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from FIGURETHE component of weight along incline is MG sinα = mg sin30 = 4(10) (1/2) = 2*10 =20N Explanation:

n:A composition of an organic compound is found to CONTAIN 39.9 % of CARBON, 6.7% of hydrogen and remaining being oxygen. The molar mass of the compound is 180. Determine its empirical FORMULA and molecular formula.Answer: Empirical formula of the compound = CH₂O Molecular formula = C₆H₁₂O₆Explanation:Mass of carbon = 39.9 gMass of hydrogen = 6.7 gMass of oxygen = (100 - (39.9 + 6.7) ) = 53.4 gEmpirical formulaMolecular formula➟ First we have to find the number of moles of each element present in the compund.➟ The number of moles of a given compound is given by,     Number of moles = Given mass/Molar mass➟ Number of moles of carbon = 39.9/12     Number of moles of carbon = 3.325 moles➟ Number of moles of hydrogen = 6.7/1     Number of moles of hydrogen = 6.7 moles➟ Number of moles of oxygen = 53.4/16     Number of moles of oxygen = 3.34 moles➟ Now we have to find the simplest whole number ratio of all the ELEMENTS.     Simplest whole number ratio of carbon = 3.325/3.325 = 1     Simplest whole number ratio of hydrogen = 6.7/3.325 = 2     Simplest whole number ratio of oxygen = 3.34/3.325 = 1➟ Hence,     Empirical formula of the compound = CH₂O➟ Now we have to find the molecular mass of the compund.     Molecular mass = 12 + 2 + 16 = 30➟ Now we know that,     Molar mass/Molecular mass = n     n = 180/30     n = 6➟ We know that,     Molecular formula = n × Empirical formula     Molecular formula = 6 × CH₂O     Molecular formula = C₆H₁₂O₆

Explanation:Initial velocity = 100 m/sFinal velocity = 50 m/sDistance travelled = 50 mRetardation➜ Here we have to find the deceleration of the vehicle.➜ By NEWTON's third equation of motion we know that,     v² - u² = 2as     where V = final velocity                U = initial velocity                a = acceleration                s = DISTANCE travelled➜ Substitute the data,      50² - 100² = 2 × a × 50      100 a = 2500 - 10000      100 a = -7500      a = -7500/100     a = -75➜ Hence the retardation of the vehicle is -75 m/s²➜ Here acceleration is NEGATIVE since it is retardation or deceleration.➜ Hence option B is correct.     ➜ The three equations of motion are:v = u + ats = ut + 1/2 × a × t²v² - u² = 2as

A ray of light or another form of radiant energy that is THROWN BACK from a nonpermeable or nonabsorbing surface is called reflected ray. The ray of light that BOUNCES back from the surface of reflection is called the reflected ray. All the rays the INCIDENT, normal and reflected lie on the same plane.

plan U = FORCE my GUESS as c 14N

answrsearchWhat would you like to ask?12thPhysicsMoving Charges and MagnetismLorentz ForceTwo protons move parallel t...PHYSICSTwo protons move parallel to each other, keeping distance r between them, both moving with same velocity v . Then the ratio of the electric and magnetic force of interaction between them is:(c - Velocity of light) HARDShareStudy laterANSWERThere are two forces electric force and magnetic force experienced by proton.The electric force between the two protons is given as F E = 4πε 0 1 r 2 q 2 Now, the magnetic force isF B =qvBB is the magnetic field.From Biot- savarts LAWB= 4πμ 0 r 2 IdL dL is the length ELEMENT of the conductor but, the expression will be for charge where is no current.So,we KNOW that,I= TQ IdL=q dtdL IdL=qvNow, the magnetic field is B= 4πμ 0 r 2 qv The magnetic force isF B =qvBF B =qv 4πμ 0 r 2 qv F B = 4πμ 0 r 2 q 2 v 2 Now, the ratio of the electric force and the magnetic force isF B F E = 4πμ 0 × r 2 q 2 v 2 4πε 0 1 × r 2 q 2 F B F E = μ 0 ε 0 v 2 1 ......(I)We know that, the speed of lightc= μ 0 ε 0 1 c 2 = μ 0 ε 0 1 Now, PUT the value of μ 0 ε 0 1 in equation (I)F B F E = v 2 c 2 Hence, the ratio of electric force and magnetic force will be F B F E = v 2 c 2 .

