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A 20 kg block is pushed up along an incline that makes an angle of 30 to the horizontal. The block starts moving with an initial speed of 4 m/s at the bottom of the incline, and stops after moving 8 m up the incline. Find the magnitude of the net force acting on the block during its entire motion. (Take the upward direction as positive direction)​

Answer» BALANCING forces along the inclined PLANE, Fcosθ=mgsinθ+ff=80N;θ=30 o is frictional force.So, Fcos30 o =200sin30 o +80⇒F=205.55NExplanation:MARK me as BRAINLIST


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