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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A B B = C then magnitude of B isÀ +(A) T-- A(B) C-A(C) 2.B - A.B(D)vaC.A - B.A |
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| 2. |
If angle between two vectors is acute angle then dot product of that two vectors is(A) Positive(B) Negative(C) Zero(D) May be +ve or -ve |
| Answer» POSITIVE EXPLANATION:HOPE it HELPS U :) | |
| 3. |
What is the effective resistancebetween A and B? |
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Answer» 0.5Explanation:EFFECTIVE resistance-1/r1+1/r2+1/r3r1-4, r2-12 , R3- 6=0.5 |
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| 4. |
6000J of heat is generated when 2A current is passed through a resistor for 4 minutes . what is the resistance of the resistor? |
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Answer» 6.25 OhmsExplanation:W = 6000 JI = 2 At = 4 mins = 4 × 60 = 240 sW = VIt6000 = V × 2 × 240V = 6000 ÷ 480 = 12.5Now, W = V²t/R6000 = (12.5 × 12.5 ×240)/R∴ R = (12.5 × 12.5 × 240) / 6000⇒R = 6.25 OhmsHope it HELPS... |
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| 5. |
What are drugs . and is added in drugs |
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Answer» okExplanation:Answer your medical QUESTIONS on PRESCRIPTION DRUGS, vitamins and Over the Counter medications. Find medical information, TERMINOLOGY |
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| 6. |
A brass wire of length 1m and area of cross section 1mm^2 is stretched by applying a force of 20N, then work done per unit volume of the wire is [Ybrass = 0.91 x 1011 N/m²](A) 2198J/m3(B) 1049 J/m3(C) 4422J/m3(D) 4521 J/m3 |
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Answer» The ANSWER is a OPTION CMark me BRAINLIEST |
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| 7. |
derive an expression for magnetic induction at a point alone at the equator of a bar magnet. Give relation between Baxis and Beq |
| Answer» ASK on GOOGLE OK........ | |
| 8. |
Check the correct of an equation v = x/t where v is velocity x is displacement & t is time |
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Answer» yes its right I THINK displacement per UNIT time is CALLED VELOCITY |
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| 9. |
In the circuit, the potential differenceacross PQ will be nearestto? |
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Answer» tion:helloiss duniya me insaan to BAHUT milte hailekin insaniyat MUSHKIL se MILTI hai |
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| 10. |
If for material Young's modulus is 6.6 x 1010 N/m2 and bulk modulus is 11 x 101°N/m2 then the Poisson's ratio is(A) 0.4(B) 0.6(C) 1(D) infinity |
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Answer» oung's modulus (Y) = Bulk modulus (B) = To FIND:POISSON's Ratio (σ)Answer:RELATION between Young's modulus (Y), Bulk modulus (B) & Poisson's Ratio (σ):By substituting VALUES we GET: Poisson's Ratio (σ) = 0.4Correct Option: |
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| 11. |
With the help of a simple experiment show that different liquids expand by different amount for the same rise in temperature |
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Answer» tion:answrsearchWhat would you like to ask?11thPhysicsThermal Properties of MatterThermal ExpansionDescribe an experiment to s...PHYSICSDescribe an experiment to show that equal volumes of different liquids expand by different AMOUNTS for the same RISE in temperature.EASYShareStudy laterANSWER1. Take 3 large test tubes and fill it with water, paraffin oil and benzene.2. Mark the starting height of each liquid in the test tubes. 3. Tie test tubes together with the rubber band so the liquids are at the same level in the glass tubing.4. Pour the HOT water into the beaker around the test tubes. Watch the height of the liquids closely as the liquids warm. 5. After SOMETIME, it is found that the level of liquid is different in different tubes. Water rises the least and benzene rises the most. Thus, water expands the least and benzene expands the most.Thus, equal volumes of different liquids expand by different amounts for the same rise in temperature. |
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| 12. |
A block of mass m initially at x = 0 is pulled along x-axis by applying the force F = b - cx, where b andcare positive constant.→Fmx=0X |
| Answer» TAKE lExplanation:L LLLLLLLL LLLLL . LL . LLLL L | |
| 13. |
Two blocks are released from rest on the incline plane where Tane > 1 & Tane > P2. P1 & 2 arecoefficient of friction between incline plane andblock A & B respectively. Choose the correctstatement(s) :- |
| Answer» NFL ISRO I'd to OX to IV duo in us CJbf cl nuts and the other SIDE of the year old GIRL that I have a great day of the year old boy and the same thing as well I'm sorry but I thinks it's not just got back and forth and the rest of your | |
