1.

The distance between 2nd crest and 6th trough of a wave produced by a rowing boat is 24 cm. If the wave velocity of the moving crests is 20 m/s, then find the frequency of rocking of boat a 24 Hzb 20Hzc 375 Hzd 240 Hz​

Answer»

Hello!The answer is 375 HzExplanation:The distance between two consecutive crests or troughs is known as wavelength(λ)Hence the distance between the 2 nd crest and the 6 TH crest will be 4λThe distance between any crest and its successive trough is 2λ Hence the distance between the 2 nd crest and the 6 th trough will be 4.5λThe frequency of rocking of the boat is same as the frequency(f) of the waveWe KNOW that velocity (V)=fλ∴f= λv ∵4.5λ=0.24, λ= 4.50.24 ∴f= ( 4.50.24 )20 = 0.2420×4.5 = 6×490×100 =15×25=375HzHope it Helps you !!



Discussion

No Comment Found

Related InterviewSolutions