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The collector has current of the NPN transistor is equal to 10 mA. If 90% of the electron from the emitter reaches collector then ......,choose the correct option from the given options. (A) Ie ≈ 9 mA, Ib ≈ 1mA (B) Ie ≈ 11 mA, Ib ≈ 9 MA (C) Ie ≈ 11 mA, Ib ≈ 1m (D) Ie ≈ 10 mA, Ib ≈ 1m |
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Answer» c) Ie ≈ 11 mA, Ib ≈ 1m Explanation:Collector CURRENT = Ic = 10mA (GIVEN)Percentage of the electron reaching the collector = 90% (Given)Thus, Ic = 90% of IeIc = 90/100 × IeIe = Ic × 100/90Ie = 10 × 100/90Ie = 1000/90Ie = 11.11Base current = Ib = Ie-Ic= 11.11 - 10= 1.1Therefore, If 90% of the electron from the emitter reaches collector then there will be Ie ≈ 11 mA, Ib ≈ 1m |
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