| 14. |
If a and b are two vectors such that axb = 3, thenfind the value of [a bāxb]. |
| Answer» GIVE the QUESTION PROPERLY | |
| 15. |
a rod of youngs modulus of 20 gpa undergoes a linear strain of6× 10 to the power -4 then increase in energy density is what |
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Answer» fsfevefbgbg by by by by BEG G yExplanation:mthtjmjmthmhtnthnuntthyjm |
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| 16. |
Two blocks are released from rest on the incline plane where Tano > H1 & Tano > H2 H1 & 2 are coefficient of friction between inclineplane and block A & B respectively. Choose the CORRECT statement(s) :-BАmm,Normal reaction between blocks is zero for H1 = 12Normal reaction between blocks is zero for H2> H1Normal reaction between blocks is non zero for 2 < N1Both move with same acceleration for H2 > 1 |
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Answer» Two BLOCKS are released from rest on the incline plane where Tano > H1 & Tano > H2 H1 & 2 are coefficient offriction between inclineplane and block A & B respectively. Choose the Normal reaction between blocks is ZERO for H1 = 12Normal reaction between blocks is zero for H2> H1Normal reaction between blocks is NON zero for 2 < N1Both move with same acceleration for H2 > 1 |
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| 17. |
Acceleration of a particle varies with time as a = 12t2 m/s2. If the particle starts its motion from rest, then its displacement in initial 2 seconds will be |
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Answer» Given that,HEIGHT = 40 mTime t =2 secWe know that,v=u+gtv=0+9.8×2v=19.6m/sThe speed of STONE is 19.6 m/sNow, the speed with which the stone STRIKES the groundv2=u2+2gsv2=0+2×9.8×40v2=784v=28m/sHence, the speed with which the stone strikes the GROUND is 28 m/sFollow me and make me brainlist and thanks for my answer okk |
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| 18. |
Find the unit of vector in the direction of vector ^i +4 ^j - 2k |
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Answer» Explanation:UNIT vector in the DIRECTION of a given vector =that given vector ÷ its MAGNITUDE |
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| 19. |
600j of heat is generated when 2A current pass through a resistor of 4 amp. what is Reactance of resistor? |
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Answer» aking the text look coloured refer the below syntax and ignore the dots [.tex]\red{the\:text\:APPEARS\:in\:red}[./tex]result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text MARQUEE[.tex][./tex]result = < marquee > {the\:text\:appears\:like\:this} < /marquee > 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex]result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the EXPONENTIAL value [.tex]{no.}^{power}[./tex]result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx FOLLOW me next |
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| 20. |
(ग (4)mok27. xy तल में गतिशील एक कण पर बल F- -k(yi + ४)(जहाँ k नियतांक है) कार्यरत है। मूल बिन्दु से गति करतेहुए कण को y-अक्ष के अनुदिश बिंदु (0. a) तक लाया जाताहै। कण पर बल F आरोपित करने वाले वाहक द्वारा कियागया कार्य है(1) k(x2 +y)(2) शून्य(3) ky(4) kx |
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| 21. |
In order to calculate pressure exerted on a surface what quantity is divided by the surface |
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Answer» forceExplanation:As we KNOW that pressure is defined as FORCE Exerted normal to a GIVEN surface per unit AreaSo here it is given asPressure = \frac{Force}{Area}Pressure= AreaForce P = \frac{F}{A}P= AF so here we can say that pressure gives force in the normal DIRECTION or perpendicular direction per unit areaIts SI unit is given as Newton per square meterthanks PLEASE follow me please |
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| 22. |
A charge is taken from a point A to a point B. The work done per unit charge in the process is called Options1. the potential at A2. the potential at B3. the potential difference between B and infinity4. the potential difference between A and B |
| Answer» OPTION 4= The POTENTIAL DIFFERENCE between A and B | |
| 24. |
If a,b and ē are three vectors. If any two vectors areparallel then abc)=[] |
| Answer» OKAY I will INBOX UR ANSWER | |
| 25. |
Ling ..The dimensions of magnetic induction field are(a)MLºT-A-1(b) MºLT-A-1(c) MLT-2A-1(d) MLºT-2A-1 |
| Answer» TION:Force F acting on CHARGE Q moving with velocity v in magnetic FIELD B is given as F=qvB thus B= QVF ∴[B]= [qv][F] = C×LT −1 MLT −2 =[MT −1 C −1 ]follow mee | |
| 26. |
What type of equilibrium is guaranteed by each condition of equilibrium? |
