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At what temperature will the average molecular kinetic energy in gaseous hydrogen be equal to the binding energy of a hydrogen atom ? Boltzmann constant Kb = 1.38*10⁻²³ JK⁻¹ [Ans: 1.051*10⁵ K] |
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Answer» udent,◆ Answer -T = 1.05×10^5 K◆ EXPLAINATION -GIVEN that average molecular kinetic energy in GASEOUS hydrogen is EQUAL to the binding energy of a hydrogen atom.KE(avg) = BE3/2 k.T = 13.6 eV1.5 × 1.38×10^-23 × T = 13.6 × 1.6×10^-19T = 2.176×10^-18 / (2.07×10^-23)T = 1.05×10^5 KTherefore, temperature is 1.05×10^5 K.Hope this helps you... |
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