GO espresso | |
| 50. |
Which type of rays are used for LASIK eye surgery?Answer the given question in brief. |
| Answer» TION:LASIK is intended for some of the most COMMON issues that laser eye surgery can correct: myopia, hyperopia, and astigmatism. A doctor performing LASIK will CREATE the flap of the outside LAYER of the corner, to open up access to the tissue UNDERNEATH. | |