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Answer» Under what conditions will an object be in equilibrium? Conditions of Equilibrium An object is in equilibrium in a reference coordinate SYSTEM when all external forces (including MOMENTS) ACTING on it are balanced. This means that the NET result of all the external forces and moments acting on this object is zero. Explanation: |
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| 27. |
River is flowing with a velocity vBR=2iˆm/s. A boat is moving with a velocity of vBR=(−4iˆ+4jˆ)m/s relative to river. The width of the river is 100m along y-direction. Choose the correct alternative(s) |
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| 28. |
Three resistances 5 ohm,5ohm and 6 ohm are connected as shown in figure. If thepoint S divides the resistance 6 ohm intotwo equal halves, the resistancebetween points P and S is? |
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Answer» ivalent circuit diagram of the GIVEN network is as shown in the figure ↑The RESISTANCE of upper ARM between P and S := 5Ω + 3Ω = 8The resistance of lower arm between P and S := 5Ω + 3Ω = 8The EQUIVALENT resistance between P and S := 4Ω |
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| 29. |
Which among the following relations can be deduced from dimensional analysis? (Symbols have their usual meaning) t = 2π*√l/gs = ut +atBoth (1) and (2)Neither (1) nor (2) |
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| 30. |
5. Write any two situations of gravitational force observed in day to day life. |
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Answer» amples of the force of gravity include: The force that holds the gases in the SUN. The force that causes a ball you throw in the AIR to come down again. The force that causes a CAR to coast downhill even when you aren't STEPPING on the gas. |
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| 31. |
State the conditions for theVariable velocity |
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Answer» Variable velocity velocity in which the space described varies from instant to instant, EITHER increasing or decreasing; -- in the FORMER case CALLED accelerated velocity, in the latter, retarded velocity; the acceleration or RETARDATION itself being also either uniform or variable. |
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| 32. |
The equivalent resistance between A and B isZero if v, V,1892 if V, V,Zero if v,>V, and 5482 if V, |
| Answer» HOPE its usefulhope its USEFUL hope its useful hope its useful hope its useful hope its useful EXPLANATION:MARK ME AS A BRAINLIST | |
| 33. |
How are ligaments different from tendons |
| Answer» MAY also attach muscles to structures such as the EYEBALL. A tendon serves to MOVE the bone or STRUCTURE. A ligament is a fibrous CONNECTIVE tissue which attaches bone to bone, and usually serves to hold structures together and keep them stable. | |
| 34. |
21. Create a unit vector pointing in positive y-axis. Now add to this another unit vector that makes 30° from first vector towards right side on the page. Calculate the resultant vector. |
| Answer» EXPLANATION:no IDEA , MATE TRY it yourself | |
| 35. |
If 62.24 cm is divided by 2.0 s, the result upto appropriate significant figures is 31.12 cm/s31.1 cm/s31.2 cm/s3.1 x 10 cm/s |
| Answer» RULE: In MULTIPLICATION or division, the final result should retain as MANY SIGNIFICANT figures as are there in the original number with the least significant figures.2.54 contain the least significant figures of 32.5497.52 =38.393=38.4 | |
| 37. |
What is least count error? How can least count error be reduced? |
| Answer» HI dear can you write the questions in easy WAY | |
| 38. |
The distance between 2nd crest and 6th trough of a wave produced by a rowing boat is 24 cm. If the wave velocity of the moving crests is 20 m/s, then find the frequency of rocking of boat a 24 Hzb 20Hzc 375 Hzd 240 Hz |
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Answer» Hello!The answer is 375 HzExplanation:The distance between two consecutive crests or troughs is known as wavelength(λ)Hence the distance between the 2 nd crest and the 6 TH crest will be 4λThe distance between any crest and its successive trough is 2λ Hence the distance between the 2 nd crest and the 6 th trough will be 4.5λThe frequency of rocking of the boat is same as the frequency(f) of the waveWe KNOW that velocity (V)=fλ∴f= λv ∵4.5λ=0.24, λ= 4.50.24 ∴f= ( 4.50.24 )20 = 0.2420×4.5 = 6×490×100 =15×25=375HzHope it Helps you !! |
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| 39. |
9. A car accelerates at 3m/s2 along a straight horizontal road. The mass of the car is 1000 kg. A forward force acts on the car in the right direction of magnitude 3500 N. Find the magnitude of the resistance force acting in the left direction |