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a. F fric =μ s W=0.4∗20=8Nb. SINCE F APPLIED F staticfric motion started.F>F kineticfric HENCE motion continues.F fric =4NExplanation:please follow me and like me mark in BRAINLIST please please please please please

The UNIT of WORK is JOULE.

the RIGHT ANSWER as 6 is GREATER than 5

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The ANSWER is a OPTION A

Force on CHARGE particle depends upon the velocity of charge particle, angle between Magnetic FIELD and velocity, and strength of Magnetic field.If angle between charge is zero the force would be zero.If velocity of both charges MAKES a DIFFERENT angle with magnetic filed then magnitude of force would be different but when that angle is same then force will be same.Hence Option D

option A it means IMAGE INVERTED and enlarged which we GET in the position between F and C for a concave mirror

The PLANETS all revolve AROUND the sun in the same direction and in virtually the same plane. In addition, they all rotate in the same general direction, with the exceptions of Venus and Uranus. These differences are believed to STEM from COLLISIONS that occurred LATE in the planets' formation.Explanation:

The ANSWER is a OPTION A

tion:ANSWER30m North20m Eastand the 30 2 SW can be REWRITTEN as 30m in south and 30m in West because south and west being at 90 0 resultin 30 2 +30 2 =30 2 so at last we have FOLLOWING data that in south X S =30m+north=30m+(−30m)=0, negative becasue north is opposite to south.and in West we have X W =30m+east=30m+(−20m)=10mso the displacement is 10m due westplease follow me FRIEND and make me as brainliest

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The ANSWER is a OPTION A

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F=m(g+a) ;for accelarating upwardsF=m(g-a) ;for accelarating DOWNWARDS

the RATE of CHANGE of VELOCITY is CALLED momentumExplanation:P= m(v-u)

A micrometer has 150 EQUAL divisions on the circular SCALE, and on one full rotation ofcircular scale main scale advances by 0.02 cm on the main scale. The least count of THEMICROMETER (in cm) ISO 4 x 10-5O 6.21 x 10-3O 1.33 x 10-4O 1.21 x 10-2

t FREQUENCY is the oscillation of a system at its NATURAL or unforced RESONANCE. Resonance occurs when a system is able to store and EASILY transfer energy between different storage modes, such as KINETIC energy or Potential energy as you would find with a simple pendulum.

(2)EXPLANATION:MARK ME BRAINLIEST__,_____

Using conservation of energy in vertical motion of pendulum when it reaches horizontal position, 21 MV h 2 +mgL= 21 mv B 2 Velocity at the bottom is GIVEN by,v b = 5gL v h = 3gL ------ (1)Tension at the horizontal position is =T= Lmv h 2 ----- (2) =3mg ; (Substituting v h from eqn 1 in eqn2)∴ Net force on the bob is = (3mg) 2 +(MG) 2 = 10 mg

(C)EXPLANATION:MARK me BRAINLIEST

After time t, distance covered by first stone is s= 21 gt 2 After time (t-1), distance travelled by second stone is s=u(t−1)+ 21 g(t−1) 2 =20t−20+ 21 g(t−1) 2 These distance must be EQUAL at the time of OVERTAKING,Thus, 21 gt 2 =20t−20+ 21 g(t−1) 2 or, 0=20t−20+ 21 g(1−2t)which gives, 20t−20+5−10t=0 (putting g=10)or t=1.5Put this t in equation for distance to get s= 21 gt 2 = 21 10(1.5) 2 =11.25mhope it helps you

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shall complex of 4 or LESS Aaron's if we use more it will KILL nucleus so OPTION AEXPLANATION:mark me as BRAINLEST

The ANSWER is a OPTION A

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