1.

Acceleration of a particle varies with time as a = 12t2 m/s2. If the particle starts its motion from rest, then its displacement in initial 2 seconds will be

Answer»

Given that,HEIGHT = 40 mTime t =2 secWe know that,v=u+gtv=0+9.8×2v=19.6m/sThe speed of STONE is 19.6 m/sNow, the speed with which the stone STRIKES the groundv2=u2+2gsv2=0+2×9.8×40v2=784v=28m/sHence, the speed with which the stone strikes the GROUND is 28 m/sFollow me and make me brainlist and thanks for my answer okk



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