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Answer» 500NExplanation:force is GIVEN byF=maF=1000×3=3000Ntotal force in forward 3500N but only 3000N is ABLE to accelarate car so remaining 3500-3000=500N is resisting the MOTION. |
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| 41. |
The speed of a weighting car is 3000N Increases fron 36 km\h to 72 km\h uniformly . The change in momentum of the car is 3x10^x kg-m\s. Then x is |
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Answer» x=3Explanation:36km\h =10m/s73km/h =20m/sweight of CAR is 3000N soweight=mass×accelaration DUE to gravityw=mgm=w/g (g=10m/s^-2) =3000/10=300kgmomentum is GIVEN by p=mvso when v=10 then p1=300×10=3000kgm/sp2=300×20=6000kgm/schange in momentum p2-p1=6000-3000=3000kgm/s=3×10^3kgm/sso COMPARING with 3×10^x KG m/sx=3 |
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| 42. |
A gas cylinder is filled with gas occupies 150cc at 200C and 800mm of Hg pressure. What will be its volume at 270C and 300mm of Hg pressure? |
| Answer» VOLUME of the gas = 0.43 LExplanation:Volume of the gas (V₁) = 150 ccTemperature of the gas (T₂) = 200° CPressure (P₁) = 800 mm of HgTemperature (T₂) = 270° CPressure (P₂) = 300 mm of HgVolume of the gas (V₂)➠ First we have to covert all the given datas to the respective S.I units.➠ Pressure: 800 mm of HG = 1 ATM 300 mm of Hg = 0.4 atm➠ Temperature: 200° C = 473.15 K 270° C = 543.15 K➠ Volume: 150 cc = 0.15 L➠ Now by the Ideal gas equation we know that, ➠ Substitute the data, ➠ Simplifying, 3.17 × 10⁻⁴ = 7.36 × 10⁻⁴ × V₂ V₂ = 3.17/7.36 V₂ = 0.43 L➠ Hence the gas occupies a volume of 0.43 L. | |
| 43. |
A 20 kg block is pushed up along an incline that makes an angle of 30 to the horizontal. The block starts moving with an initial speed of 4 m/s at the bottom of the incline, and stops after moving 8 m up the incline. Find the magnitude of the net force acting on the block during its entire motion. (Take the upward direction as positive direction) |
| Answer» BALANCING forces along the inclined PLANE, Fcosθ=mgsinθ+ff=80N;θ=30 o is frictional force.So, Fcos30 o =200sin30 o +80⇒F=205.55NExplanation:MARK me as BRAINLIST | |
| 44. |
A3 kg block (A) is placed on 6 kg block (B) which rest on the table. Coefficient of the friction between (A) and(B) is 0.3 and between (B) and table is 0.6. A 30 N horizontal force is applied on the block (B), then calculatethe friction force between the block (A) and (B). |
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Answer» tion:A3 kg block (A) is placed on 6 kg block (B) which rest on the table. COEFFICIENT of the frictionbetween (A) and(B) is 0.3 and between (B) and table is 0.6. A 30 N HORIZONTAL force is applied on the block (B), then calculatethe FRICTION force between the block (A) and (B). |
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| 45. |
A car accelerates at 3m/s2 along a straight horizontal road. The mass of the car is 1000 kg. A forward force acts on the car in the right direction of magnitude 3500 N. Find the magnitude of the resistance force acting in the left direction |
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Answer» 3m/sec²a= 3m/sec²mass= 1000 kga= 3m/sec²mass= 1000 kgforce in right direction= 3500 NTO FINDMagnitude of force in left direction= ?SolutionForce = (1000 X 3) NForce = 3000 N3000 N force is ACTING from left direction.Net force acting = f2 - f1Net force acting = 3500-3000 = 500 N_____________________________________ |
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| 46. |
kal thik din ke 12 baje me chalijaungi usi time mene start kia tha or usi time katham kardungi okk phir milenge |
| Answer» U are SAYING? I not UNDERSTOOD. | |
| 47. |
2 A cricket ball of mass 0-2 kg moving with a velocity of20 m s-l is brought to rest in 0-4s. Find the averageforce. |
| Answer» GIVEN, m= 0.2 KG. V = 20 m/s, t = 0.1sF=ma= ΔtmΔv ∴f=0.2× 0.120 =40N | |
| 48. |
Please help me answer this question |
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Answer» hiExplanation:12•=¥{×{`{`=|=|{=$™`✓`{× |
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| 49. |
a block of mass m initially at x=0 is pulled along x axis by applying the force F=cb-x, where b and c are positive constant. what is the maximum speed of block during motion and what is the maximum value of x? |
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| 50. |
A current of 10 Ampere is flowing across a resistor of 4 ohm. what is the potential difference across the ends of the resistor ? |
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Answer» A current of 5 AMPERES is flowing through a resistor of 15 ohms. How would one calculate the potential difference between the ends of the resistor?Which is the fastest scientific calculator for ENGINEERING?Explanation:please MARK me as BRAINLEAST and follow also |
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